What will happen to the brightness of the lamp when the 
the slider is moved towards x
what will happen to the brightness of the lamp when - 1

Answers

Answer 1
Answer:
The rheostat is used to kind of  'spread out' the battery voltage,
you might say.  It's like the whole battery voltage is spread out
along the length of the rheostat, and you can connect to any point
you want, from the negative side of the battery (Y) to the positive
side (X), and every point in between, and you get whatever the
voltage is at that particular point.

One side of the light bulb (and the voltmeter) is connected to the
negative side of the battery, and you can't change that.

But the other side of the bulb (and the voltmeter) is connected to
the slider, which can be slid anywhere between 'x' and 'y'.

When the slider is down at 'y', that's the negative side of the battery.
So both sides of the lamp are connected to the same place, there's
no voltage across the lamp, and it just sits there, cool and dark.

When the slider is all the way up at the 'x' end, that's the positive
side of the battery.  So the full battery voltage is connected across
the lamp, and the lamp sparkles bright and hot.

When the slider is someplace in between, then only a part of the
full battery voltage is across the lamp (and the voltmeter).
The higher the slider is ... the closer it is to 'x' ... the more voltage
there is across the lamp.  The brighter the lamp shines, and the
higher the voltmeter reads.


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Answers

I would look this one up on google

Answer:

10

____________________________

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Recall Elmer Trett, who in 1994 reached a speed of 103m/s on his motorcycle. Suppose trett drives off a horizontal ramp at this velocity and lands a horizontal distance of 40.0m away from the edge of the ramp. What is the height of ramp?

Answers

Speed of the motor cycle is given as

v_x = 103 m/s

distance that he moved off from the ramp is given as

x = 40 m

now we know that

x = v_x * t

40 = 103* t

t = 0.39 s

now we can use this to find the height

h = v_i*t + (1)/(2)gt^2

h = 0 + (1)/(2)*9.8*0.39^2

h = 0.74 m

so its height will be 75 cm from ground

Final answer:

The height of the ramp is approximately 0.748m.

Explanation:

To find the height of the ramp, we can use the equations of motion. Since the motorcycle leaves the ramp horizontally, the horizontal distance traveled is equal to the initial horizontal velocity multiplied by the time of flight.

Using the equation x = vt, where x is the horizontal distance traveled, v is the initial horizontal velocity, and t is the time of flight, we can solve for t.

For this problem, the horizontal distance is 40.0m and the initial horizontal velocity is 103m/s. Substituting these values into the equation, we get t = x/v = 40.0m / 103m/s = 0.388s.

Next, to find the height of the ramp, we can use the equation h = (1/2)gt^2, where h is the height of the ramp and g is the acceleration due to gravity (approximately 9.8m/s^2). Substituting the value of t we found into the equation, we get h = (1/2)(9.8m/s^2)(0.388s)^2 = 0.748m.

Learn more about height of ramp here:

brainly.com/question/14519217

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Which plate is covering most of two continents ? what two continents?

Answers

The plate that is covering most of the two continents is the Eurasian plate.
The continents are
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The Eurasian plate covers most of the continents of Europe and Asia.