CHEMISTRY HIGH SCHOOL

Which substance in the table below has the strongest intermolecular forces

Answers

Answer 1
Answer:

Answer : Option A) HF.

Explanation : Assuming the complete question as per the attachment.

H-F bonds are formed because of hydrogen bonding between H atom and F atom and is considered to be strongest amongst the rest other options given.

As given in the table it is clear that the molar mass of HF molecule is the lowest. It shows that, when dispersion increases in the molecule molecular weight also increases.

Answer 2
Answer: The strongest intermolecular bonding is hydrogen bonding. The hydrogen bonding is the electrostatic bonding between hydrogen atom and any of the electronegative atoms, such as Oxygen, Nitrogen and Flourine. The strength of H-F bonding is strongest, then H-N and then H-O bond.

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A copper penny has a mass of 6.2 grams and a volume of 0.70ml. What is the density of the penny

Answers

Given:
A copper penny has a mass of 6.2 grams and a volume of 0.70ml

Required:
density of the penny

Solution:
D = M/V where D is teh density, M is the mass and V is the volume

D = 6.2 grams/0.70 mL
D = 8.9 grams per milliliters

A solution containing large amount of solute in comparison to solvent is... A ) aqueous,b. concentrated,
c. Diluted, and
d. soluble

Answers

A solution containing large amount of solute in comparison to solvent is concentrated. Meaning the solute's concentration is high. The answer to this question is letter "B" or "B. Concentrated". I hope this helps you on your assignment. 

the answer will be b)

The oxidation # (charge) of an element called "lindenium "Ld is + 1 and the oxidation # (charge) of an element called "mendezine symbol "Mz, is -2. What is the chemical formula for the compound called lindenium mendezide?

Answers

Answer:

Ld₂Mz

General Formulas and Concepts:

Chemistry - Compounds

  • Valence shells
  • Writing chemical compounds
  • Balancing charges

Explanation:

Step 1: Define

"Lindenium" Ld w/ oxidation charge of +1

"Mendezine" Mz w/ oxidation charge of -2

Step 2: Write Compound

To balance out the charges to be neutral (0), we must counter balance the amount of Ld's with Mz's. We need 2 Ld's with 1 Mz to create a compound with a neutral charge:

2Ld¹⁺ + Mz²⁻

2(+1) + (-2) = (+2) + (-2) = 0 (neutral charge)

Therefore, our compound must be Ld₂Mz.

You fill a rigid steel cylinder that has a volume of 20.0 L with nitrogen gas to a final pressure of 2.00 *10^4 Kpa at 28c How many kilograms of N2 does the cylinder contain

Answers

The quantity of nitrogen the cylinder contains is 4477.8 g

What is pressure?

Pressure is a force exerted in a perpendicular direction in any item.

By ideal gas law

PV = nRT

P =(w)/(M) =(RT)/(V)\n

w = mass

Volume is 20.0 l

Pressure is  2.00 * 10^4 \;Kpa

The molar mass of nitrogen is 28 g/mol

R is gas constant = 0.0821

Temperature is 28 converted into kelvin that is 301 k

Putting the values

197.6 =(w)/(28) =(0.0821 * 301 )/(20\;l)\n\nw = 4477.8 g

Thus, the mass of nitrogen is 4477.8 g.

Learn more about pressure, here:

brainly.com/question/356585

Answer : The mass of N_2 gas is, 4477.8 g

Solution :

using ideal gas equation,

PV=nRT\n\nP=(w)/(M)* (RT)/(V)

where,

n = number of moles of gas

w = mass of gas

P = pressure of the gas = 2* 10^4Kpa=197.6atm

conversion :1atm=101.2Kpa

T = temperature of the gas = 28^oC=273+28=301K

M = molar mass of N_2 gas = 28 g/mole

R = gas constant = 0.0821 Latm/moleK

V = volume of gas = 20 L

Now put all the given values in the above equation, we get the mass of gas.

197.6atm=(w)/(28g/mole)* (0.0821Latm/moleK* 301K)/(20L)

w=4477.8g

Therefore, the mass of N_2 gas is, 4477.8 g

How many moles of oxygen are produced when 26.5 mol of aluminum oxide are decomposed?

Answers

The balanced chemical reaction is:

 

2Al2O3 = 4Al +3 O2

 

We are given the amount of the reactant. This will be the starting point of our calculations.

 

26.5 mol Al2O3 ( 3 mol O2 / 2 mol Al2O3 ) = 39.75 mol O2 needed

 

Thus, 0.014 mol of I2 is needed to form the given amount of NI3.

the balanced chemical equation for the decomposition of Al₂O₃ is as follows

2Al₂O₃ --> 4Al + 3O₂

stoichiometry of Al₂O₃ to O₂ is 2:3

when 2 mol of Al₂O₃ decomposes - 3 mol of O₂ are formed

therefore when 26.5 mol of Al₂O₃ decomposes - 3/2 x 26.5 mol = 39.75 mol

the number of moles of O₂ formed are 39.75 mol

Mixture of sediments deposited by a glacier

Answers

Answer:

Till

Explanation:

Till is unsorted glacial sediment showing no stratfaction.

Answer: Glacier Deposition

Explanation:
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