36 Which compound has the highest percent composition by mass of strontium?(1) SrC12 (2) SrI2 (3) SrO (4) SrS
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(mass of strontium) / (mass of compound) * 100% = (percent mass of Strontium)
1. The mass of strontium is 87.62 and the mass of Chlorine is 35.45. There are 2 chlorine atoms in the compound, so 35.45*2 = 70.9. Add the strontium to get the mass of compound. 70.9 + 87.62 = 158.52. Now, we can use the equation.
87.62 / 158.52 * 100% = 55.27% Strontium
2. There are 2 Iodine atoms in the compound, and the molar mass of Iodine is 126.9. The mass of the compound is 126.9 + 87.62 = 214.52. Now, we can use the equation
87.62 / 214.52 * 100% = 40.84% Strontium
3. The molar mass of Oxygen is 16, and there is only one oxygen atom. So the mass of the compound will be 16 + 87.62 = 103.62. Now we can use the equation.
87.62 / 103.62 * 100% = 85.46% Strontium
4. Finally, the molar mass of sulfur is 32.06, and there is only one sulfur atom in the compound, so the mass will be 32.06 + 87.62 = 119.68. Now we can use the equation
87.62 / 119.68 * 100% = 73.21% Strontium
Therefore, the answer is 3 because it has the highest percentage of Strontium than the other compounds. Hope this helped!! :D
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Answer:
Complexity.
Explanation:
Okay, I am NOT explaining this whole thing, but simply, C2n product.
Don't ask. Just don't.
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Answer:
The answer is c. 173 g
Explanation:
You know the reaction :
KClO3 ⇒ 2 KCl + 3 O2
By stoichiometry, that is, the amount of reagents and products in a chemical reaction when it is balanced (as in this case), it is known that for 2 moles of O2, 1 mole of KCLO3 is needed. So you can do the following rule of three to know the number of moles to produce 4.26 moles of 02:
If 1 mole of KClO3 is necessary to produce 3 moles of O2, how many moles are needed to produce 4.26 moles of 02?
So you need 1.42 moles of KClO3
Now it is necessary to know the molar mass of KClO3, which is the mass that contains 1 mole of the substance. For that you need to know the mass of K, Cl and O:
- K: 39 g/mol
- Cl: 35.45 g/mol
- O: 16 g/mol
So, the molar mass of KClO3 is:
39 g/mol + 35.45 g/mol + 3*16 g/mol=122.45 g/mol
because it contains 1 atom of K, 1 atom of Cl and 3 atoms of O.
Now, to calculate the mass representing 1.42 moles of KClO3 (needed to produce 4.26 moles of O2) you simply multiply that amount of moles by the molar mass:
This means that approximately 174 g of KClO3 are necessary to produce 4.26 moles of O2.
2KClO3 -> 2KCl + 3O2 (Always check if equation is balanced - in this case it is)
4.26moles
So we know that we have 4.26 moles of oxygen (O2). Now lets look at the ratio between KClO3 and O2.
We see that the ratio is 2:3 meaning that we need 2KClO3 in order to produce 3O2.
Therefore divide 4.26 by 3 and then multiply by 2.
4.26/3 = 1.42
1.42 * 2 = 2.84
Now we know that the molarity of KClO3 is 2.84 moles.
Multiply by R.M.M to find how many grams of KClO3 we have.
R.M.M of KClO3
K- 39
Cl- 35.5
3O- 3 * 16 -> 48
---------------------------
122.5
2.84 * 122.5 = 347.9 grams therefore the answer is (a)
348 grams needed of KClO3 to produce 4.26 moles of O2.
Hope this helps :).
b. nucleotide.
c. peptide.
d. monomer.
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Answers
Answer:
λ = 0.0167 m = 16.7 mm
Explanation:
The wavelength of these radio waves can be found out by using the formula for the speed of radio waves:
v = fλ
where,
v = speed of radio waves = speed of light = 3 x 10⁸ m/s
f = frequency of radio waves = 18 GHz = 18 x 10⁹ Hz
λ = Wavelength = ?
Therefore,
3 x 10⁸ m/s = (18 x 10⁹ Hz)λ
λ = (3 x 10⁸ m/s)/(18 x 10⁹ Hz)
λ = 0.0167 m = 16.7 mm
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Answers
Answer: The correct answer is neutrons.
Explanation:
There are 3 subatomic particles that are present in an atom. They are: protons, electrons and neutrons.
Protons carry positive charge and are found inside the nucleus of an atom.
Electrons carry negative charge and are found around the nucleus in the orbits.
Neutrons does not carry any charge and are found inside the nucleus of an atom.
Hence, the correct answer is neutrons.