What solution of the inequality -1<4+5x<9

Answers

Answer 1

Answer: $-1\ \textless \ 4+5x\ \textless \ 9 \n \n -1 - 4 \ \textless \ 5x \ \textless \ 9 - 4 \ / \ subtract \ 4 \ from \ equation \n \n -5 \ \textless \ 5x \ \textless \ 5 \ / \ simplify \n \n - (5)/(5) \ \textless \ x \ \textless \ 1 \ / \ divide \ equation \ by \ 5 \n \n -1 \ \textless \ x \ \textless \ 1 \ / \ simplify \n \n$

Answer: -1 < x < 1

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x is a point in the interior of rectangle PTRS. If XP=a, XT=c and XR=b, determine XS. a<b<c. Answer should be in terms of a, b and c

Answers

so you cannot really get the exact measure because they didn't give you any measures, but we can infer that if c>b and a then
maybe SX (d) is more than b and a so

a<b<c or d not sure which
sorry if I didn't help

A physical fitness association is including the mile run in its secondary- school fitness test. The time for this event for boys in secondary school is known to possess a normal distribution with a mean of 440 seconds and a standard deviation of 50 seconds. Find the probability that a randomly selected boy in secondary school can run the mile in less than 325 seconds.

Answers

Answer:

0.0107 is the probability that a randomly selected boy in secondary school can run the mile in less than 325 seconds.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 440 seconds

Standard Deviation, σ = 50 seconds

We are given that the distribution of time is a bell shaped distribution that is a normal distribution.

Formula:

$z_(score) = \displaystyle(x-\mu)/(\sigma)$

P(run the mile in less than 325 seconds)

P(x < 325)

$P( x < 325) = P( z < \displaystyle(325 - 440)/(50)) = P(z < -2.3)$

Calculation the value from standard normal z table, we have,

$P(x < 325) = 0.0107 = 1.07\%$

0.0107 is the probability that a randomly selected boy in secondary school can run the mile in less than 325 seconds.

What is the square root of 300 rounded to the nearest tenth?

Answers

$17 < √(300) < 18\ becouse\ 17^2=289 < 300 < 324=18^2$

$17.3^2= 299.29 < 300\n\n17.4^2=302.76 > 300$

$17.3 < √(300) < 17.4$

$√(300)\ \text{is closer to 17.3. Therefore}\ √(300)\approx17.3$

Fill in the blank for each part below.1) The slope is...
A. zero
B. Undefined

2) The equation is...
A. y=-1
B. X=-1