Compare the mean and standard deviation of Set A and Set B.Set A: 7, 3, 4, 9, 2
Set B: 5, 8, 7, 6, 4

Answers

Answer 1

Answer: Set A: {7, 3, 4, 9, 2}
Finding the Mean of Set A: $\bar{x} = (7 + 3 + 4 + 9 + 2)/(5)$
   $\bar{x} = (25)/(5)$
   $\bar{x} = 5$

Finding the Standard of Set A: $\sigma = \sqrt{\frac{(\bar{x} - x_(1))^(2) + (\bar{x} - x_(2))^(2) + (\bar{x} - x_(3))^(2) + (\bar{x} - x_(4))^(2) + (\bar{x} - x_(5))^(2)}{n}}$
   $\sigma = \sqrt{((5 - 7)^(2) + (5 - 3)^(2) + (5 - 4)^(2) + (5 - 9)^(2) + (5 - 2)^(2))/(5)}$
   $\sigma = \sqrt{((-2)^(2) + (2)^(2) + (1)^(2) + (-4)^(2) + (3)^(2))/(5)}$
   $\sigma = \sqrt{(4 + 4 + 1 + 16 + 9)/(5)}$
   $\sigma = \sqrt{(34)/(5)}$
   $\sigma = √(6.8)$
   $\sigma \approx 2.6$

Finding the Mean of Set B: $\bar{x} = (5 + 8 + 7 + 6 + 4)/(5)$
   $\bar{x} = (30)/(5)$
   $\bar{x} = 6$

Finding the Standard Deviation of Set B: $\sigma = \sqrt{\frac{(\bar{x} - x_(1))^(2) + (bar{x} - x_(2))^(2) + (\bar{x} - x_(3))^(2) + (\bar{x} - x_(4))^(2) + (\bar{x} - x_(5))}{n}}$
$\sigma = \sqrt{((6 - 5)^(2) + (6 - 8)^(2) + (6 - 7)^(2) + (6 - 6)^(2) + (6 - 4)^(2))/(5)}$
$\sigma = \sqrt{((1)^(2) + (-2)^(2) + (-1)^(2) + (0)^(2) + (2)^(2))/(5)}$
$\sigma = \sqrt{(1 + 4 + 1 + 0 + 4)/(5)}$
$\sigma = \sqrt{(10)/(2)}$
$\sigma = √(5)$
$\sigma \approx 2.236$

The mean and standard deviation of Sets A and B are different.

Answer 2

Answer:

Final answer:

Mean of Set A is 5 and Set B is 6. Standard deviation of Set A is approximately 2.83, and for Set B, it's approximately 1.67. This indicates that values in Set B are generally closer to their mean than values in Set A to their mean.

Explanation:

To compare the mean and standard deviation of Set A and Set B, we first need to calculate these for each set. Mean is the average of the numbers and standard deviation is a measure of the amount of variation or dispersion of a set of values.

First, calculate the mean by adding the numbers in each set and dividing by the total number of values. For Set A, the mean is (7+3+4+9+2)/5 = 5. For Set B, the mean is (5+8+7+6+4)/5 = 6.

The standard deviation is a bit more complex, as it involves subtracting the mean from each value, squaring the result, finding the mean of these squares, and then taking the square root of that mean. For Set A, these steps result in a standard deviation of approximately 2.83. For Set B, these steps result in a standard deviation of approximately 1.67.

In conclusion, Set B has a higher mean and a lower standard deviation compared to Set A which means values in Set B are generally closer to the mean of Set B than values in Set A are to the mean of Set A.

Learn more about Mean and Standard Deviation here:

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Answers

Answer:

ad=DC is your answer.....

Ad=dc - hope this helps!!!!!

2/3 of the pizza was left over from last night. Then, Marcy ate another 2/9 of it. Which of the following statements is true?A.Very little of the pizza is left.
B.About half of the pizza is left.
C.Most of the pizza is left.

Answers

About half of the Pizza is left

Explanation
By subtracting what Marcy ate, i.e 2/9 of 2/3, we get 14/27 to be the remaining pizza. This is about half

Write an equation in slope-intercept form of the line shown in the graph below.A. y = -2x + 1
B. y = -4x + 2
C. y = 4x + 2
D. y = 2x - 2

Answers

your answer is B. y=-4x+2

A rectangular stage set up in a theater has an area of (15x^2+3x-12) square feet. Factor the polynomial completely.

Answers

15x²+3x-12
=3(5x²+x-4)
=3(x²+x-20)
=3(x+5)(x-4)
=3(5x+5)(5x-4)
=3(x+1)(5x-4)

Your team dives for 28 lobsters over 7 days which integer represents the average daily lobster catch

Answers

Answer:

4 lobsters a day

Step-by-step explanation:

28 / 7 = 4

Write the equation for each transformation of f(x)= |x| described below.a. translate left 9 units, stretch vertically by a factor of 5, and translate down 23 units.

b. translate left 12 units, stretch horizontally by a factor of 4, and reflect over the x-axis.

need steps don't understand how to do!

Answers

okay, original equation of an absolute value function is:
a. f(x) = a |x-h| + k
a is the stretch or shrink
h is horizontal movement (watch the negative!!)
k is vertical shift

Translate left 9 units means horizontal shift so the h changes. When you move to the left, the numbers become negative so y = a|x-(-9)| + k which becomes
y = a|x+9| + k Then the vertical stretch of 5 becomes y = 5|x+9| + k And then a translation down 23 units means a negative shift down (which is your vertical shift) so:
f(x) = 5(x+9) - 23

b. translate left 12 units meaning a negative horizontal shift. y = a|x-(-12)| + k
so then it becomes y = a|x+12| + k
a stretch horizontally by 4 is your a, so y = 4|x+12| (you can just forget about the k since there is no vertical shift so your k = 0)
a reflection over the x-axis means that your horizontal axis is taken and folded and the reflection from the graph is your new graph. So basically, the whole equation becomes negative.
y = -4|x+12|

Final answer:

For a, the transformed function is 5*|x+9| - 23 after translating 9 units to the left, stretching vertically by a factor of 5, and translating down 23 units. For b, the transformed function is -|(x+12)/4|, after translating 12 units to the left, stretching horizontally by a factor of 4, and reflecting over the x-axis.

Explanation:

The given function is f(x) = |x|. To write the equation for each transformation, you need to understand how they influence the function.

a. To translate the function left 9 units, the value 9 needs to be added inside the absolute value brackets creating f(x) = |x+9|. To stretch it vertically by a factor of 5, we multiply the entire function by 5 - 5 * f(x) = 5*|x+9|. Lastly, to translate down 23 units, we subtract 23 from the entire function, leading us to 5*|x+9| - 23.

b. To translate left 12 units, we change the function to |x+12|. To stretch horizontally by a factor of 4, divide the x inside the absolute value by 4, getting |(x+12)/4|. To reflect over the x-axis, we multiply the entire function by -1, leading to -|(x+12)/4|.