__________ is one of many factors that can determine the rate of alcohol absorption.

Answers

Answer 1
Answer: Food consumption affects the rate of alcohol absorption in the bloodstream.

Explanation:

The type of food and therefore the amount of food that is a gift in your epithelial duct once you consume alcohol have the foremost direct impact on the speed of alcohol absorption.

When you consume alcohol on the associate empty abdomen, the alcohol is sometimes absorbed within the blood among fifteen minutes to two-and-a-half hours. If you have got a moderate quantity of food in your abdomen once you drink, that speed slows all the way down to thirty minutes to a few hours. If you’re drinking on a full abdomen, alcohol absorption ranges from 3 to 6 hours.
Answer 2
Answer:

Answer: The answer is C. Food.


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In Act IV, Scene 1, of A Midsummer Night's Dream, as the drama nears resolution, to whom does Demetrius address these lines?My love to Hermia,
Melted as the snow, seems to me now
As the remembrance of an idle gaud

Answers

Answer:

The lines were addressed to Theseus, the Duke of Athens.

Explanation:

William Shakespeare's "Midsummer Night's Dream" is a comedy that portrays the events surrounding the marriage of Theseus, the Duke of Athens and Hyppolita.

Hermia and Lysander were in love, much to the dismay of her father Egeus. Demetrius had been previously in love with Helena, Hermia's best friend. But now he's trying to marry Hermia, with the full support of Egeus. In Act IV, scene 1, the four characters Lysander, Hermia, Demetrius and Helena were all found in deep sleep. Hermia and Lysander had planned to elope and run away but was caught up by Helena who, through the magic potion, had fallen in love with Lysander. On the other hand, Demetrius had, by the same magic potion put on him by Queen Hyppolita, had fallen in love with Helena. When Egeus and Theseus arrived, they woke them up. It was then that they started explaining their situation to the Duke and Egeus.

Demetrius spoke the lines "My love to Hermia,

Melted as the snow, seems to me now

As the remembrance of an idle gaud"

to Duke Thesues describing his love for Hermia.

In Act IV, Scene 1, of A Midsummer Night's Dream, as the drama nears resolution, to whom does Demetrius address these line to Hermia

Which of the following is an example of a covalent compound? ​

Answers

Answer:

CCI2

Explanation:

HELP ME PLEASE 40 POINTS You may select a topic from the list below, or choose your own.black hole
oort cloud
star types (supergiant, red dwarf, white dwarf)
supernovae
planetary nebulae
Andromeda galaxy
quasar
Use the library and other resource materials to research and understand your topic. Remember that nasa.gov is a web site that has reliable information as well that you may use for your research. Now write a 300-word report on what you have learned in the essay box below.

Answers

Answer:

Do black hole

Explanation:

Which of the following bonds is the most polar in nature:(1) Cl2
(2) HCl
(3) HBr
(4) HI

Answers

The answer will be (4) HI because the greater the difference of the bonds in electronegativity, the more polar a bond is.

Final answer:

HCl is the most polar bond, as greater the difference in electronegativity, the more polar the bond. Here, Chlorine is more electronegative than Hydrogen, Bromine, and Iodine, making the HCl bond most polar.

Explanation:

The most polar bond in the list provided is HCl. Polarity in bonds is determined by the difference in electronegativity between the two atoms in the bond. The greater the electronegativity difference, the more polar the bond. Chlorine (Cl) is more electronegative than Hydrogen (H), Bromine (Br), and Iodine (I), and so the bond between Cl and H is the most polar. The other three options (Cl2, HBr, HI) are either bonds between atoms of the same element (and therefore nonpolar because the electrons are shared equally) or are less polar due to the lower electronegativity difference.

Learn more about Polarity of Bonds here:

brainly.com/question/32841252

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Which reaction occurs most rapidly at standard conditions?H2(g) + I2(s) 2HI(g)
Cu(s) + S(s) CuS(s)
C6H12O6(s) + 6O2(g) 6CO2(g) + 6H2O(g)
5C2O42-(aq) + 2MnO4-(aq) + 16H+(aq) 10CO2(g) + 2Mn2+(aq) + 2H2O(l)
Ag+(aq) + I-(aq) AgI2(s)
NextReset

Answers

Answer : Option A) H_(2)_((g)) + I_(2)_((s)) ----> 2HI_((g)).

Explanation : The reaction of hydrogen gas with iodine in solid phase will react most rapidly at standard conditions.

A rapid chemical reaction is one where reactants react fast with each other to give the products at the standard temperature and pressure conditions.

In the given choices Iodine is highly reactive as it belongs to the halogen group and also atomic hydrogen is very reactive in nature, when both combine it gives hydrogen iodide which is much stable in nature than the reactants.

when one mole of hydrogen reacts with one mole of iodine it produces 2 moles of hydrogen iodide.

H_(2)_((g)) + I_(2)_((s)) ----> 2HI_((g)).

The reaction occurs most rapidly at standard conditions are:
H2(g) + I2(s) 2HI(g)

The reaction that do not occur rapidly at standard conditions are 
Cu(s) + S(s) CuS(s)
C6H12O6(s) + 6O2(g) 6CO2(g) + 6H2O(g)
5C2O42-(aq) + 2MnO4-(aq) + 16H+(aq) 10CO2(g) + 2Mn2+(aq) + 2H2O(l)
Ag+(aq) + I-(aq) AgI2(s)

Only a small fraction of a weak acid ionizes in aqueous solution. What is the percent ionization of a 0.100-M solution of acetic acid, CH3CO2H? CH3CO2H(aq)+H2O(l)⇌H3O+(aq)+CH3CO2−(aq )Ka=1.8×10−5

Answers

Answer:

1.33%

Explanation:

In an aqueous solution, a weak acid such as acetic acid, will be in equilibrium with its conjugate base, acetate ion, thus:

CH₃CO₂H(aq) + H₂O(l) ⇌ H₃O⁺(aq) + CH₃CO₂⁻(aq )

Where dissociation constant, ka, is defined as the ratio of concentrations of products and reactants:

Ka = 1.8x10⁻⁵ = [H₃O⁺] [CH₃CO₂⁻] / [CH₃CO₂H]

H₂O is not taken into account in the equilibrium because is a pure liquid

When a solution of acetic acid becomes to equilibrium, the original concentration of the acid decreases producing more H₃O⁺ and CH₃CO₂⁻.

The concentrations at equilibrium when a 0.100M solution of acetic acid reaches this state, is:

[CH₃CO₂H] = 0.100M - X

[H₃O⁺] = X

[CH₃CO₂⁻] = X

Where X is reaction coordinate.

Replacing in Ka expression:

1.8x10⁻⁵ = [H₃O⁺] [CH₃CO₂⁻] / [CH₃CO₂H]

1.8x10⁻⁵ = [X] [X] / [0.100M - X]

1.8x10⁻⁶ - 1.8x10⁻⁵X = X²

1.8x10⁻⁶ - 1.8x10⁻⁵X - X² = 0

Solving for X:

X = -0.00135 → False solution. There is no negative concentrations.

X = 0.00133 → Right solution.

That means concentration of acetate ion is:

[CH₃CO₂⁻] = 0.00133M.

Now, percent ionization is defined as 100 times the ratio between weak acid that is ionizated, [CH₃CO₂⁻] = 0.00133M, per initial concentration of the acid, [CH₃CO₂H] = 0.100M. Replacing:

% Ionization = 0.00133M / 0.100M × 100 =

1.33%