The earth exerts a force of 500 newtons on an object what is the mass of the object in kg

Answers

Answer 1

Answer:
Weight (that's what the 500 N is) = (mass) x (gravity) .

On Earth, gravity = about 9.8 m/s² , so

   500 N = (mass) x (9.8 m/s²) .

Divide each side by 9.8 m/s²:

   Mass = (500 N) / (9.8 m/s²)

=    51 kg (rounded) .

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What happens to the force between the objects if Mass 2 decreases? (increases, decreasesaffected)

Answers

The more separation two objects have, the more the force between them decreases. When mass 1 increases the force between the objects increases. If Mass 2 decreases, the force between the objects decreases.

A 3,000-N force gives an object an acceleration of 15 m/s2. The mass of the object is

Answers

Answer:

force= mass x acceleration

3000 N = m x 15

m= 3000/15

m=200 kg

If 600 J of work is done in 3 s, what is the power? (Power: P = W/t)

Answers

P = W/t
= 600 / 3
Power = 200 Watt

Answer: 200 W

Explanation:

In physics, power is defined as the amount of work done divided by the time taken to do that work:

$P=(W)/(t)$

where W is the work done and t is the time.

In this problem, the work done is W=600 J, while the time taken is t=3 s. Substituting into the formula, we find the power:

$P=(600 J)/(3 s)=200 W$

An ultrasound unit is being used to measure a patient's heartbeat by combining the emitted 2.0 MHz signal with the sound waves reflected from the moving tissue of one point on the heart. The beat frequency between the two signals has a maximum value of 560 Hz . What is the maximum speed of the heart tissue? The speed of ultrasound waves in human tissue is 1540 m/s.Express your answer to two significant figures and include the appropriate units.

Answers

Hi there,
for this question we have:
Signal 2.0 MHz = Emitted so we can call it $f_e$
and we need the Reflected = $f_(r)$
In this question, we have a source which goes to the heart and a reflected which comes back from the heart and we need the speed of the reflected.
So you should know that the speed of reflected is lower than the source(Emitted).
we also know: ΔBeat frequency(max) = 560 Hz = $f_(b)$
so we have:
$f_(e)$ - $f_(r)$ = $f_(b)$
so frequency of Reflected is:
2.0 × 10^6 Hz - 560 Hz = 1.99 × 10^6 Hz = $f_(r)$
now you know that Lambda = v/f
so if we find the lambda with our Emitted then we can find v with the Reflected:
Lambda = 1540(m/s) / 2.0 × 10^6 Hz = 7.7 × 10^-4 m
=> $v_(max)$ = (lambda)( $f_(r)$
=> 7.7 × 10^-4m (1.99 × 10^6Hz) = 1532 m/s
so the $v_(max)$ is equal to 1532 m/s :)))
This question is solved by two top teachers as fast as they could :))
I hope this is helpful
have a nice day

A bear is sitting at rest on a tricycle. The bear then starts to accelerate uniformly at a rate of 2.5 m/s2 (meters per second square). How long will it take the bear to reach a velocity of 15 m/s (meters per second)