CHEMISTRY HIGH SCHOOL

A solution is considered basic or alkaline if its pH is _________ 7.A. equal to
B. less than
C. greater than

Answers

Answer 1
Answer: C greater than because anthing basic is 8 or up

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Determine the pH of a 5x10^-4 M solution of Ca(OH)2

Answers

Ca(OH)₂ ==> Ca²⁺ + 2 OH-   

Ca(OH)₂ is strong Bases

Therefore,  the [OH-] equals 5 x 10⁻⁴ M. For every Ca(OH)₂ you produce 2 OH⁻.

pOH = - log[ OH⁻]

pOH = - log [ 5 x 10⁻⁴ ]

pOH = 3.30

pH + pOH = 14

pH + 3.30 = 14

pH = 14 - 3.30

pH = 10.7

hope this helps!

Which of the following devices can measure only atmospheric pressure?        A. Pressure gauge   B. Barometer   C. Tire gauge   D. Mercury tube

Answers

B.) Barometer

Hope that helps :-)

What are the thin fibers of the human nervous system that send messages between different parts of the body?A.
nerves





B.
brain





C.
spinal cord





D.
eye

Answers

Answer:

The correct answer is option A, that is, nerves.

Explanation:

The nerves are also known as neurons that make up the nervous system. The nerves are considered as the unique cells, which conduct messages from one section of the body to another, as minute electrical signals. These messages are also called nerve impulses. There are three distinct kinds of neurons known, and each one exhibit a somewhat different function. These are relay neurons, sensory neurons, and motor neurons.
A. Nerves, it's literally the only one that makes sense

A gas initial volume and pressure is 5m^3 and 101320 Pa and allows to expand up to 12m^3 then what is the final pressure?

Answers

Answer:

New pressure = 42216.66 Pa

Explanation:

Given that,

Initial volume, V₁ = 5 m³

Final pressure, P₁ = 101320 Pa

Final volume, V₂ = 12 m³

We need to find the final pressure of the gas. We know that the relation between pressure and volume is given by :

P\propto (1)/(V)\n\nP_1V_1=P_2V_2\n\nP_2=(P_1V_1)/(V_2)\n\nP_2=(101320 * 5)/(12)\n\nP_2=42216.67\ Pa

So, the new pressure is equal to 42216.66 Pa.

The two classifications of all chemicals are organic and salts.
a. True
b. False

Answers

Chemicals are never classified all depends upon it's physical and chemical properties so the answer is FALSE

Answer:

False I took the test

Explanation:

Sulfur and fluorine react in a combination reaction to produce sulfur hexafluoride: S(g) + 3F2(g) ->SF6(g) If 50 g S is allowed to react as completely as possible with 105.0g F2(g), what mass of the excess reactant is left.

Answers

Answer: The mass of excess reagent left is 20.48 g

Explanation:

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

  • For sulfur:

Given mass of sulfur = 50 g

Molar mass of sulfur = 32 g/mol

Putting values in equation 1, we get:

\text{Moles of sulfur}=(50g)/(32g/mol)=1.56mol

  • For fluorine gas:

Given mass of fluorine gas = 105 g

Molar mass of fluorine gas = 37.99 g/mol

Putting values in equation 1, we get:

\text{Moles of fluorine gas}=(105g)/(37.99g/mol)=2.76mol

The chemical equation for the reaction of sulfur and fluorine gas follows:

S(g)+3F_2(g)\rightarrow SF_6(g)

By Stoichiometry of the reaction:

3 moles of fluorine gas reacts with 1 mole of sulfur

So, 2.76 moles of fluorine gas will react with = (1)/(3)* 2.76=0.92mol of sulfur

As, given amount of sulfur is more than the required amount. So, it is considered as an excess reagent.

Thus, fluorine gas is considered as a limiting reagent because it limits the formation of product.

Moles of excess reagent (sulfur) left = 1.56 - 0.92 = 0.64 moles

  • Now, calculating the mass of sulfur from equation 1, we get:

Molar mass of sulfur = 32 g/mol

Moles of sulfur = 0.64 moles

Putting values in equation 1, we get:

0.64mol=\frac{\text{Mass of sulfur}}{32g/mol}\n\n\text{Mass of sulfur}=20.48g

Hence, the mass of excess reagent left is 20.48 g
The mole number of 50 g S is 1.563 mol. 105.0 g F2 is 2.763 mol. The ratio of S and F2 is 1:3. So the excess one is S. And mass left is 0.642*32=20.52 g.
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