Write the equation of the given circle. Center (1,-5) Radius of 10

Answers

Answer 1
Answer:

The equation of the circle with the given center and radius is x²-2x+y²+10y-74=0.

What is a circle equation?

The equation of circle provides an algebraic way to describe a circle, given the center and the length of the radius of a circle. The equation of a circle is different from the formulas that are used to calculate the area or the circumference of a circle.

The standard equation of a circle with center at (x₁, y₁) and radius r is (x-x₁)²+(y-y₁)²=r²

Given that, the center of a circle is (1, -5) and the radius is 10 units.

Now, equation of a circle is

(x-1)²+(y+5)²=10²

x²+1-2x+y²+25+10y=100

x²-2x+y²+10y+26=100

x²-2x+y²+10y-74=0

Therefore, the equation of the circle with the given center and radius is x²-2x+y²+10y-74=0.

To learn more about an equation of a circle visit:

brainly.com/question/23799314.

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Answer 2
Answer: (x-1)^2 + (y+5)^2 =100

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Hi I need help with the one that is circle thank you

Does funko pop do custom orders?

Answers

yes they do on their website!!

Answer:

yeah i think so

In a city known for many tech start-ups, 311 of 800 randomly selected college graduates with outstanding student loans currently owe more than $50,000. In another city known for biotech firms, 334 of 800 randomly selected college graduates with outstanding student loans currently owe more than $50,000. Perform a two-proportion hypothesis test to determine whether there is a difference in the proportions of college graduates with outstanding student loans who currently owe more than $50,000 in these two cities. Use α=0.05. Assume that the samples are random and independent. Let the first city correspond to sample 1 and the second city correspond to sample 2. For this test: H0:p1=p2; Ha:p1≠p2, which is a two-tailed test. The test results are: z≈−1.17 , p-value is approximately 0.242

Answers

Answer:

Null hypothesis:p_(1) - p_(2)=0  

Alternative hypothesis:p_(1) - p_(2) \neq 0  

z=\frac{0.389-0.418}{\sqrt{0.403(1-0.403)((1)/(800)+(1)/(800))}}=-1.182    

p_v =2*P(Z<-1.182)=0.2372  

Comparing the p value with the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say that we don't have significant difference between the two proportions.  

Step-by-step explanation:

1) Data given and notation  

X_(1)=311 represent the number college graduates with outstanding student loans currently owe more than $50,000 (tech start-ups)

X_(2)=334 represent the number college graduates with outstanding student loans currently owe more than $50,000 ( biotech firms)

n_(1)=800 sample 1

n_(2)=800 sample 2

p_(1)=(311)/(800)=0.389 represent the proportion of college graduates with outstanding student loans currently owe more than $50,000 (tech start-ups)

p_(2)=(334)/(800)=0.418 represent the proportion of college graduates with outstanding student loans currently owe more than $50,000 ( biotech firms)

z would represent the statistic (variable of interest)  

p_v represent the value for the test (variable of interest)  

\alpha=0.05 significance level given

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to check if is there is a difference in the two proportions, the system of hypothesis would be:  

Null hypothesis:p_(1) - p_(2)=0  

Alternative hypothesis:p_(1) - p_(2) \neq 0  

We need to apply a z test to compare proportions, and the statistic is given by:  

z=\frac{p_(1)-p_(2)}{\sqrt{\hat p (1-\hat p)((1)/(n_(1))+(1)/(n_(2)))}}   (1)  

Where \hat p=(X_(1)+X_(2))/(n_(1)+n_(2))=(311+334)/(800+800)=0.403  

3) Calculate the statistic  

Replacing in formula (1) the values obtained we got this:  

z=\frac{0.389-0.418}{\sqrt{0.403(1-0.403)((1)/(800)+(1)/(800))}}=-1.182    

4) Statistical decision

Since is a two sided test the p value would be:  

p_v =2*P(Z<-1.182)=0.2372  

Comparing the p value with the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say that we don't have significant difference between the two proportions.  

Cho S là ngoại diên của khái niệm con người, p(x,y) = x yêu thương y. 1) Viết các phán đoán sau đây dưới dạng công thức:
a) Nhiều người yêu thương A. (Thay A bằng chính tên của em).
b) A yêu thương nhiều người. (Thay A bằng chính tên của em).
2) Phủ định hai phán đoán ở phần 1) (viết dưới dạng câu văn hoàn chỉnh).

Answers

The question involves using logical quantifiers to express the statements "Many people love A" and "A loves many people" and their negations. The formulas are ∃x (p(x, A)) and ∃y (p(A, y)) for the original statements, and the negations are ¬∃x (p(x, A)) and ¬∃y (p(A, y)).

The question involves expressing statements about relationships using logical quantifiers and then finding their negations. Given S as the domain of humans and p(x, y) representing the statement "x loves y", we can write the formulas for the following statements:

a) Many people love A: ∃x (p(x, A))

b) A loves many people: ∃y (p(A, y))

The negation of these statements can be written as:

a) It is not the case that many people love A: ¬∃x (p(x, A)), which means no one loves A or everyone does not love A.

b) A does not love many people: ¬∃y (p(A, y)), implying A loves no one or A does not love everyone.

Answer:

Step-by-step explanation:

Please help its vocab matching

Answers

Answer:

1. S

2. G

3. I

4. O

5. P

6. D

7. C

8. F

9. J

10. Q

11. E

12. K

13. R

14. A

15. B

16. N

17. M

18. L

19. H

Step-by-step explanation:

4. O

→ 3 is a coefficient of 3x

5. P

→ 3 is a common factor in the expression 3x+9

6. D

→example of a constant term is 1,3,10

7. C

cosx=(adjacent)/(hypotenuse) =(A)/(H)

8. F

x^(2) -4 will be factorised as (x-2)(x+2)

9. J

→ example of an expression is 2x+9

10. Q

→ factors of 3 are 3×1.

11. E

→ example of factoring is (x+2)(3x+4)

12. K

→ example of a factored completely is 2x(x+y)

14. A

→example of a polynomial is 3yx^(3) +xy^(2) -2x+9.

15. B

→ example of a quadratic expression is x^(2) +6x-9.

17. M

sinx=(opposite)/(hypotenuse) =(O)/(H)

18. L

tanx=(opposite)/(adjacent) =(O)/(A)

19. H

→ example of a term is 2x,3,40

There are 80 participants in a competition. The average score of each participant is 58.5. The average score of the male participants is 64 and the average score of the female participants is 56. How many male participants are there in the competition?

Answers

Answer:

  • 25

Step-by-step explanation:

Given

  • Total number of participants= 80
  • Male = x
  • Female = 80 - x
  • Average = 58.5
  • Average for male = 64
  • Average for female = 56

Equation to reflect the sum:

  • 64x + 56(80 - x) = 80*58.5
  • 64x - 56x = 80*(68.5 - 56)
  • 8x = 80*2.5
  • x = 25

The answer is 25 male participants

While shopping, Cori spent three times as much as Ann. If they spent a total of $124, how much did each person spend?

Answers

Ann-x
Cori-3x

3x+x=124

4x=124
divide both sides by 4

x=31 now plug it in and you get

Ann-31
Cori-31×3=93

Ann spent 31$
Cori spent 93$