PHYSICS HIGH SCHOOL

The charge on an electron is:
positive
negative
neutral
unknown

Answers

Answer 1
Answer: negative

Firstly it is best to describe the shape and structure of an atom, an atom's system and structure is like of the solar planet, the heliocentric view where the sun is the neutrons and protons and the planets are the electrons. Moreover, the electrons are outside these neutrons and protons surrounding the entire system of its atomic structure. Its movement is like of a planet. 

An energy level also known as electron shell, or just shell is a location around an atom where electrons with a specific  energy value,  or quantum number may be found.

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Two objects with different masses collide and bounce back after an elastic collision. Before the collision, thetwo objects were moving at velocities equal in magnitude but opposite in direction. After the collision,
A. the less massive object had gained momentum.
B. the more massive object had gained momentum.
C. both objects had the same momentum.
D. both objects lost momentum.

Answers

The more massive object will lose momentum after collision while the less massive object will gain momentum after collision.

  • Let the mass of the first object = m₁
  • Let the mass of the second object = m₂
  • let the initial velocities of the two objects = u
  • let the final velocity of the first object after collision = v₁
  • Let the final velocity of the second object after collision = v₂

Apply theprinciple of conservation of linear momentum for elastic collision;

let the heavier object = m₁

m₁u + m₂(-u) = m₁(-v₁) + m₂v₂

m₁u  - m₂u = -m₁v₁ + m₂v₂

where;

m₁u and m₂u  are initial momentum of both objects before collision

m₁v₁ and  m₂v₂ are final momentum of both objects after collision

Thus, from the equation above we can conclude the following, the more massive object will lose momentum after collision while the less massive object will gain momentum after collision.

Learn more here:brainly.com/question/11214803

Answer:A

Explanation:

Given

mass of two objects are  m_1 and m_2

taking m_1>m_2

Suppose u_1  and  u_2 are the velocities of m_1 and

u_1=u and  u_2=-u

therefore after elastic collision velocity of m_1 and m_2/[tex] are [tex]v_1 and v_2

v_1=(m_1-m_2)/(m_1+m_2)\cdot u_1+(2m_2)/(m_1+m_2)\cdot u_2

v_2=(2m_1)/(m_1+m_2)\cdot u_1-(m_1-m_2)/(m_1+m_2)\cdot u_2

for u_1 and u_2

v_1=(m-m)/(m+m)\cdot u+(2m)/(m+m)\cdot (-u)

v_1=(m_1+m_2)/(m_1+m_2)\cdot u=u

v_2=(2m)/(m+m)\cdot u-(m-m)/(m+m)\cdot (-u)

v_2=(3m_1-m_2)/(m_1+m_2)\cdot u

v_2=u+2\cdot (m_1-m_2)/(m_1+m_2)\cdot u

so velocity of mass m_2 is more as compared to m_1

so less massive object gained some momentum

what is the acceleration of a rocket that speeds up uniformly from rest and travels 650 m in the first 12 seconds?

Answers

the acceleration of the rocket is approximately \(9.03\, \text{m/s}^2\) when it speeds up uniformly from rest and travels 650 meters in the first 12 seconds.

a boy runs from his house to school at speed 5m/s on a straight road and returns with speed of 10m/s.The distance between the house and school is 100m. Find his average velocity.... with explaination please​

Answers

Explanation:

time spent to run from house to school=100/5=20s

time spent to return from school=100/10=10s

average velocity=200m/(10+20)

  • =6.66m/s

"A car accelerates at a rate of 3.0 m/s2. If its original speed is 8.0 m/s, how many seconds will it take the car to reach a final speed of 23.0 m/s?"

Answers

Answer:

\boxed{Time = t = 5 seconds}

Explanation:

Acceleration = (V_(f)-V_(i))/(t)

Where

Acceleration = 3 m/s²

V_(f) = 23 m/s

V_(i) = 8 m/s

So,

3 = (23-8)/(t)

t = (15)/(3)

Time = t = 5 seconds

Answer:

.81 m second i think

Explanation:

A ball with a mass of 1.5 kilograms is tied to the end of a rope. The ball is pulled to a height of 0.5 meters above the ground and released.The ball has joules of potential energy at position B. At position A, all of the energy changes to kinetic energy. The velocity of the ball at position A is meters/second. Assume there’s no air resistance. Use g = 9.8 m/s2 , PE = m × g × h, and

Answers

Solve the potential energy at point B

PE = mgh

Where m is the mass

G is the acceleration due to gravity 9.8 m/s2

H is the height

PE = ( 1.5 kg) ( 9.8 m/s2) (0.5 m)

PE = 7.35 J

 

Solve the velocity using the

KE = 0.5mv^2

Where ke is the kinetic energy

M is the mass

V is the velocity

Since all energy is converted to KE

So KE = PE

 

7.35 = 0.53(1.5) v^2

V = 3.13 m/s

The velocity of the ball at position A is equal to 3.13 m/s.

Given the following data:

  • Mass of ball = 1.5 kilograms.
  • Height = 0.5 meters.
  • Acceleration due to gravity = 9.8 m/s^2

How to calculate potential energy.

Mathematically, potential energy is given by this formula:

P.E = mgh\n\n

Where:

  • m is the mass.
  • h is the height.
  • g is acceleration due to gravity.

Substituting the given parameters into the formula, we have;

P.E = 1.5 * 9.8 * 0.5

P.E = 7.35 Joules.

Assuming there’s no air resistance, the potential energy would be equal to kinetic energy.

P.E = K.E\n\n7.35 = (1)/(2) mv^2\n\nmv^2 = 7.35 * 2\n\n1.5v^2 = 14.7\n\nv=\sqrt{(14.7)/(1.5) } \n\nv=√(9.8)

V = 3.13 m/s.

Read more on potential energy here: brainly.com/question/1242059

400J of heat is produced in 4 sec in 4ohm resistor.calculate yhe PD across the resistor.

Answers

Actually, after the information you gave, I expected you to ask for the voltage
across the resistor, so I'm not quite sure what you mean by 'PD'.  It could be the
"Potential Difference" or the "Power Dissipation" across the resistor.
Here are both answers:

Power Dissipation:
Power = Energy/time =  400 joules / 4 seconds = 100 joules/second = 100 watts.

Potential Difference (voltage):
Power dissipated by a resistor = (voltage)² / Resistance

100 watts = (voltage)² / 4 ohms

Multiply each side by 4 ohms:

400 watts-ohms = (voltage)²

Voltage = square root of 400 watts-ohms = 20 volts
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