The table shows the number, expressed in millions, of citizens who moved in 2004, categorized by where they moved and whether they were an owner or a renter. find the probability, expressed as a decimal rounded to the nearest number of people in a certain country who moved in 2004, in millions moved to same region moved to different region moved to different country owner 11.6 11.6 2.7 2.7 0.4 0.4 renter 18.7 18.7 4.5 4.5 1.0 1.0 hundredth, that a randomly selected citizen who moved in 2004 was a person who moved to a different region to a different region.

Answers

Answer 1

Answer: The table is attached.
You need to find the probability, expressed as a decimal rounded to the nearest hundredth, that a randomly selected citizen who moved in 2004 was a person who moved to a different region.

What you need to calculate is the empirical probability: the number of success over the total number of outcomes.

People who moved to a different region = 2.7 + 4.5 = 7.2 millions
People who moved in 2004 = 11.6 + 2.7 + 0.4 + 18.7 + 4.5 + 1.0 = 38.9 millions

P = People who moved to a different region / People who moved in 2004
= 7.2 millions / 38.9 millions = 0.18508997

Therefore, the probability that a randomly selected citizen who moved in 2004 was a person who moved to a different region is P = 0.19

Answer 2

Answer:

Step-by-step explanation:

0.19

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According to a random sample taken at 12 A.M., body temperatures of healthy adults have a bell-shaped distribution with a mean of 98.28degreesF and a standard deviation of 0.63degreesF. Using Chebyshev's theorem, what do we know about the percentage of healthy adults with body temperatures that are within 2 standard deviations of the mean? What are the minimum and maximum possible body temperatures that are within 2 standard deviations of the mean? At least nothing% of healthy adults have body temperatures within 2 standard deviations of 98.28degreesF.
Whart is 1 divided by 1/2

Enter the symbol (<, >, or =) that correctly completes this comparison.
0.147 0 0.174

Answers

Answer:

Step-by-step explanation:

.174 is greater than .147

It is believed that the average amount of money spent per U.S. household per week on food is about $98, with standard deviation $11. A random sample of 36 households in a certain affluent community yields a mean weekly food budget of $100. We want to test the hypothesis that the mean weekly food budget for all households in this community is higher than the national average. State the null and alternative hypotheses for this test, the test statistic and determine if the results significant at the 5% level.

Answers

Answer:

The null hypothesis is

$H_o : \mu =$ $98

The alternative hypothesis is

$H_a : \mu >$ $98

test statistics $t_s = 1.091$

The the result of the test statistics is significant

Step-by-step explanation:

From the question we are told that

The population mean is $\mu =$ $98

The standard deviation is $\sigma =$ $11

The sample size is $n = 36$

The sample mean is $\= x =$ $100

The level of significance is $\alpha = 5$ % = 0.05

The null hypothesis is

$H_o : \mu =$ $98

The alternative hypothesis is

$H_a : \mu >$ $98

Now the critical values for this level of significance obtained from critical value for z-value table is $z_\alpha = 1.645$

The test statistics is mathematically evaluated as

$t_s = (\= x - \mu)/( (\sigma )/( √(n) ) )$

substituting values

$t_s = (100 - 98)/( (11 )/( √(36) ) )$

$t_s = 1.091$

Looking at $z_\alpha \ and \ t_s$ we see that $z_\alpha \ > t_s$ hence the we fail to reject the null hypothesis

hence there is no sufficient evidence to conclude that the mean weekly food budget for all households in this community is higher than the national average.

Thus the the result is significant

Which of the following must be given to prove that ΔABC is similar to ΔDBA?a. Segment AD is an altitude of ΔABC.
b. Segment CB is a hypotenuse.
c. Segment CA is shorter than segment BA.
d. Angle C is congruent to itself.

Answers

Answer:

The correct answer is option A.

Step-by-step explanation:

For the given triangles to be similar the segment AD must be an altitude of ΔABC.

We can provide a theorem for the same:

If we draw an altitude from the right angle of any right triangle, then the two triangles formed are similar to the original triangle.

Also all the three triangles are similar to each other.

Like here, in the triangle ABC, we draw an altitude from A to the side BC, thus forming 2 triangles; ΔDBA and ΔDAC. These both will be similar to ΔABC.

So, by the theorem it is proven that ΔABC is similar to ΔDBA.

Therefore, option A is correct.

this answer is a (A) segment AD is an altitude at angle ABC

1/4÷(-2/3) =3/8 she is right now did she get the answer

Answers

Answer:

see below for the working

Step-by-step explanation:

Dividing by a number is the same as multiplying by the inverse of that number.

$\displaystyle(\left((1)/(4)\right))/(\left(-(2)/(3)\right))=-(1)/(4)\cdot(3)/(2)=-(3)/(4\cdot 2)=-(3)/(8)$

Please help me with number 7 and 8 and explain both of them how you got it. Will mark the brainliest!

Answers

7. No this isnt possible only a irregular shape, a square or a rectangle.
8. True. it has 4 equal sides and 4 equal angles.

g Determine the critical values for these tests of a population standard deviation. (a) A right-tailed test with 16 degrees of freedom at the alphaequals0.01 level of significance (b) A left-tailed test for a sample of size nequals23 at the alphaequals0.1 level of significance (c) A two-tailed test for a sample of size nequals31 at the alphaequals0.1 level of significance

Answers

Answer:

Step-by-step explanation:

We are to find critical values for the test given

a) df =16: Alpha = 0.01 and right tailed

Critical value= 2.583

b) df = 23-1 = 22: alpha = 0.1 and left tailed

critical= -1.717

c)df=31-1 =30: alpha =0.1: two tailed

t =1.697

Critical values can be obtained from critical t tables.

Left tailed will have negative sign and right tailed positive

Final answer:

The critical values for these tests of a population standard deviation can be found via looking up a chi-square distribution table at the specified degrees of freedom and alpha level. For a two-tail test, the alpha value needs to be divided equally in the two tails.

Explanation:

To determine the critical values for these tests of a population standard deviation, we first need to understand the critical values for a chi-squared test. The chi-square test is used when the degrees of freedom and the level of significance (alpha) are known.

(a) A right-tailed test with 16 degrees of freedom at the alpha equals 0.01 level of significance: To find this critical value, we would check a chi-square distribution table at 16 degrees of freedom and alpha equals 0.01. The value we find is the critical value.

(b) A left-tailed test for a sample of size n equals 23 at the alpha equals 0.1 level of significance: Similarly, we would check the chi-square distribution table but this time at 22 degrees of freedom and alpha equals 0.1. Please note that degrees of freedom is calculated as n-1 which gives us 22 in this case.

(c) A two-tailed test for a sample of size n equals 31 at the alpha equals 0.1 level of significance: For a two-tailed test, we distribute the alpha equally in the two tails of the distribution. That means, we lookup chi-square distribution table for 30 degrees of freedom and alpha equals 0.05 to get our critical value.

Learn more about Population Standard Deviation here:

brainly.com/question/29320183

#SPJ3

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