What is the molarity of a solution that contains 12 moles of cacl2 in 3 liters of solution?

Answers

Answer 1

Answer: Molarity is defined as the number of moles of solute dissolved in a volume of 1 L.
the number of moles of CaCl₂ present - 12 mol
Volume of solution - 3 L
Therefore if 3 L contains 12 mol of CaCl₂
then 1 L of CaCl₂ contains - $(12 mol)/(3 L)$ = 4 mol/L
Therefore molarity of CaCl₂ is 4 M

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Is the following a chemical change or a physical change? A pencil is sharpened in a pencil sharpener, leaving behind shaving. Physical Change Chemical Change

Answers

This is an example of physical change, because the pencil's chemical composition does not change.

*Physical Change.*
A physical change in a substance doesn't change what the substance is.
A Chemical change, there is a chemical reaction, a new substance is formed and energy is either given off or absorbed.

A patient is given 0.050 mg of technetium-99 m (where m means metastable—an unstable but long-lived state), a radioactive isotope with a half-life of about 6.0 hours.How long until the radioactive isotope decays to 1.3×10−2 mg ?

Answers

The correct answer is 9.6h.

As you know, a radioactive isotope's nuclear half-life tells you exactly how much time must pass in order for an initial sample of this isotope to be halved.

Using the formula , A = Ao. $1/2^n$

where , A- final mass after decay

Ao - initial mass

n - the number of half-lives that pass in the given period of time

Now, putting all the values, we get

1.3 × $10^-2$ mg = 0.050 mg × $1/ 2^n$

Take the natural log of both sides of the equation to get,

㏑ $(1.3 . 10^(-2) / 0.050 )$ = ㏑ $((1/2)^(n))$

㏑ $(1.3 . 10^(-2) / 0.050 )$ = n. ln $(1/2)\n$

n = 1.6

Since n represents the number of half-lives that pass in a given period of time, you can say that

$n = t / t _(1/2)$

t= 1.6 × 6 h

t = 9.6h
Hence, it will take 9.6 h until the radioactive isotope decays.

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Final answer:

Using the formula for radioactive decay and the provided half-life of technetium-99m, it can be calculated that it takes approximately 28.5 hours for 0.050 mg of technetium-99m to decay to a quantity of 1.3 x 10^-2 mg.

Explanation:

The decay of a radioactive isotope is an exponential process based on the half-life, which is, in turn, constant for any given isotope. The general formula for the remaining quantity of a radioactive isotope after a given time is given by: N = N0 (0.5) ^(t/t1/2), where (N0) is the initial amount, (N) is the remaining amount, (t) is time, and (t1/2) is the half-life of the isotope. In this case, we are given the initial quantity (N0 = 0.050 mg), the remaining quantity (N = 1.3 x 10^-2 mg), and the half-life (t1/2 = 6.0 hours).

We can solve for time (t) in the equation: N = N0 (0.5) ^(t/t1/2). Plugging in the values, we get 1.3 x 10^-2 = 0.050 x (0.5)^(t/6), and solving for t, we find that it takes approximately 28.5 hours for the technetium-99m to decay to 1.3 x 10^-2 mg.

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Look at the image above then answer these questions:Which one is the correct answer? Why is it the correct answer?

Answers

Answer:

yes its correct, temperature is a measure of energy particles have, the more energy the faster they move and the higher the temp

Explanation:

Calculate the pH of an acetic acid solution, originally 0.25 M, in water. The pKa for acetic acid = 4.76. Use the x-is-small approximation. Enter your answer with two digits after the decimal point.

Answers

Answer:

Initial concentration of acetic acid (CH3COOH_initial): 0.25 M

pKa for acetic acid: 4.76

Assume x is the concentration of H+ ions formed through dissociation.

CH3COOH ⇌ x (due to dissociation)

Apply the x-is-small approximation: We assume x is much smaller than the initial concentration of acetic acid (0.25 M). Therefore, we can neglect x in comparison to 0.25 M.

Calculate pH using the pKa equation:

Rounded to two decimal places, the pH of the acetic acid solution is approximately 2.68.

Explanation:

All of the following are true of carbon except which of the following?a. Carbon is the major component of inorganic molecules.
b. Carbon is ranked seventeenth in abundance in Earth's crust.
c. Carbon is readily found combined and uncombined in nature.
d. Carbon is found in all living matter and in common fuels including coal.

Answers

All the statements are true about carbon except option a. Carbon is not a major component of inorganic molecules.

What is carbon?

Carbon is 6th element in periodic table. It is in 14th group and is a non-metal or gas. Carbon is present in all living matter and in common fuels including coal.

Carbon can be readily found in combined or non-combined state. Carbon is the major component of organic molecules and not that of inorganic molecules.

Organic molecules are hydrocarbons or their derivatives whose backbone is carbon chain. Therefore, option a is not true about carbon.

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I think the answer is D

What balances charges that may build up as reduction and oxidation occur in a voltaic cell?a.
the salt bridge
c.
the electrolyte solutions
b.
one of the half-cells
d.
the moving electrons

Answers

I think the correct answer from the choices listed above is option A. It is the salt bridge that balances charges that may build up as reduction and oxidation occur in a voltaic cell. The salt bridge is to maintain charge balance because the electrons are moving from one half cell to the other.

Answer: Option (a) is the correct answer.

Explanation:

In a voltaic cell, salt bridge is used for connecting oxidation and reduction half cells.

The main purpose of using salt bridge in a voltaic cell is that it helps in maintaining electrical neutrality in the internal circuit occurring at anode and cathode of the cell.

Without salt bridge in a voltaic cell there will be imbalance of charges as a result solution in anode compartment will become positively charged whereas solution in cathode compartment will become negatively charged.

Thus, we can conclude that the salt bridge balances charges that may build up as reduction and oxidation occur in a voltaic cell.

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