I need help um i dont need to to my work or check my answer justAs you can see, I can figure out the problems fine, its explaining how the solution is related to the situation. If you could help, or if you see any problems with my work, it would be very appreciated. Thank you for your time.
Answers
area=legngth tiimes width
legnth is 10 more than 2 times width
l=10+2w
lw=area=(10+2w)w=10w+2w^2
area=3600
3600=10w+2w^2
so divide by 2
1800=5w+w^2
subtract 1800 from both sides
(note they used x instead of w)
0=w^2+5w-1800
then the facotred form is (w-40)(w+45)=0
0 product property measn if you have xy, then x and or y =0
therefor
w-40=0 and w+45=0
w=40 or -45
discard negative because negative legnth is not possible
explian how solution relates to situation
it is math so it is correct because we represented it corrrectly
the other solution is because of math and eliminate negative legnth becasue tha tis not possible
basically because we represented it correctly
not a very clear quetion to answer
basically 'because it represents the solution so we solved it and it is correct'
#3:
In the first paragraph, the equation is x² + 5x - 1800 = 0 .
Here's where this equation comes from:
Call the width of the park 'x'.
Then, according to the question, the length is (2x + 10).
When you multiply (width) x (length) to get the area, and
simplify the product, it turns out that x² + 5x - 1800 = 0 .
But don't forget . . . 'x' started out being the width, and when
you figure out what 'x' is, that'll be the width of the dog park.
3.a). is factoring the equation, getting ready to solve it.
3.b). is finding the solutions for 'x' from the factored form.
Remember that every quadratic equation has two solutions.
In this one, they are x = 40 and x = -45 .
'x' is the width of the dog park. Can it be both values ?
Can it be only one of them ? Can it be 40 ? How about -45 ?
3.c). 'x' is the width of the real dog park. In the real world, there's
no way the city engineers can build it with a negative width.
That would be totally silly. So the real width 'x' = 40 yards.
Now look way back at the question:
"The length of the park is 10 more than twice the width."
The width is 40 yards.
Twice the width is 80 yards.
10 more than that is 90 yards.
==> The length is 90 yards.
Now we have (length = 90 yards) and (width = 40 yards).
How do we know if these are correct ?
Well, let's use them to calculate the area.
Area = (length) x (width)
= (90 yards) x (40 yards) = 3,600 square yards.
That's what the question said !
We got the right numbers ! yay !
_______________________________________________
#4
This one is very similar to the dog park in many ways.
Again, in the first paragraph, the signs are missing from the
equation. The correct equation is: x² + 6x - 55 = 0 .
This is also a tricky question, because some of the information
in the first paragraph is only there to confuse you. That business about "... increase both the height and the width ... by 3 inches."
You don't need that ! It may come up in #5, I don't know. But here
in #4, it never asks anything about it, and you don't need to know it.
All you need to know is that it's a "square image". That does that
tell you ? It tells you that the height and width are equal !
That's why the equation x² + 6x - 55 = 0 "can be used to find the
height and width of the original image" . They're both the same.
4.a). is factoring the equation, getting ready to solve it.
4.b). is finding the solutions for 'x' from the factored form.
Remember that every quadratic equation has two solutions.
In this one, they are x = 5 and x = -11 .
'x' is a dimension of the image. Can it be either value ?
Can it be only one of them ? Can it be 5 ? How about -11 ?
4.c). 'x' is a dimension of the real image. In the real world,
there's no way the graphic designer can start with an image
that has a negative dimension. That would be totally silly.
So the real dimension of the image is 5 inches.
Since it's square, the length and width are both 5 inches.
________________________________________
Now I'll just bet that there's another problem coming along to
ask you what the area of the new, bigger image is going to be,
after he increases both the height and the width of the image
by 3 inches. You don't need to worry about crossing that
bridge until you come to it.
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Answers
Answers
Answer:
This system of equations has infinite points of intersection
Step-by-step explanation:
* To know the point of intersection of the system of equations,
you will solve the graphically or algebraically
- Graphically by drawing two lines on the coordinate plane
- Algebraically by substitution method or elimination method
* Lets use the substitution method
∵ y = 4 - x
∵ 2y = 8 - 2x
- Substitute y in the second equation by its value in the
first equation
∴ 2(4 - x) = 8 - 2x ⇒ open the bracket
∴ 8 - 2x = 8 - 2x
* The two sides equal each other, that means we can use any
vales of x, and on the graph they will be the same line for
the two equations
∴ This system of equations has infinite points of intersection
Answers
1 oz=0.0283495 kilograms
first convert 13 pounds to oz
16 oz=1 poiund
13 pounds=16 times 13 oz=208 oz
add
208+7=215 oz
so 215 oz=0.0283495 times 215=6.095=6
answer is 6 kilograms
Well, you've got a problem there, because "kilogram" is not a unit
of weight or force. It's a unit of mass, and it has different weights
in different places.
On the moon, 13 pounds 7 ounces is the weight of about
36.8 kilograms of mass.
On Mars, 13 pounds 7 ounces is the weight of about
16.1 kilograms of mass.
On Earth, 13 pounds 7 ounces is the weight of about
6.09 kilograms of mass.
Answers
0.07 and 0.35 are not the same
Answers
Answer:
θ = 52.71° or 232.71°
In radians
θ = 0.2928π rad or 1.2928π rad
That is,
θ = 0.92 rad or 4.06 rad
Step-by-step explanation:
Cot θ = 0.7615 for 0 ≤ θ ≤ 2π
Note that Cot θ = (1/tan θ)
(1/tan θ) = 0 7615
tan θ = (1/0.7615) = 1.3132
θ = tan⁻¹ (1.3132) = 52.71°
But, note that tan is also positive in the 3rd quadrant, hence,
θ is also equal to 180° + 52.71° = 232.71°
θ = 52.71° or 232.71°
We now convert to radians
360° = 2π
52.71° = (52.71 × 2π)/360 = 0.2928π = 0.92 radian
232.71° = (232.71 × 2π)/360 = 1.2928π = 4.06 radians
Hope this Helps!!!
Answers
area of a cube=6*(14 m)²=6*196 m²=1176 m²
Answer: 1176 m²
SA = 6 × (14)²
SA = 6 × 14×14
SA = 6×14
SA= 84²
which would give you 1176m²