Tom just received a credit card with an introductory APR of 0% for nine months and a credit limit of $500. The APR for purchases after the introductory period is 19.9%. The penalty APR is 24.9% and the APR for cash advances is 20.4%. Tom uses his card at the mall and spends $360. If Tom wants to have a balance of $0 before his introductory period expires, what monthly payments should he make?

Answers

Answer 1
Answer:

Answer:

The monthly payment Tom must make is $40

Step-by-step explanation:

The steps taken in solving the problem is shown below

Tom received a credit card with an APR =0%

The credit limit is = $500

The APT for purchases after the introductory period is = 19.9%

The APR penalty is = 24.9%

APR cash advances = 20.4%

Tom spends $360 with his card at the mall, for which  He wants his balance to be zero  before his introductory period elapses.

For a 9 months period, Tom must divide his spending's  /expenses

Therefore

$360 ÷ 9 months gives  = $40

Answer 2
Answer: Given:
0% - APR for nine months
$500 - credit limit
19.9% - APR after nine months
24.9% - APR penalty
20.4% - APR for cash advance

Tom spends $360. He wants to have a zero balance before his introductory period expires.

Tom must divide his spending by 9 months.

$360 ÷ 9 mos = $40

Tom should make a monthly payment of $40 for nine months to achieve a balance of zero before the introductory period expires.

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mike drove to a frineds house at the rage of 40 mph. he returned hoke by the dsne route at 45 mph the driving time for the round trip was four hours how long did it take mike to get home

Answers

Let the distance be x miles

Time = Distance / speed

Time taken by Mike to go to his friend's house = x / 40 hours

Time taken by him to return = x / 45 hours

Total time = x / 40 + x / 45 = 4 hours

= 9x + 8x = 1440 miles

17x = 1440

= x = 1440 ÷ 7

= x = 84.706

Time taken to return home = 84.706 /45= 1.882 hours .

Therefore , Mike took1.882hoursto reach home .

Find the area of a regular hexagon with an apothem 10.4 yards long and a side 12 yards long

Answers

The area of a regular hexagon with an apothem 10.4 yards long and a side 12 yards longis 374.4 yard^2.

What is a regular hexagon?

A regular hexagon is defined as a closed shape consisting of six equal sides and six equal angles. The sum of the measure of angles of a regular hexagon is 120 degrees.

The area of a regular hexagon = (1)/(2) * h* p

It is given that apothem is 10.4 yards and side is 12 yards long.

The area of a regular hexagon = (1)/(2) * h* p

                                               = 6× 10.4 × (12/2)

                                                = 374.4 yard^2

Thus the area of a regular hexagon is 374.4 yard^2.

Learn more about regular hexagons;

brainly.com/question/1694257

Regular hexagon consists of 6 congruent triangles.
So the area, A, of the regular hexagon is 6 x the area of one triangle
The area of a triangle is half the base times the height
The height of a triangle is the apothem of the hexagon and the base is the side of the hexagon.

A = 6* 10.4 * (12/2) yard^2 = 374.4 yard^2

How do you solve 2(10-6x)=x-8x
Show work

Answers

2(10)-2(6x)= x-8x 
20-12x=x-8x 
   +12x+12x

20=13x-8x
20=5x 
4=x
Hey, Lizzy147! 
1st. Distribute 2 to 10 and -6x
20-12x=x-8x 
2nd. Move -12x to the other side.
20=13x-8x
Simple math.
20=5x 
x=4

I need help with this question ( see image).
Please show workings.​

Answers

Answer:

#4

2.50 out of 15 is:

  • 2.50/15*100% = 16.67%

#5

  • Salary = 9600
  • Increase = 1680

Percent increase:

  • 1680/9600*100% = 17.5%

Can someone explain how to get the answer?

Answers

Answer:

54 degrees.

Step-by-step explanation:

By the external angle of a triangle theorm:

7x + 1 + 7x - 2 = 111

14x - 1 = 111

14x = 112

x = 112/14

  = 8.

So, m < S = 7(8) - 2

                =  54 degrees.

Which statistic can be used to determine the probability of variances occurring? a. Binomial Statistic b. Poisson Statistic c. Moving Average Statistic d. Chi-Square statistic

Answers

Answer:

To determine the probability of variances occurring, the appropriate statistic would be d) Chi-Square statistic.