**PLEASE PLEASE HELP WILL GIVE BRAINLIEST TO FIRST LOTS OF POINTS* Any help would be appreciated. If you could even answer one of the problems I would be grateful!

Answers

Answer 1

Answer: b) RH = UM = HM = RU Reason: Since they form a rhombus, its sides are of equal length.
c) RUBM is a rhombus Reason: Given
d) Reason: RUBM is identified as a rhombus. Thus, its sides are of equal length.
e) RUMH and RUBM are rhombus which have similar dimensions. Each sides of any rhombus is equal in length and since both are of similar dimensions, then, all of their sides lengths are equal with each other.
f) Rhombus have opposite sides that are parallel and its opposite angles are equal. Rhombus is also called a parallelogram.

Answer 2

Answer:

Answer:

b) RH = UM = HM = RU Reason: Since they form a rhombus, its sides are of equal length.

c) RUBM is a rhombus Reason: Given

d) Reason: RUBM is identified as a rhombus. Thus, its sides are of equal length.

e) RUMH and RUBM are rhombus which have similar dimensions. Each sides of any rhombus is equal in length and since both are of similar dimensions, then, all of their sides lengths are equal with each other.

f) Rhombus have opposite sides that are parallel and its opposite angles are equal. Rhombus is also called a parallelogram.

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Factorise xy(x-y)+yz(y-z)+zx(z-x)

Answers

expand first:-
yx^2 - xy^2 + zy^2 -yz^2 + xz^2 - zx^2
there is no common factor so we cant factorize this

|2x-3| < 9 solve for x

Answers

$|2x-3| < 9 \n \n2x-3 < 9 \ \ and \ \ 2x-3 > -9 \n \n 2x < 9 +3 \ \ and \ \ 2x > -9 +3 \n \n 2x < 12\ \ and \ \ 2x > -6 \n \n x < 6\ \ and \ \ x > - 3 \n \n x \in (-3,6)$

$|2x-3| < 9\iff2x-3 < 9\ \wedge\ 2x-3 > -9\n\n2x < 9+3\ \wedge\ 2x > -9+3\n\n2x < 12\ \wedge\ 2x > -6\n\nx < 6\ \wedge\ x > -3\n\n\nx\in(-3;\ 6)$

2x+14/2 +1 = 10-x/5

please help

Answers

Hope my ans helps u

2x+14/2+1=10-x/5
3x+14/2+1=10/5
3x+8=2
3x=-6
X=-2

8 = -8
A True
© False
????

Answers

Answer:

FALSE

Step-by-step explanation:

Answer:

False

Step-by-step explanation:

8 does not equal -8 becsue one is positive and the other is negative

How do I find a2 and a3 for the following geometric sequence? 54, a2, a3, 128

Answers

The formula for the nth term of a geometric sequence:
$a_n=a_1 * r^(n-1)$
a₁ - the first term, r - the common ratio

$54, a_2, a_3, 128 \n \na_1=54 \na_4=128 \n \na_n=a_1 * r^(n-1) \na_4=a_1 * r^3 \n128=54 * r^3 \n(128)/(54)=r^3 \n (128 / 2)/(54 / 2)=r^3 \n(64)/(27)=r^3 \n\sqrt[3]{(64)/(27)}=\sqrt[3]{r^3} \n\frac{\sqrt[3]{64}}{\sqrt[3]{27}}=r \nr=(4)/(3)$

$a_2=a_1 * r= 54 * (4)/(3)=18 * 4=72 \na_3=a_2 * r=72 * (4)/(3)=24 * 4=96 \n \n\boxed{a_2=72, a_3=96}$

$a=54 \n \n a2=54q \n \n a3=54q^(2) \n \n 128=54q^(3) \n \n q^(3)= (128)/(54)= (64)/(27) \n \n q= (4)/(3) \n \n a2= 54*(4)/(3)= 72 \n \n a3=54*( (4)/(3))^(2)=54* (16)/(9) =96$

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Eric and four of his friends are taking a trip across the New York State Thruway. They decide to split the cost of tolls equally. If the total cost of tolls is $8, how much will each person have to pay? Include the product of rational numbers (multiplication problem) you used to find your answer.

Answers

Answer:

1$ and 60 cent each

Step-by-step explanation:

****PLEASE PLEASE HELP WILL GIVE BRAINLIEST TO FIRST LOTS OF POINTS*** Any help would be appreciated. If you could even answer one of the problems I would be grateful!

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**PLEASE PLEASE HELP WILL GIVE BRAINLIEST TO FIRST LOTS OF POINTS* Any help would be appreciated. If you could even answer one of the problems I would be grateful!