HELP ME WITH MATH PLZ !!!!
HELP ME WITH MATH PLZ !!!! - 1

Answers

Answer 1
Answer: first you write out the equation
(1)/(16) + (3)/(16)
because of the way the fractions are written, just add the top numbers

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Identify the turning point of the function f(x)=x^2-2x+8 by writing its equation in vertex form.Show work

Answers

f(x)=x^2-2x+8 \n \n To \ convert \ the \ standard \ form \ y = ax^2 + bx + c \n \n of \ a \ function \ into \ vertex \ form \n \n y = a(x - h)^2 + k \n \n Here \ the \ point \ (h, k) \ is \ called \ as \ vertex \n \n h=(-b)/(2a) , \ \ \ \ k= c - (b^2)/(4a)\n \n a=1 ,\ b=-2 , \ c = 8

h=(-b)/(2a)=(-(-2))/(2 )=(2)/(2)=1 \n\n k=c - (b^2)/(4a) =8 - ( (-2)^2)/(4 ) = 8-1 = 7 \n \n y= (x-1)^2 + 7 \n \n So \ the \ turning \ point \ is \ (1,7)


A 5 inch tall bamboo shoot doubles in height every 3 days. If the equation y=ab^x, where x is the number of doubling periods, represents the height of the bamboo shoot, what are the values of a and b?

Answers

The correct answer for the question that is being presented above is this one: "x = 2; a = 5; b = 3" A 5 inch tall bamboo shoot doubles in height every 3 days. If the equation y=ab^x, where x is the number of doubling periods, represents the height of the bamboo shoot

Answer:

Given the equations:

y=ab^x        ....[1]

where,

a is the initial amount

b is the growth rate.

x is the number of doubling period and

y represents the height of the bamboo shoot.

As per the statement:

A 5 inch tall bamboo shoot doubles in height every 3 days.

⇒y(0)=a= 5 inch

doubles in height every 3 days

then

in 1 days =  (x)/(3)

then the height of the bamboo shot becomes:

y=5(2)^{(x)/(3)}

y = 5(\sqrt[3]{2})^x

On comparing with [1] we have;

a = 5 in and b = \sqrt[3]{2}

Therefore, the value of a = 5 and  b = \sqrt[3]{2}

which of the following expressions does not contain any like terms? a. 2x^2+3x-4x+2 b. xy+yz-17 c. x^3+x^2-2x-x^2 d. 14+8+y

Answers

Answer : B


The expression xy+yz-17 do not contain any like terms


I hope that's help !

(5xy - y^2) - (3yz + 2xy) + (3y^2 - 4xy)

Answers

(5xy - y^2) - (3yz + 2xy) + (3y^2 - 4xy) \n= 5xy-y^2-3yz-2xy+3y^2-4xy \n =2y^2-xy-3yz
(5xy - y^2) - (3yz + 2xy) + (3y^2 - 4xy)=\n 5xy-y^2-3yz-2xy+3y^2-4xy=\n 2y^2-xy-3yz

Simplify this expression. 2 square root 5 (13 + square root 2)

Answers

The product of 2 square root 5 (13 + square root 2) in simplified form is 26√5 + 2√10

Calculating the product in simplified form

From the question, we have the following parameters that can be used in our computation:

2 square root 5 (13 + square root 2)


Express as products

So, we have

2√5 * (13 + √2)

Open the brackets

So, we have

2√5 * (13 + √2) = 2√5 * 13 + 2√5 *√2

Multiply the radicands

So, we have the following

2√5 * (13 + √2) = 2√5 * 13 + 2√10

Evaluate the products

So, we have the following

2√5 * (13 + √2) = 26√5 + 2√10

Hence, the solution is 26√5 + 2√10

Read more about expressions at

brainly.com/question/34777630

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Answer:

i'm assuming it's 2*√5(13+√2) so 2√10+26√5

Step-by-step explanation:

a type of brass is made by combing copper and zinc in a 8:2 ratio. if you want to make 2kg of brass, how many grams of copper do you need

Answers

Answer:

2.5gramsofCopper

Step-by-step explanation:

• Total ratio = 8 + 2 = 10

Let the grams of copper be y

{ \tt{ (8)/(10) * y = 2 }} \n \n { \tt{8y = 2 * 10}} \n { \tt{8y = 20 \: \: \: \: \: \: \: \: \: }} \n { \tt{y = 2.5}}

Grams of copper = 2.5 g