Angela and Ryou are painting a room. Angela has 2 1/2 gallons of blue paint and Ryou has half as much white paint. It will take 2 3/4 quarts to cover each wall. if each wall is painted only one color, how many walls will be blue and how many will be white? How much paint will be left over?

Answers

Answer 1

Answer: If my math is correct you should be able to get 15 walls done, 10 are blue and 5 would be white

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|)) Which sign makes the statement true?
83.95% ? 83.95%
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Submit

Answers

Answer: =

Step-by-step explanation:

83.95% is equal to 83.95% (look at it)

Answer:

Step-by-step explanation:

umm 83.95 = 83.95?

One sample has a mean of and a second sample has a mean of . The two samples are combined into a single set of scores. What is the mean for the combined set if both of the original samples have scores

Answers

Answer:

a) For this case we can use the definition of weighted average given by:

$M = ( \bar X_1 n_1 + \bar X_2 n_2)/(n_1 +n_2)$

And if we replace the values given we have:

$M = (8*4 + 16*4)/(4+4)= 12$

b) $M = (8*3 + 16*5)/(3+5)= 13$

c) $M = (8*5 + 16*3)/(5+3)= 11$

Step-by-step explanation:

Assuming the following question: "One sample has a mean of M=8 and a second sample has a mean of M=16 . The two samples are combined into a single set of scores.

a) What is the mean for the combined set if both of the original samples have n=4 scores"

For this case we can use the definition of weighted average given by:

$M = ( \bar X_1 n_1 + \bar X_2 n_2)/(n_1 +n_2)$

And if we replace the values given we have:

$M = (8*4 + 16*4)/(4+4)= 12$

b) what is the mean for the combined set if the first sample has n=3 and the second sample has n=5

Using the definition we have:

$M = (8*3 + 16*5)/(3+5)= 13$

c) what is the mean for the combined set if the first sample has n=5 and the second sample has n=3

Using the definition we have:

$M = (8*5 + 16*3)/(5+3)= 11$

Which ordered pair describes the location of point x

Answers

x , y
If I understand the question correctly

Perform the indicated operations. Write answer in descending order.Add -3x, 5x + y, and 7x - 8 - 3y

Answers

The required sum of -3x, 5x + y, and 7x - 8 - 3y in descending order is 9x - 2y - 8.

What is simplification?

Simplification involves applying rules of arithmetic and algebra to remove unnecessary terms, factors, or operations from an expression. The goal is to obtain an expression that is easier to work with, manipulate, or solve.

Here,
To add -3x, 5x + y, and 7x - 8 - 3y, we can first combine like terms.

Group the x-terms together:

-3x + 5x + 7x = 9x

Group the y-terms together:

y - 3y = -2y

Group the constants together:

-8

Putting it all together, we get:

9x - 2y - 8

Therefore, the sum of -3x, 5x + y, and 7x - 8 - 3y in descending order is 9x - 2y - 8.

Learn more about simplification here:

brainly.com/question/12501526

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9x - 2y - 8
F I N A L A N S W E R

A certain test preparation course is designed to help students improve their scores on the MCAT exam. A mock exam is given at the beginning and end of the course to determine the effectiveness of the course. The following measurements are the net change in 7 students' scores on the exam after completing the course: 37,12,12,17,13,32,23 Using these data, construct a 80% confidence interval for the average net change in a student's score after completing the course. Assume the population is approximately normal. Step 1 of 4 : Calculate the sample mean for the given sample data. Round your answer to one decimal place.

Answers

Answer:

The 80% confidence interval for the average net change in a student's score after completing the course is (15.4, 26.3).

Step-by-step explanation:

The net change in 7 students' scores on the exam after completing the course are:

S = {37 ,12 ,12 ,17 ,13 ,32 ,23}

Compute the sample mean and sample standard deviation as follows:

$\bar x=(1)/(n)\sum x=(1)/(7)* 146=20.857\n\ns=\sqrt{(1)/(n-1)\sum (x-\bar x)^(2)}}=\sqrt{(1)/(7)* 622.8571}=10.189$

As the population standard deviation is not known, a t-interval will be formed.

Compute the critical value of t for 80% confidence interval and 6 degrees of freedom as follows:

$t_(\alpha/2, (n-1))=t_(0.20/2, (7-1))=t_(0.10,6)=1.415$

*Use a t-table.

Compute the 80% confidence interval for the average net change in a student's score after completing the course as follows:

$CI=\bar x\pm t_(\alpha/2, (n-1))*(s)/(√(n))$

$=20.857\pm 1.415*(10.189)/(√(7))\n\n =20.857\pm 5.4493\n\n=(15.4077, 26.3063)\n\n\approx (15.4,26.3)$

Thus, the 80% confidence interval for the average net change in a student's score after completing the course is (15.4, 26.3).

I really need help I posted this question 3 times and no answers, can someone help I even put extra points and ill give brainliest <333

Answers

Answer:

In a quadrilateral ABCD, ∠A = 100°, ∠B = 105° and ∠C = 70°, find ∠D.

Solution:

Here the sum of the four angles

or, ∠A + ∠B + ∠C + ∠D = 360°

We know, ∠A = 100°, ∠B = 105° and ∠C = 70°

or, 100° + 105° + 70° + ∠D = 360°

or, 275° + ∠D = 360°

∠D = 360° - 275°

Therefore, = 85°

i hope this was helpful. <3

crown?

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