Hello can you please help me posted picture of question

Answers

Answer 1

Answer: The term of degree 1 in the given polynomial is +9x.

The coefficient is the constant term that is being multiplied to the variable. The variable in this case is x and the constant being multiplied to x is 9. So the coefficient of the term is 9.

Therefore, the answer to this question is option A

Answer 2

Answer: The answer is A. 9
The leading coefficient for the term of the degree 1 is the number with only one variable (x)

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ASAP! GIVING BRAINLIEST! Please read the question THEN answer correctly! No guessing. Show your work or give an explaination.
Find the measurement of the numbered angles

A trapezoid is shown:

What is the area of the trapezoid?

Answers

Answer:

Area of trapezoid is:

162 cm²

Step-by-step explanation:

Area(A) of trapezoid is given by:

$A=(1)/(2)* (sum\ of\ parallel\ sides)* (Height)$

Here, we are given Height=9 cm

One parallel side=6 cm

Other parallel side=(12+6+12) cm

= 30 cm

Sum of parallel side=(6+30) cm

= 36 cm

Area= $(1)/(2)* 36* 9$

= 162 cm²

Hence, Area of trapezoid is:

162 cm²

A = 1/2(6+30)(9)
A = 1/2(36)(9)
A = 162
answer
162 cm^2

What is the value of the function at x = 2?

Answers

check the picture below.

Giuseppe is studying shark attacks around the world and finds that most such attacks occur during the day. He concludes that sharks usually do not eat at night. This conclusion is A) not justified, since sharks can't tell day from night. B) justified, since he studied attacks from all around the world. C) not justified, since people usually swim in the ocean during the day. D) justified, assuming that the sharks finish eating their kills before sunset.

Answers

Answer:

C) not justified, since people usually swim in the ocean during the day.

In tilapia, an important freshwater food fish from Africa, the males actively court females. They have more incentive to court a female who has already laid all of her eggs, but can they tell the difference? an experiment was done to measure the male tilapia's response to the smell of female fish. Water containing feces from females that were either pre-ovulatory (they still had eggs) or post-ovulatory (they had already laid their eggs) was washed over the gills of males hooked up to an electro-olfactogram machine which measured when the senses of the males were excited. The amplitude of the electro-olfactogram was used as a measure of the excitability of the males in the two different circumstances. Six males were exposed to the scent of pre-ovulatory females; their readings average 1.51 with a standard deviation of .25. Six different males were exposed to post-ovulatory females; their average readings of 0.87 with standard deviation is .31. Assume that the electro-olfactogram readings were approximately normally distributed within the groups.(A) test for a difference in the excitability of the males with exposure to these two types of females
(B) what is the estimated average difference in electro-olfactogram readings between the two groups? What is the 95% confidnece limit for the difference between population means?

Answers

Answer:

a) $t=\frac{1.51-0.87}{\sqrt{(0.25^2)/(6)+(0.31^2)/(6)}}=3.936$

"=T.INV(1-0.025,10)", and we got $t_(critical)=\pm 2.28$

Statistical decision

Since our calculated value is higher than our critical value, $z_(calc)=3.936>2.28=t_(critical)$ , we have enough evidence to reject the null hypothesis at 5% of significance.

b) $(\bar X_1 -\bar X_2) \pm t_(\alpha/2)\sqrt{(s^2_(1))/(n_(1))+(s^2_(2))/(n_(2))}$

The degrees of freedom are given:

$df = n_1 + n_2 -2 = 6+6-2 = 10$

$(1.51 -0.87) - 2.28\sqrt{(0.25^2)/(6)+(0.31^2)/(6)}= 0.269$

$(1.51 -0.87) + 2.28\sqrt{(0.25^2)/(6)+(0.31^2)/(6)}= 1.010$

Step-by-step explanation:

Part a

Data given and notation

$\bar X_(1)=1.51$ represent the mean for scent of pre ovulatory

$\bar X_(2)=0.87$ represent the mean for post ovolatory

$s_(1)=0.25$ represent the sample standard deviation for preovulatory

$s_(2)=0.31$ represent the sample standard deviation for postovulatory

$n_(1)=6$ sample size for the group preovulatory

$n_(2)=6$ sample size for the group postovulatory

z would represent the statistic (variable of interest)

$p_v$ represent the p value

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the mean's are different, the system of hypothesis would be:

H0: $\mu_(1) = \mu_(2)$

H1: $\mu_(1) \neq \mu_(2)$

If we analyze the size for the samples both are lower than 30, so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{\bar X_(1)-\bar X_(2)}{\sqrt{(s^2_(1))/(n_(1))+(s^2_(2))/(n_(2))}}$ (1)

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the statistic

We have all in order to replace in formula (1) like this:

$t=\frac{1.51-0.87}{\sqrt{(0.25^2)/(6)+(0.31^2)/(6)}}=3.936$

Find the critical value

We find the degrees of freedom:

$df = n_1 + n_2 -2 = 6+6-2 = 10$

In order to find the critical value we need to take in count that we are conducting a two tailed test, so we are looking for thwo values on the t distribution with df =10 that accumulates 0.025 of the area on each tail. We can us excel or a table to find it, for example the code in Excel is:

"=T.INV(1-0.025,10)", and we got $t_(critical)=\pm 2.28$

Statistical decision

Since our calculated value is higher than our critical value, $z_(calc)=3.936>2.28=t_(critical)$ , we have enough evidence to reject the null hypothesis at 5% of significance.

Part b

For this case the confidence interval is given by:

$(\bar X_1 -\bar X_2) \pm t_(\alpha/2)\sqrt{(s^2_(1))/(n_(1))+(s^2_(2))/(n_(2))}$

The degrees of freedom are given:

$df = n_1 + n_2 -2 = 6+6-2 = 10$

$(1.51 -0.87) - 2.28\sqrt{(0.25^2)/(6)+(0.31^2)/(6)}= 0.269$

$(1.51 -0.87) + 2.28\sqrt{(0.25^2)/(6)+(0.31^2)/(6)}= 1.010$

Use the given graph to determine the limit, if it exists. Find limit as x approaches three from the left of f of x. Please include an explanation in your answer, I don't really understand limits so I'll give brainliest to the best explanation.

Answers

Answer:

$\displaystyle \lim_(x \to 3^-) f(x) = -1$

General Formulas and Concepts:

Calculus

Limits

Right-Side Limit: $\displaystyle \lim_(x \to c^+) f(x)$
Left-Side Limit: $\displaystyle \lim_(x \to c^-) f(x)$

Graphical Limits

Step-by-step explanation:

As we approach 3 from the left according to the graph (follow the left graphed line), we see that we approach -1.

∴ $\displaystyle \lim_(x \to 3^-) f(x) = -1$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

Explain how you can use the Triangle Sum Theorem to find the measures of the angles in an equilateral triangle.The angles of an equilateral triangle are . Let the measure of each angle be x. Then, by the Triangle Sum Theorem, x + x + x = 3x = °_____________. Solving for x gives x = °____________.

Answers

Answers:

The first blank is 180

The second blank is 60

======================================

The triangle sum theorem basically says that adding up all three angles of any triangle always leads to 180 degrees. So that's why

(angle1)+(angle2)+(angle3) = 180

x+x+x = 180

3x = 180

Divide both sides of that last equation by 3. This is to undo the multiplication of 3 done to x.

3x = 180

3x/3 = 180/3 ... divide both sides by 3

x = 60

Each angle of this equilateral triangle is 60 degrees. In an equilateral triangle, all three sides are the same length. Also in an equilateral triangle, all three angles are the same measure and always 60 degrees.

Final answer:

The Triangle Sum Theorem says that all angles in a triangle add up to 180 degrees. In an equilateral triangle, all angles are equal. Hence, each angle is 60 degrees.

Explanation:

The Triangle Sum Theorem states that the sum of the measures of the angles in a triangle is always 180 degrees. Now, in an equilateral triangle, all angles are equal. Let's denote the measure of each angle with x. According to the theorem, the sum of these measures is x + x + x = 180. Simplifying this gives 3x = 180. Hence, solving for x, which refers to the measure of each angle in the equilateral triangle, we get x = 180 / 3 = 60 degrees. Thus, each angle in an equilateral triangle measures 60 degrees.

Learn more about Triangle Sum Theorem here:

brainly.com/question/13275340

#SPJ2

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Help!! Is anyone good at algebra??

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