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Find the missing coefficient. (5d − 7)(5d − 6) = 25d2 ++ 42 5 65 –5 –65

Answers

Answer 1

Answer:

Answer:

-65d

Step-by-step explanation:

(5d − 7)(5d − 6)

$(5d - 7)(5d - 6)$

Multiply it using FOIL method to find the missing term

Multiply 5d inside the second parenthesis and then multiply -7 inside second parenthesis

$5d \cdot 5d= 25d^2$

$5d \cdot -6= -30d^2$

$-7 \cdot 5d=-35d$

$-7 \cdot -6=42$

Now write all the terms together

$25d^2-30d-35d+42$

Combine like terms

$25d^2-65d+42$

HEre -65d is missing

Answer 2

Answer: i do believe it is -65d because the equation will look like this in the end
-65d=-65d.

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Which equation represents the line that passes through points (1, –5) and (3, –17)?A. y = -6x + 1
B. y = 6x + 1
C. y = -6x - 1
D. y = 6x - 1

Answers

Answer:

Step-by-step explanation:

I’m rusty with my math, so I’m not 100% sure this is correct. My best attempt.

(1,-5) & (3,-17)

1=1x, -5=1y, 3=2x, -17=2y

Formula is y2-y1/x2-x1

-17 - -5 = -12

3 - 1 =2

So -12/2 = -6

Formula for the line is

y-y1 = m (x-x1)

In this equation m=-6

Y - -5 = -6 ( x - 1 )

Answer:C

Step-by-step explanation:

I know the answer is 36 but I need to know the working out and I am unsure how to work the question out.Plz explain

Thanks in advance!! :)

Answers

Answer:

Step-by-step explanation:

Since the 3 numbers have a ratio of 2:3:7, that means it simplifies to that. So, there must be a common factor, let’s say x, for each of the numbers. Thus, the numbers are 2x, 3x, and 7x. To find the mean, we add up all of the numbers and divide by the number of numbers: (2x + 3x + 7x)/3 = 12x/3 = 4x = 48. Dividing by 4 on both sides gets x = 12. The median of the numbers is the number in the middle which is 3x. Substituting x = 12, we get: 3(12) = 36.

I hope this helps!!! :)

Find the volume of the cone below.

Answers

Answer:

$V =(1)/(3) \pi r^2 h$

For this case we know that the radius is r=7cm and the height is h =11cm. And replacing we got:

$V=(1)/(3) \pi (7cm)^2 (11cm)= (1)/(3) \pi (49cm^2) (11 cm)=(539)/(3) \pi cm^3$

And the best option would be:

$V = (539)/(3) \pi cm^3$

Step-by-step explanation:

For this case we know that the volume of the cone is given by:

$V =(1)/(3) \pi r^2 h$

For this case we know that the radius is r=7cm and the height is h =11cm. And replacing we got:

$V=(1)/(3) \pi (7cm)^2 (11cm)= (1)/(3) \pi (49cm^2) (11 cm)=(539)/(3) \pi cm^3$

And the best option would be:

$V = (539)/(3) \pi cm^3$

Find an equation for the tangent to the curve at P and the horizontal tangent to the curve at Q. y = 5 + cot x - 2 csc x 0 1 2 3 0 2 4 x y Upper QUpper P left parenthesis StartFraction pi Over 2 EndFraction comma 3 right parenthesis

Answers

Answer with explanation:

The given function in x and y is,

y= 5 +cot x-2 Cosec x

To find the equation of tangent, we will differentiate the function with respect to x

$y'= -\csc^2 x+2 \csc x* \cot x$

Slope of tangent at (π/2,3)

$y'_{((\pi)/(2),3)}= -\csc^2(\pi)/(2) +2 \csc (\pi)/(2)* \cot (\pi)/(2)\n\n=-1+2* 1 * 0\n\n= -1$

Equation of tangent passing through (π/2,3) can be obtained by

$\rightarrow (y-y_(1))/(x-x_(1))=m(\text{Slope})\n\n \rightarrow (y-3)/(x-(\pi)/(2))=-1\n\n\rightarrow 3-y=x-(\pi)/(2)\n\n\rightarrow x+y-3-(\pi)/(2)=0$