If there are 16 ounces in a pound how manyh are in 24 ounces

Answers

Answer 1
Answer: 16 ounces = 1 pound
1  ounce = 1/16 pound
24 ounces = 1/6 x 24 = 4 pounds

Answer: 4 pounds
Answer 2
Answer:

Final answer:

24 ounces equals 1.5 pounds, based on the conversion factor of 1 pound equals 16 ounces.

Explanation:

Your question is related to unit conversion. If we know that one pound equals 16 ounces, then to convert 24 ounces to pounds, we must divide 24 ounces by the number of ounces in a pound. Here's how we can do it:

  1. Set up the conversion: 24 oz / 16 oz/lb.
  2. Dividing these amounts gives the result: 24 / 16 = 1.5 lbs.

S, this means that 24 ounces is equal to 1.5 pounds.

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Hey can you please help me posted picture of question

Answers

it would be false i believe so and if it is wrong i am sorry

Nina made 8 withdrawals fromher bank account. If each
withdrawal was for $20, what
was the total change in her
bank account?

Answers

the total change in her bank account would be $160,

if you multiply 8x$20 you get $160

What is the average rate of change for this function for the interval from x= 2
to x = 4?

Answers

Answer:

8

Step-by-step explanation:

hn hn

Log8 (t) - log8 (5) = 1

Answers

Answer:

t = 40

Step-by-step explanation:

Given the logarithmic expression: log_8 (t) - log_8 5= 1

Use the Logarithmic Property (Quotient Rule):

log_b a - log_b c = log_b ((a)/(c))

log_8 (t) - log_8 5 = log_8 ((t)/(5)) = 1

Next, using the Logarithmic Property:  log_b b= 1

We must determine the possible value oft that can be divided by 5 to produce a quotient of 8 that will make the logarithmic property, log_b b= 1, true.  In that case, t = 40 divided by 5 results in a quotient of 8.

log_8 (t) - log_8 5 = log_8 ((t)/(5)) = log_8 ((40)/(5)) = log_8 8 = 1

Therefore, the value oft = 40.

The volume V of a growing spherical cell is V = 4 3 πr3, where the radius is measured in micrometers (1 µm = 10−6m). Find the average rate of change of V with respect to r when r changes from 6 to each of the following. (Round your answers to one decimal place.) (i) 6 to 9 µm
(ii) 5 to 6 µm
(iii) 5 to 5.1 µm

Answers

Final answer:

The average rate of volume change of a growing spherical cell for different changes in radius can be calculated using the formula for the volume of a sphere and the formula for average rate of change (ΔV/Δr).

Explanation:

To find the average rate of change of the volume V with respect to the radius r, you will need to subtract the initial volume from the final volume and then divide by the change in radius. This is represented by the formula ΔV/Δr, where Δ represents change in.

  1. For r changing from 6 to 9 µm, ΔV = V(9) - V(6) = 4/3π(9^3) - 4/3π(6^3). Therefore, ΔV/Δr = (4/3π(9^3) - 4/3π(6^3)) / (9 - 6).
  2. For r changing from 5 to 6 µm, ΔV = V(6) - V(5) = 4/3π(6^3) - 4/3π(5^3). Therefore, ΔV/Δr = (4/3π(6^3) - 4/3π(5^3)) / (6 - 5).
  3. For r changing from 5 to 5.1 µm, ΔV = V(5.1) - V(5) = 4/3π(5.1^3) - 4/3π(5^3). Therefore, ΔV/Δr = (4/3π(5.1^3) - 4/3π(5^3)) / (5.1 - 5).

These calculations will give you the average rate of volume change for each of the radius changes indicated.

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Find the volume, I really need help, thank you!!

Answers

the area of the base
(4 * 6) / 2 = 24 / 2 = 12


the volume
12 * 6 = 72


the answer is 72 in^3




good luck