Here is how to do the question,
The Remainder Theorem starts with an unnamed polynomial p(x), where "p(x)" just means "some polynomial p whose variable is x". ... If you get a remainder, you do the multiplication and then add the remainder back in. For instance, since 13 ÷ 5 = 2 R 3, then 13 = 5 × 2 + 3. This process works the same way with polynomials.
Hope that helps!!!!
Answer:
Remainder Theorem starts with an unnamed polynomial p(x), where p(x) just means "some polynomial p whose variable is x". ... If you get a remainder, you do the multiplication and then add the remainder back in, For instance, since 13 ÷ 5 = 2 R 3, then 13 = 5 × 2 + 3. This process works the same way with polynomials
Choose the solution set.
-7x<-21
The only thing you need to do is just divide both sides by -7
-7x/-7<-21/-7
x>3
I hope that's help :)
after the bus. The bus has a 15-minute head start and
is traveling at an average rate of 40 mph. Clever is
traveling at an average rate of 60 mph. How long does
Clever take to catch up to the bus? Draw a diagram to
solve the problem.
Answer:
Speed = Distance / Time
Distance = Speed x Time
Bus: 15 x 40 = 600 m
Clever: 600 / 60 = 10 minutes
Answer = 10 mins
Step-by-step explanation:
hope it helps:) brainlest?!
Answer:
wheres the question??
Step-by-step explanation:
put a question pls
b. The median of the chosen number is 91, is there an limit to how large the aerge of the chosen numbers can be? If so, what is the largest the average can be?
c. The average of the chosen number is 91, what is the smallest the median of the 9 chosen numbers could be?
d. The average of the chosen numbers is 91. What is the largest the median of the chosen numbers could be?
Answer:
a) 1
b) There is no limit to which the largest number can be because we are only given information about the median.
c) 1
d) 90
The smallest average is 49 and the largest average is 91. The smallest median is 91 and the largest median is also 91.
a. Since the median is 91, at least 5 friends must choose numbers greater than or equal to 91, and at most 4 friends can choose numbers less than 91. To minimize the average, let's assume the four friends choose the smallest possible numbers less than 91 (1, 2, 3, and 4). The remaining five friends can then choose 91, 91, 91, 91, and 91. The average of the nine chosen numbers is (1 + 2 + 3 + 4 + 91 + 91 + 91 + 91 + 91)/9 = 49.
b. There is no limit to how large the average of the chosen numbers can be. The nine friends can all choose the same number, such as 91, which would make the average 91.
c. Since the average is 91, let's assume the eight friends choose the smallest possible numbers less than 91 (1, 2, 3, ..., 8). The remaining friend can then choose a number greater than or equal to 91. To minimize the median, the friend can choose the smallest possible number greater than or equal to 91, which is 91. So, the smallest median would be 91.
d. Since the average is 91, let's assume the eight friends choose the largest possible numbers less than 91 (84, 85, ..., 91). The remaining friend can then choose a number greater than or equal to 91. To maximize the median, the friend can choose the largest possible number greater than or equal to 91, which is 91. So, the largest median would also be 91.
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