the cost of picture framing depends on the Outer Perimeter of the frame if a 15 inch by 15 inch picture frame cost $35 more than a 10 inch by 10 inch picture frame what is the cost of framing in dollars per inch?

Answers

Answer 1
Answer: Let c be the cost of a 10" by 10" frame.  Then 

2(15 in)+ 2(15 in) = c+$35, so 60 in = c + $35

c = 4(10)= $40 for the 10 by 10 inch frame; ($40+$35), or $75, for the 15 by 15 inch frame.

cost per inch is $75/60 in, or $1.25/inch.  Same as $40/ 40 inches, or $1/inch.  Can't have 2 different answers!

Let's try again.  This time, let C represent the cost of the frame material in dollars per inch.

The 10 by 10 frame would cost (40 inches)C.

The 15 by 15 frame would cost (60 inches)C

and (60 inches)C = (40 inches)C + $35

Then 60C = 40C + $35
so that    20C = $35, and C = cost per inch = $35/20 inches = $1.75/inch (answer)


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Answers

Answer:

y = 4x + 2

Step-by-step explanation:

This is the formula:  y - y_(1) = m(x - x_(1))

y - 2 = 4(x - 0) (distribute the 4)

y - 2 = 4x (add 2 on both sides)

y = 4x + 2

That's all she wrote!

Hope this helps ya!!

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Answers

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Answers

Mutiply each by four to get n=-49.6. Hope this helped.

Answer:

Multiply by 4.

Step-by-step explanation:

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Answers

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The daily high temperatures, in degrees Celsius, for two weeks were recorded. The first week had a mean high temperature of 8 degrees Celsius and a mean absolute deviation (MAD) of 1 degree Celsius. The second week had a mean high temperature of 4.86 degrees Celsius and a mean absolute deviation (MAD) of 1.91 degrees Celsius. Which week had greater variability in high temperature? Explain your reasoning.

Answers

The required week that had greater variability in high temperature is week 2.

Given that,
The first week had a mean high temperature of 8 degrees Celsius and a mean absolute deviation (MAD) of 1 degree Celsius.
The second week had a mean high temperature of 4.86 degrees Celsius and a mean absolute deviation (MAD) of 1.91 degrees Celsius.

What is Statistic?

Statistics is the study of mathematics that deals with relations between comprehensive data.

Here,
The system of observation that has a higher mean absolute deviation, will have the chance of greater variability in high temperature. So,
mean absolute deviation of week 1 = 1
mean absolute deviation of week 2 = 1.91
MAD of week  2 > MAD of week 1

Thus, the required week that had greater variability in high temperature is week 2.

Learn more about Statistics here:
brainly.com/question/23091366

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Answer:

mean 4.86

MAD = 1.91

Step-by-step explanation:

33 is 50 percent of what number?

Answers

66 is the answer
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