CHEMISTRY HIGH SCHOOL

A soccer balll is travelling at a velcrocity of 50ms the kinetic energy of the ball is 500 what is the mass of the soccer ball

Answers

Answer 1

Answer:

KE = mv²/2

m=2*KE/v²

v=50 m/s

KE=500J

m=2*KE/v² =2*500/50²=1000/2500= 0.4 kg

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If the acetylene tank contains 37.0 mol of C2H2 and the oxygen tank contains 81.0 mol of O2, what is the limiting reactant for this reaction?

Answers

Answer: $O_2$ is considered as the limiting reagent for this reaction.

Explanation:

Limiting reagent is the reagent which limits the formation of the product.

Excess reagent is the reagent which is present in excess in a chemical reaction.

For the combustion of acetylene, the reaction follows:

$2C_2H_2(g)+5O_2(g)\rightarrow 4CO_2+2H_2O$

By Stoichiometry,

5 moles of oxygen gas reacts with 2 moles of acetylene.

So, 81 moles of oxygen gas will react with = $(2)/(5)* 81$ = 32.4 moles of acetylene.

As, the required amount of acetylene is less than the given amount. So, it is considered as an excess reagent and oxygen gas is the limiting reagent.

Answer:

Oxygen is the limiting reactant of this reaction.

Explanation:

$2C_2H_2+5O_2\rightarrow 4CO_2+2H_2O$

2 moles of acetylene reacts with 5 moles of oxygen.

Then 37 moles of acetylene will react with :

$(5)/(2)* 37.0 mol=92.5 moles$ of oxygen gas.

But only 81 moles of oxygen gas is present.

Then 81.0 moles of oxygen gas will react with:

$(2)/(5)* 81.0 mol=32.4 moles$ of acetylene.

And still acetylene will remain after.

So, from the above calculation we cans see that oxygen is present in limiting amount which will limit the reaction.Hence, the limiting reactant of this reaction is oxygen.

The pressure the gas exert the walls of the container will decrease because the gas particles hit the wall of the container

Answers

The statement is false. The pressure of a gas do not decrease as the gas molecules hit the walls of the container. According to the Kinetic Molecular Theory, collisions of the gas molecules or with the walls of the container are perfectly elastic. This means that energy is not lost as the molecules collide with each other or with the walls of the container.

The temperature at the point of intercept of the plotted data with the Temperature axis is:600°C
-273°C
-160°C
50°C

Answers

Answer: The temperature at the point of intercept is -273°C.

Explanation: Intercept is a point on a graph which crosses the x and y axes.

Here, The X-axis represents Temperature in °C and Y-axis represents the Volume in mL.

On X-axis, the major division is 100 and minor division is 10. The slope intercepts the X-axis at third minor division from the origin. Hence, the temperature of intercept corresponds to -273°C.

An axis is a line of numbers in a graph. The intercept is where a line of data and axis intersect, which if you look at the purple line and the temp. axis, is around -273 C.

How many neutrons does an atom of
Copper have in its nucleus?

Answers

answer:34.55
explanation:number of neutrons=mass number-atomic number
the mass number for copper is 63.55 so you do 63.55-29 (29 is the atomic number) and you would get 34.55

True or false during decomposition nitrogen gas is changed into nitrogen compounds

Answers

I believe this is true

What is the melting point of a 3L aqueous solution that contains 100g of MgCl2? kf H2O=1.86 rhoH2O=1gmL

Answers

Answer:

Melting point of aqueous solution = -10.32 °C

Explanation:

$\Delta T_f=i * k_f * m$

Where,

ΔT_f = Depression in freezing point

k_f = molal depression constant

m = molality

Formula for the calculation of molality is as follows:

$m=(Mass\ of\ solute\ (kg))/(molecular\ mass\ of\ solute * mass\ of\ solvent)$

density of water = 1 g/mL

density = mass/volume

Therefore,

mass = density × volume

volume = 3 L = 3000 mL

Mass of water = 1 g/mL × 3000 mL

= 3000 g

$Molality(m)=(100*1000)/(18* 3000) \n=1.85\ m$

van't Hoff factor (i) for MgCl2 = 3

Substitute the values in the equation (1) to calculate depression in freezing point as follows:

$\Delta T_f=i * k_f * m\n=3* 1.86 * 1.85\n=10.32\ °C$

Melting point of aqueous solution = 0 °C - 10.32 °C

= -10.32 °C

Answer:

The melting point of the solution is - 1.953 °C

Explanation:

In an ideal solution, the freezing point depression is computed as follows:

$ΔT_f = k_f * b * i$

where:

$ΔT_f$ is the freezing-point depression

$k_f$ is the cryoscopic constant, in this case is equal to 1.86

b is the molality of the solution

i is the van't Hoff factor, number of ion particles per individual molecule of solute, in this case is equal to 3

Molality is defined as follows:

b = moles of solute/kg of solvent

Moles of solute is calculated as follows:

moles of solute = mass of solute/molecular weight of solute

In this case there are 100 g of solute and its molecular weight is 35.5*2 + 24 = 95 g/mole. So, the moles are:

moles of solute = 100 g/(95 g/mol) = 1.05 moles

The mass of solvent is computed as follows:

mass of solvent = density of solvent * Volume of solvent

Replacing with the data of the problem we get:

mass of solvent = 1 kg/L*3 L = 3 kg

Finally, the molality of the solution is:

b = 1.05/3 = 0.35 mol/kg

Then, the freezing-point depression is:

$ΔT_f = 1.86 * 0.35 * 3$

$ΔT_f = 1.953 C$

The freezing-point depression is the difference between the melting point of the pure solvent (here water) and the melting point of the solution. We know that the the melting point of water is 0 °C, then:

melting point of water - melting point of the solution = 1.953 °C

melting point of the solution = 0 °C - 1.953 °C = - 1.953 °C

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