True or false during decomposition nitrogen gas is changed into nitrogen compounds

Answers

Answer 1

Answer: I believe this is true

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Which is the molar mass of BF3?10.81 g/mol
29.81 g/mol
48.81 g/mol
67.81 g/mol

Answers

The molar mass of BF3 is 67.81 g/mol

Explanation

Molar mass is the mass of all atoms in a molecule in gram per mole.
molar mass of a molecule is calculated by adding atomic mass of constituent atom

use the periodic table to determine the atomic mass of each element in the molecule.

that is;

atomic mass of B = 10.81 g/mol

atomic mass of F = 19 g/mol

since there 3 atoms of F in BF3 the atomic massof F in BF3= 3 x19 = 57 g/mol

total molar mass of BF3 = 10.81 g/mol + 57 g/mol = 67.81 g/mol

67.81 g/mol is the molar mass of BF $_3$ . Therefore, the correct option is option D among all the given options.

The ratio among the mass with the quantity of substance (measured within moles) in any sample of a compound of chemicals is known as the molar mass (M) in chemistry. The molar mass of a material is a bulk attribute rather than a molecular one. The compound's molecular weight is an average over numerous samples, which frequently have different masses because of isotopes. A terrestrial average or a function of the relative proportion of the isotopes of the component atoms on Earth, the molar mass is most frequently calculated using the standard atomic weights.

atomic mass of B = 10.81 g/mol

atomic mass of F = 19 g/mol

atomic massof F in BF $_3$ = 3 x19 = 57 g/mol

total molar mass of BF $_3$ = 10.81 g/mol + 57 g/mol = 67.81 g/mol

Therefore, the correct option is option D.

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Enter the appropriate symbol for an isotope of calcium-42 corresponding to the isotope notation AZX.Express your answer as a chemical symbol using isotope notation.

40
20Ca

Answers

Answer is ₂₀⁴²Ca.

In AZX notation
A - Represents the mass number of atom.
Mass number = number ofprotons + number of neutrons.
It is shown atthe above of the left side of theatom.
Here it is 42.

  Z - Represents the atomic number.
  Atomic number = number of protons.
  It is shown at the bottom line of the left side of the atom.
  Here it is 20.

X - Represents the symbol of the atom.
    Here X is Ca.

The symbol for an isotope of Calcium-42 corresponding to the isotope notation $\rm _A^ZX$ is $\rm _(20)^(42)Ca.$

Isotopes are atoms of the same element that have the same number of protons (atomic number) but different numbers of neutrons (mass number).

In case of Calcium-42,

The chemical symbol for calcium (X) is Ca.

The mass number (A) of the isotope is 42, which is the sum of the number of protons and neutrons in the nucleus of the atom.
The atomic number (Z) of calcium is 20, which is the number of protons in the nucleus of the atom.

Therefore, the chemical symbol for the isotope Calcium-42 is $\rm _(20)^(42)Ca.$

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What is the molecular shape of hydrogen sulphide molecule, H₂S?

Answers

the shape would be bent

How many moles of NO3 are there in 6.2g?

Answers

Answer : The number of moles of $NO_3$ is, 0.1 moles

Solution : Given,

Mass of $NO_3$ = 6.2 g

Molar mass of $NO_3$ = 62 g/mole

Now we have to calculate the moles of $NO_3$ .

$\text{Moles of }NO_3=\frac{\text{Mass of }NO_3}{\text{Molar mass of }NO_3}=(6.2g)/(62g/mole)=0.1moles$

Therefore, the number of moles of $NO_3$ present in 6.2 g is, 0.1 moles

6.2 divided by the mass number of NO3 is 0.1 moles. Anytime your trying to find the moles of something you divide it by the mass number of your combined elements.

The characteristic odor of pineapple is due to ethyl butyrate, a compound containing carbon, hydrogen, and oxygen. combustion of 3.61 mg of ethyl butyrate produces 8.22 mg of co2 and 3.35 mg of h2o. what is the empirical formula of the compound

Answers

Answer:

Empirical Formula = C₃H₆O₁

Solution:

Data Given:

Mass of Ethyl Butyrate = 3.61 mg = 0.00361 g

Mass of CO₂ = 8.22 mg = 0.00822 g

Mass of H₂O = 3.35 mg = 0.00335 g

Step 1: Calculate %age of Elements as;

%C = (mass of CO₂ ÷ Mass of sample) × (12 ÷ 44) × 100

%C = (0.00822 ÷ 0.00361) × (12 ÷ 44) × 100

%C = (2.277) × (12 ÷ 44) × 100

%C = 2.277 × 0.2727 × 100

%C = 62.09 %

%H = (mass of H₂O ÷ Mass of sample) × (2.02 ÷ 18.02) × 100

%H = (0.00335 ÷ 0.00361) × (2.02 ÷ 18.02) × 100

%H = (0.9279) × (2.02 ÷ 18.02) × 100

%H = 0.9279 × 0.1120 × 100

%H = 10.39 %

%O = 100% - (%C + %H)

%O = 100% - (62.09% + 10.39%)

%O = 100% - 72.48%

%O = 27.52 %

Step 2: Calculate Moles of each Element;

Moles of C = %C ÷ At.Mass of C

Moles of C = 62.09 ÷ 12.01

Moles of C = 5.169 mol

Moles of H = %H ÷ At.Mass of H

Moles of H = 10.39 ÷ 1.01

Moles of H = 10.287 mol

Moles of O = %O ÷ At.Mass of O

Moles of O = 27.52 ÷ 16.0

Moles of O = 1.720 mol

Step 3: Find out mole ratio and simplify it;

C H O

5.169 10.287 1.720

5.169/1.720 10.287/1.720 1.720/1.720

3.00 5.98 1

3 ≈ 6 1

Result:

Empirical Formula = C₃H₆O₁

Iron(III) oxide + carbon yields carbon monoxide and iron (write the correct formulas and then balance)

Answers

Iron(III) oxide = Fe₂O₃
Carbon = C
Carbon monoxide = CO
Iron = Fe

Fe₂O₃ + C ⇒ CO + Fe

These are the correct formulas, but the equation is not balanced. There are two Fe's on the left side, so we have to put a 2 in front of the Fe on the right. Also, there are 3 O's on the left but only 1 on the right, so we need to put a 3 in front of the CO; however, this 3 makes it 3 C's on the right, so we balance that off by putting a 3 in front of the C on the left:

Fe₂O₃ + 3C ⇒ 3CO + 2Fe

Fe(coeffecient 2)O(coeffecient 3) +3C=3CO+2Fe is the balanced equation

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