Which compound is an isomer of CH3CH2OH
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Which element has properties most similar to Bromine? A) F B) Kr C) S D) Se
(adapted)According to this passage, those who adopted this pledge believed that (1) religion had no place in national politics (2) Congress should repeal Prohibition (3) alcohol consumption was damaging to society (4) only the government can solve social problems
Describe how you would use the information depicted in the potential energy diagram below to determine the enthalphy change of the reaction and if the reaction is endothermic or exothermic?
Aqueous solutions of this ion give a reddish precipitate when excess hydroxide ion is added.(A) Cu^{2+} (B) CO₃^{2−} (C) Fe^{3+} (D) Al^{3+} (E) Pb^{2+}
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This hypothetical process would produce actinium-230.
Explanation
An alpha decay reduces the atomic number of a nucleus by two and its mass number by four.
There are two types of beta decay: beta minus β⁻ and beta plus β⁺.
The mass number of a nucleus stays the same in either process. In β⁻ decay, the atomic number increases by one. An electron e⁻ is produced. In β⁺ decay, the atomic number decreases by one. A positron e⁺ is produced. Positrons are antiparticles of electrons.
β⁻ are more common than β⁺ in decays involving uranium. Assuming that the "beta decay" here refers to β⁻ decay.
Gamma decays do not influence the atomic or mass number of a nucleus.
Uranium has an atomic number of 92. 238 is the mass number of this particular isotope. The hypothetical product would have an atomic number of 92 - 2 ⨯ 2 + 1 = 89. Actinium has atomic number 89. As a result, the product is an isotope of actinium. The mass number of this hypothetical isotope would be 238 - 2 ⨯ 4 = 230. Therefore, actinium-230 is produced.
The overall nuclear reaction would involve five different particles. On the reactant side, there is
- one uranium-238 atom.
On the product side, there are
- one actinium-230 atom,
- two alpha particles (a.k.a. helium-4 nuclei),
- one electron, and
- one gamma particle (a.k.a. photon).
Consider: what would be the products if the nucleus undergoes a β⁺ decay instead?
FeCl3
Fe2(SO4)3
PbO
PbO2
Pb3O4
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FeCl3= 162.2
Fe2(SO4)3= 354.88
PbO=223.2
PbO2 = 239.2
Pb3O4=685.6
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A star is born, it radiates energy for a long time, toward the end it expands, it may or may not explode, and then it dies. It vary in sizes, masses and surface temperature range. The colors of stars reflect their surface temperature. Their relative brightness is expressed in a scale of six magnitudes. The brightest the stars are first-magnitude stars, while the dimmest are sixth-magnitude stars.
The lower the number, the brighter the star.
For example:
Star color Surface Temperature
Blue-white around 25 000 K & higher
white around 10 000 K
yellow around 7 000 K
Red around 5 000 K & lower
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Answer: 1.848 g
Explanation: To calculate the moles, we use the equation:
....(1)
For ammonia:
Putting values in above equation, we get:
For the reaction:
By Stoichiometry of the reaction,
4 moles of ammonia combine with 3 moles of Oxygen
Thus 0.132 moles of ammonia will combine with= of oxygen
Thus ammonia is the limiting reagent as it limits the formation of product.
4 moles of ammonia produces 2 moles of nitrogen
0.132 moles of ammonia will produce= of nitrogen
Molar mass of nitrogen = 28 g/mol
Amount of nitrogen produced=
Final answer:
In the given chemical reaction, 8.00 x 10²² molecules of ammonia would produce 37.3 grams of nitrogen gas.
Explanation:
In this chemical reaction, every 4 molecules of ammonia (NH₃) produce 2 molecules of nitrogen gas (N₂). Given you have 8.00 x 10²² molecules of ammonia, this would produce (8.00 x 10²² / 2) x 2 = 8.00 x 10²² molecules of nitrogen gas, according to the reaction stoichiometry.
One molecule of nitrogen gas (N₂) has a molar mass of 28 g/mol. To convert molecules to moles, we need Avogadro's number (6.022 x 10²³ molecules = 1 mol). So, the number of moles of nitrogen gas is (8.00 x 10²² molecules / 6.022 x 10²³ molecules/mol) = 1.33 mole.
Now, by using the molar mass of nitrogen gas, we can find the mass. So, the mass of nitrogen gas = molar mass x moles = 28 g/mol x 1.33 mol = 37.3 grams.
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