Volatile organic compounds

Answers

Answer 1

Answer:

Volatile organic compounds are compounds that easily evaporate at standard room temperature and pressure. They are considered harmful to the environment if regulations are not followed. Examples of this are:

Benzene

Ethanol

Benzopyrene

Ethenone

Acetic acid

Methane

Butane

Heptane

Pentane

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Explain how much risk you think your area has for water scarcity????

Answers

Not very much because half the time the water is purified but just normal water in my area probably has serious levels of scarcity.

Answer:

Explanation: Over pumping refers to pumping fresh water and reducing the level of an underground layer of water. In coastal areas, the lower underground layer of water is infiltrated with salt water, eventually increasing the salinity of the underground layer of water to the point that it is not drinkable. The scarcity of water in the coastal areas because the water in the coastal areas is not drinkable.

Which calculation set-up would be correct to determine the volume of concentrated hydrochloric acid (12.0 M HCl) that is required to make 500.0 milliliters of a 6.0 M HCl?

Answers

Answer : The volume of concentrated hydrochloric acid is, 0.25 liters

Explanation :

Using neutralization law,

$M_1V_1=M_2V_2$

where,

$M_1$ = molarity of concentrated hydrochloric acid = 12 M = 12 mole/L

$M_2$ = molarity of hydrochloric acid = 6 M = 6 mole/L

$V_1$ = volume of concentrated hydrochloric acid = ?

$V_2$ = volume of hydrochloric acid = 500 ml = 0.5 L

Now put all the given values in the above formula, we get the volume of concentrated hydrochloric acid.

$12mole/L* V_2=6mole/L* 0.5L$

$V_2=0.25L$

Therefore, the volume of concentrated hydrochloric acid is, 0.25 liters

M₁ *V₁ = M₂ * V₂

12.0 * V₁ = 6.0 * 500.0

12.0 V₁ = 3000

V₁ = 3000 / 12.0

V₁ = 250 mL

hope this helps!

Which formula represents a molecular compound?
(1) Kr (3) N2O4
(2) LiOH (4) NaI

Answers

N2O4 is the only option from the list that represents a molecular compound, since compounds must contain at least two different atoms, although these can be from different groups.

Answer: Option (3) is the correct answer.

Explanation:

A molecular compound is a compound in which atoms used to share electrons and thus results in the formation of covalent bonds.

For example, $N_(2)O_(4)$ is a covalent compound and hence, it is a molecular compound.

Whereas LiOH and NaI are ionic compounds as their atoms has transferred electrons.

Therefore, we can conclude that out of the given options, $N_(2)O_(4)$ is the formula which represents a molecular compound.

The standard enthalpy change for the reaction of SO3(g) with H2O(l) to yield H2SO4(aq) is ΔH∘ = -227.8 kJ . Use the following information S(s)+O2(g)→SO2(g), ΔH∘ = -296.8kJ SO2(g)+12O2(g)→SO3(g) , ΔH∘ = -98.9kJ to calculate ΔH∘f for H2SO4(aq) (in kilojoules per mole). [For H2O(l),ΔH∘f = -285.8kJ/mol].

Answers

Answer:

-909.3KJ/mole

Explanation:

The heat of reaction is accessible from the heat of formation of reactants and products using the formula below:

ΔH = Σ ΔHf products - Σ ΔHf reactants

Before we proceed, it is important to know that the enthalpy of formation of element is zero ,be it a single element or a molecule of an element.

From the reaction for the formation of sulphuric acid, we know we need to know the heat of formation of sulphur (vi) oxide and water. The examiner is quite generous and have us for water already.

Now we need to calculate for sulphur (vi) oxide. This is calculated as follows:

We first calculate for sulphur(iv)oxide. This can be obtained from the reaction between sulphur and oxygen. The calculation goes thus:

ΔH = Σ ΔHf products - Σ ΔHf reactants

ΔH = [ 1 mole suphur(iv) oxide × x] - [ (1 mole of elemental sulphur × 0) + (1 mole of elemental oxygen × 0]

We were already told this is equal to -296.8KJ. Hence the heat of formation of sulphur(iv) oxide is -296.8KJ.

We then proceed to the second stage.

Now, here we have 1 mole sulphur (iv) oxide reacting with 0.5 mole oxygen molecule.

We go again :

ΔH = Σ ΔHf products - Σ ΔHf reactants

ΔH = [ 1 mole of sulphur (vi) oxide × y] - [ (1 mole of sulphur (iv) oxide × -296.8) + (0.5 mole of oxygen × 0)].

We already know that the ΔH here equals -98.9KJ.

Hence, -98.9 = y + 296.8

y = -296.8KJ - 98.9KJ = -395.7KJ

We now proceed to the final part of the calculation which ironically comes first in the series of sentences.

Now, we want to calculate the standard heat of formation for sulphuric acid. From the reaction, we can see that one mole of sulphur (vi) oxide, reacted with one mole of water to yield one mole of sulphuric acid.

Mathematically, we go again :

ΔH = Σ ΔHf products - Σ ΔHf reactants

ΔH = [ 1 mole of sulphuric acid × z] - [( 1 mole of sulphur vi oxide × -395.7) + ( 1 mole of water × -285.8)].

Now, we know that the ΔH for this particular reaction is -227.8KJ

We then proceed to to open the bracket.

-227.8 = z - (-395.7 - 285.8)

-227.8 = z - ( -681.5)

-227.8 = z + 681.5

z = -227.8-681.5 = -909.3KJ

Hence, ΔH∘f for sulphuric acid is -909.3KJ/mol

In the reaction C + 02 - CO2, 18 g of carbon react with oxygen to produce 72 g of carbon dioxide. What mass of oxygen would be needed in the reaction? O 18 g O 54 g O 72 g 0 90 g

Answers

Mass of oxygen : 54 g

Further explanation

Conservation of mass applies to a closed system, where the masses before and after the reaction are the same

Reaction

$\tt C+O_2\rightarrow CO_2$

mass before reaction = mass after reaction

mass C + mass O₂= mass CO₂

$\tt 18~g+mass~O_2=72~g\n\nmass~O_2=72-18=\boxed{\bold{54~g}}$

A student views four models showing magnified views of the phases of matter.What question will best help the student determine which model is plasma?
A
Which model is composed of rapidly moving particles?
B.
Which model is composed of particles vibrating in place?
C
Which model is composed of electrically charged particles?
Which model is composed of particles sliding past each other?

Answers

Answer:

C Which model is composed of electrically charged particles?

Explanation:

The best question to resolve and determine the model which is plasma is to find one that is composed of electrically charged particles.

Plasma is one of the states of matter which is characterized by ions and other charged particles.

Matter is anything that has weight and occupies space.

There are four known states of matter which are:

Solid
Liquid
Gas
Plasma

Plasma is the only state of matter made up of charged particles.

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