What is the pOH of a 7.9 x 10 ^-4 M OH- solution?

pOH= ?

Answers

Answer 1
Answer:

Answer: pOH of the given hydroxide ion concentration is 3.10

Explanation:

pOH is defined as the negative logarithm of hydroxide ion concentration. It is represented by the equation:

pOH=-\log[OH^-]

We are given:

Hydroxide ion concentration, [OH^-]=7.9* 10^(-4)M

Putting values in above equation, we get:

pOH=-\log(7.9* 10^(-4))\n\npOH=3.10

Hence, pOH of the given hydroxide ion concentration is 3.10

Answer 2
Answer:

pOH is defined as -log([OH-]).

pOH = -log([OH-]) = -log(7.9 * 10^-4) = 3.1

Hope this helps!


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I have a cup of hot coffee at 140 oC but I want to cool it to 110 oC. My cup holds about 0.3 kg of coffee. Fortunately, I have a bunch of aluminum cubes in the freezer that I can drop into my hot coffee to cool it down. If each aluminum cube has a mass of 1 g (not 1 kg!) and my freezer keeps its contents at a temperature of –10 oC, how many cubes do I have to drop into my coffee? The specific heat of water is around 4000 joules/kg/oC and aluminum is about 900 joules/kg/oC. (Pick the answer closest to the true value and ignore any thermal losses to surroundings.)

A. 200
B. 330
C. 400
D. 110
E. 88

Answers

Answer:

The correct answer is option B.

Explanation:

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1* c_1* (T_f-T_1)=-m_2* c_2* (T_f-T_2)

where,

C_1 = specific heat of metal = 900 J/kg^oC

C_2 = specific heat of coffee= 4000 J/kg^oC

m_1 = mass of metal = x

m_2 = mass of coffee = 0.3 kg

T_f = final temperature of aluminum metal= 110^oC

T_1 = initial temperature of aluminum metal = -10^oC

T_2 = initial temperature of coffee= 140^oC

Now put all the given values in the above formula, we get

x* 900 J/kg^oC* (110-(-10))^oC=-(0.3 kg* 4000 J/kg^oC* (110-140)^oC

x=0.333 kg

Mass of aluminum cubes = 0.3333 kg = 333.3 g

If mass of 1 cube is 1 gram, then numbers of cubes in 333.3 grams will be:

=(333.3 g)/(1 g)=333.3\approx 330

330 cubes of aluminum cubes will be required.

Grunge is a rock style from Detroit. True False

Answers

Answer:

FALSE

Explanation:

Grunge refers to the genre of rock music and the fashion inspired by it. It originated in the mid-1980s in Seattle, Washington State.

Grunge was described as the fusion of punk rock and heavy metal.

This genre of music became popular in the early mid-1990s and included lyrics based on the theme of emotional and social alienation, betrayal, abuse, trauma etc.    

The amount of heat required to melt 2 lbs of ice is twice the amount of heat required to melt 1 ib of ice. is this observation a macroscopic or microscopic description of chemical behavior? Explain your answer.

Answers

The observation in this instance relates to the quantity of heat needed to melt ice, and it is expressed in terms of weights (2 lbs and 1 lb) and a comparison (twice the amount).

Without going into detail into the different molecules or their interactions, it concentrates on the general behaviour and characteristics of the substance (ice) as a whole.

A microscopic description, on the other hand, would describe the behaviour in terms of the molecular or atomic interactions that take place at the particle level. It would go into ideas such as the amount of heat required to dissolve the intermolecular interactions between water molecules.

Therefore, the observation regarding how much heat is needed to melt ice is a macroscopic description since it ignores the underlying molecular interactions in favour of the substance's general behaviour and qualities.        

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The observation that melting 2 lbs of ice requires twice the heat of melting 1 lb is a macroscopic description, focusing on observable properties and behavior without exploring microscopic details.

This observation is a macroscopic description of chemical behavior. Macroscopic descriptions involve the properties and behavior of substances on a large scale that can be observed directly, without delving into the molecular or atomic details. In this case, the statement refers to the amount of heat required to melt a certain quantity of ice, and it is expressed in terms of macroscopic, measurable quantities (pounds of ice and the associated heat).

The macroscopic observation does not provide insight into the molecular or atomic interactions within the ice but rather focuses on the overall behavior of the substance. The concept that the amount of heat required to melt 2 lbs of ice is twice that needed for 1 lb of ice is a statement about the material's behavior at a larger scale.

This observation aligns with the macroscopic principles of heat and phase transitions, where the heat required for a phase change is directly proportional to the mass of the substance undergoing the transition. The macroscopic perspective is concerned with observable properties and measurements, making it a practical and accessible way to describe chemical behavior without delving into microscopic details.

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Which step would help a student find the molecular formula of a compound from the empirical formula? Multiply the subscripts of the empirical formula by the value of the ratio of the molar mass of the compound to the empirical molar mass of the compound. Subtract the value of the ratio of the molar mass of the compound to the empirical molar mass of the compound from the subscripts of the empirical formula. Divide the subscripts of the empirical formula by the value of the ratio of the molar mass of the compound to the empirical molar mass of the compound. Add the value of the ratio of the molar mass of the compound to the empirical molar mass of the compound to the subscripts of the empirical formula..

Answers

Answer:

Multiply the subscripts of the empirical formula by the value of the ratio of the molar mass of the compound to the empirical molar mass of the compound.

Explanation:

got it right on edge 2020 :)

Answer:

Multiply the subscripts of the empirical formula by the value of the ratio of the molar mass of the compound to the empirical molar mass of the compound.

Explanation:

Choose All correct statements about the crystal structure of materials Select one or more: a. Isotopic properties are the characteristics of polycrystalline materials. b. The crystal structure of metals is very complicated. c. Presence of various elements in the metallic crystal structures is the main contributor to its densely packed structure. d. Metal's crystalline structure tends to be densely packed. e. Anisotropic materials have their properties varying with the direction of measurement. f. The directional characteristic of metallic bonds is one of the reason for the densely packed crystalline structure of metals.

Answers

Answer:

c. Presence of various elements in the metallic crystal structures is the main contributor to its densely packed structure

d. Metal's crystalline structure tends to be densely packed.

e. Anisotropic materials have their properties varying with the direction of measurement.

Explanation:

a. Isotopic properties are the characteristics of polycrystalline materials.

False because crystalline solids are anisotropic in nature because some properties like refractive index change in different direction in crystalline solids .

b. The crystal structure of metals is very complicated

false - crystalline solids have fixed and ordered pattern. so it has simple structure .

c. false - there is only one element . packed structure is because of short bond length .

d.  true - metals are closely packed and in order manner

e.  true - they have different properties in all direction like electrical conductivity and refractive index

f.  False - metallic bonds are indirectional in nature .

An aqueous CsCl solution is 8.00 wt% CsCl and has a density of 1.0643 g/mL at 20°C. What is the boiling point of this solution? Kb = 0.51°C/m for water. Enter your answer with 2 decimal places and no units.

Answers

Answer: The boiling point of solution is 100.53

Explanation:

We are given:

8.00 wt % of CsCl

This means that 8.00 grams of CsCl is present in 100 grams of solution

Mass of solvent = (100 - 8) g = 92 grams

The equation used to calculate elevation in boiling point follows:

\Delta T_b=\text{Boiling point of solution}-\text{Boiling point of pure solution}

To calculate the elevation in boiling point, we use the equation:

\Delta T_b=iK_bm

Or,

\text{Boiling point of solution}-\text{Boiling point of pure solution}=i* K_b* \frac{m_(solute)* 1000}{M_(solute)* W_(solvent)\text{ (in grams)}}

where,

Boiling point of pure solution = 100°C

i = Vant hoff factor = 2 (For CsCl)

K_b = molal boiling point elevation constant = 0.51°C/m

m_(solute) = Given mass of solute (CsCl) = 8.00 g

M_(solute) = Molar mass of solute (CsCl) = 168.4  g/mol

W_(solvent) = Mass of solvent (water) = 92 g

Putting values in above equation, we get:

\text{Boiling point of solution}-100=2* 0.51^oC/m* (8.00* 1000)/(168.4g/mol* 92)\n\n\text{Boiling point of solution}=100.53^oC

Hence, the boiling point of solution is 100.53

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