At which temperature and pressure would a sample of helium behave most like an ideal gas?
Answers
The Helium gas tends to behave as an ideal gas at 0temperature and 1 atm pressure.
By applying the real gas law to the gases at the high temperature,m the gases start to behave as the ideal gas.
The gas behaves at the ideal gas when the van der wall force between the gases has been the lowest and they tend to react less with the other atoms.
The Helium gas has the maximum tendency to behave as an ideal gas, as it has been the single atomic gas. Being single atomic, the gas tends to exhibit less forces, and the complete octet helps the gas to reactless with the other atoms.
Because of the characteristics, Helium acts as an ideal gas at STP.
Thus the Helium gas tends to behave as an ideal gas at 0temperature and 1 atm pressure.
For more information about the ideal gas, refer to the link:
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There are two alloys, one is 1 part silver and 5 parts copper and the other 3 parts silver and 1 part copper are mixed to form 350 pounds of an alloy that is equal in silver and copper content.How many pounds of each should be used?
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Mg + Cl2 Mg2+ + 2Clmc005-2
Answers
Answer:
Mg+Cl2 = Mg2+2Cl
Explanation:
Firstly balance the equation
2Mg+Cl2=Mg2+2Cl
the oxidized substance=Cl2
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The balanced chemical reaction will be:
C3H8 + 5O2 = 3CO2 +4H2O
We are given the amount of oxygen gas to burn the propane gas. This will be our starting point.
34.0 L O2 ( 1 mol O2 / 22.4 L O2 ) (1 mol C3H8 / 5 mol O2 ) ( 22.4 L C3H8 / 1 mol C3H8) = 6.8 L C3H8
Answers
Answer: False
Explanation:
Metal oxides that dissolve in water, react with water to form basic solutions.
Nonmetal oxides react with water to form acidic solutions.
Final answer:
False. The nature of the solution actually depends on the type of metal oxide. Not all metal oxides will make water acidic when mixed.
Explanation:
The statement that mixing metal oxide with water will result in an acidic solution is generally false.
Actually, the nature of the solution (acidic, basic, or neutral) after mixing metal oxide with water depends on the type of metal oxide. Some metal oxides, particularly those of alkali metals and alkaline earth metals (Group 1 and 2 in the Periodic Table), form basic solutions when dissolved in water. For instance, sodium oxide or magnesium oxide will react with water to form their respective hydroxides, which are basic in nature.
However, certain metal oxides like aluminum oxide or zinc oxide may react with water to form amphoteric solutions (can behave as both acids and bases).
Thus, not all metal oxides will make the water acidic when mixed.
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Answers
Given:
Height of the mercury manometer, h = 23.6 cm
To determine:
The pressure of gas trapped in the closed-tube mercury manometer
Explanation:
In the case of a closed tube mercury manometer, the pressure of the gas is equal to the height difference of the mercury levels in the two arms of the manometer.
i.e. P(gas) = P(h)
in this case, h = 23.6 cm = 236 mm
i.e. Pgas = 236 mmHg
Since, 1 atm = 760 mmHg
The corresponding Pgas(atm) = 236 mmHg * 1 atm/760 mmHg = 0.311 atm
Ans: The pressure of the gas is 0.311 atm
Final answer:
The pressure of the gas in the closed-tube mercury manometer is approximately 0.31 atmospheres, calculated by converting the height of the mercury column into atmospheres.
Explanation:
The pressure of a gas in a closed-tube mercury manometer can be determined using the known height of the mercury and the concept of hydrostatic pressure. Firstly, it's important to note that the pressure on either side of the mercury column in the tube is equal. The pressure of the gas is the same as the hydrostatic pressure due to a column of mercury of the given height in the tube.
In the reference solution provided, the height is given as 26.4 cm. However, according to the question, the height is provided as 23.6 cm. Assuming the height is indeed 23.6 cm, we need to convert this to a pressure value. It is known that 1 atm at sea level is equivalent to a column of mercury that is about 760 mm high.
Therefore, we can convert the height of 23.6 cm or 236 mm into atmospheres. To do this, divide 236 mm by 760 mm to find the pressure in atmospheres. Therefore, the pressure of the gas in the manometer is approximately 0.31 atmospheres.
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