What is the coefficient monomial of 5pk
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I need help my teacher's note didn't help at all please
Write the equation for each transformation of f(x)= |x| described below.a. translate left 9 units, stretch vertically by a factor of 5, and translate down 23 units. b. translate left 12 units, stretch horizontally by a factor of 4, and reflect over the x-axis. need steps don't understand how to do!
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This is a little bit weird, but it's not hard if you just
do it one step at a time.
Here's the important part that you need to know
in order to solve this problem:
All four sides of a square are equal.
Got that ? Good.
Here we go.
-- First, take the left and right sides.
They must be equal, so
2y - 5 = y - 1
Add 5 to each side: 2y = y + 4
Subtract 'y' from each side: y = 4 .
The left side is y-1 = 3
The right side is 2y-5 = 2(4) - 5
= 8 - 5
= 3 .
Good ! We have the left and right sides equal.
Do we really need to do the other two sides ?
They told us it's a square, so can't we just say
the top and bottom are also 3 ?
Well, maybe. But maybe they're trying to trick us,
and the top and bottom aren't really 3 . I think
we ought to check it out. It's more good math practice.
-- Take the bottom side ... it's 3y-9 .
But you know what 'y' is !
We just calculated that y=4,
so
3y - 9 = 3(4) - 9 = 12 - 9 = 3 .
Great ! The bottom side is 3 .
2.- the equation has a rate of change of 4 and crosses y intercept at -5
3._ none of the above
4._ all the above
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Answer:
hello
Step-by-step explanation:
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Answer:
14
Step-by-step explanation:
To calculate the greatest common factor (GCF) of 28 and 42, we need to factor each number (factors of 28 = 1, 2, 4, 7, 14, 28; factors of 42 = 1, 2, 3, 6, 7, 14, 21, 42) and choose the greatest factor that exactly divides both 28 and 42, i.e., 14.
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Answer:
The probability that the sum of the numbers rolled is either a multiple of 3 or 4 is 5/9.
Step-by-step explanation:
As given: Franklin rolls a pair of six-sided fair dice with sides numbered 1 through 6.
A pair of dice has 36 possible outcomes.
The probability that the sum of the numbers rolled is either a multiple of 3 or 4 is or
Let 'A' and 'B' be the events that the sum of the numbers rolled is a multiple of 3 and a multiple of 4 respectively.
Set for A = {(1, 2), (1, 5), (2, 1), (2, 4), (3, 3), (3, 6), (4, 2), (4, 5), (5, 1), (5, 4), (6, 3), (6, 6)}, and set for B = {(1, 3), (2, 2), (2, 6), (3, 1), (3, 5), (4, 4), (5, 3), (6, 2), (6, 6)}.
So, together they form 20 sets ((6,6) is repeating so take once)
Hence, we get 20/36=5/9
3 out of 6
1/2
probablity is 0.5