If the Ka of a monoprotic weak acid is 5.4 × 10-6, what is the pH of a 0.25 M solution of this acid?

Answers

Answer 1
Answer: The first step is to write the balanced equation of the dissociation of the monoprotic weak acid. This can be assumed to have 1:1 stoichiometric relationships, so the equation and ICE chart are given by:

                          HA ---> H^+ + A^-
initial                 0.25       0          0
change               -x         x           x
equilibrium    0.25-x       x           x

This gives an expression for Ka given by:

Ka = (x)^2/(0.25-x) = 5.4x10^-6
x = 1.159x10^-3 = [H+] = [A-]

pH = -log[H+] = -log[1.159x10^-3] = 2.936

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Which atom in the ground state requires the least amount of energy to remove its valence electron?(1) lithium atom (2) potassium atom (3) rubidium atom (4) sodium atom

Answers

Answer:

                   Rubidium (Rb)

Explanation:

                           Ionization Energy is defined as, "the minimum energy required to knock out or remove the valence electron from valence shell of an atom".

Trends in Periodic table:

               Along Periods:

                                        Ionization Energy increases from left to right along the periods because moving from left to right in the same period the number of protons (atomic number) increases but the number of shells remain constant hence, resulting in strong nuclear interactions and electrons are more attracted to nucleus hence, requires more energy to knock them out.

              Along Groups:

                                        Ionization energy decreases from top to bottom along the groups because the number of shells increases and the distance between nucleus and valence electrons also increases along with increase in shielding effect provided by core electrons. Therefore, the valence electrons experience less nuclear attraction and are easily removed.

Conclusion:

                   Given elements belong to same group hence, Rubidium present at the bottom of remaining elements will have least ionization energy due to facts explained in trends of groups above.

How much heat energy is required to raise the temperature of 0.368 kg of copper from 23.0 ∘C to 60.0 ∘C? The specific heat of copper is 0.0920 cal/(g⋅∘C)

Answers

23.0 + 60.0 = 83.0° C heat energy is required to raise

What is the Hf for this reaction? 16CO2(g) + 18H2O(g) 2C8H18(l) + 25O2(g)

Answers

To solve this we must be knowing each and every concept related to Enthalpy. Therefore, 10,148KJ/mol is the ΔH for formation for the reaction 16CO_2(g) + 18H_2O(g) \rightarrow 2C_8H_(18)(l) + 25O_2(g)

What is Enthalpy?

Enthalpy term is basically used in thermodynamics to show the overall energy that a matter have. Mathematically, Enthalpy is directly proportional to specific heat capacity of a substances. Specific heat capacity of a substance is the amount of heat required to raise the temperature by one degree Celsius of one gram of a substance.

The balanced equation for the given chemical reaction can be given as

16CO_2(g) + 18H_2O(g) \rightarrow 2C_8H_(18)(l) + 25O_2(g)

ΔH for formation= 10,148KJ/mol

Therefore, 10,148KJ/mol is the ΔH for formation for the reaction 16CO_2(g) + 18H_2O(g) \rightarrow 2C_8H_(18)(l) + 25O_2(g)

To know more about enthalpy, here:

brainly.com/question/24170335

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Answer:

10,148

Explanation:

An urban area is characterized by _____.A) a dense human population
B)farm land
C)highways
D)public transportation

Answers

Answer: Option (A) is the correct answer.

Explanation:

An urban area is an area which is developed and it is a place where people can get almost all the things of their need easily.

Therefore, more an more people would like to live in an urban area as there will be more resources which can make people's work easy.

Hence, we can conclude that out of the given options an urban area is characterized by a dense human population.

A) A dense human population

Calculate the concentration (in molarity) of NaOH solution if 25.0mL of the solution are needed to neutralize 17.4 mL of a 0.132M HCL solution

Answers

Given:

25.0mL NaOH
17.4 mL of a 0.132M HCL

Required:

molarity of NaOH


Solution:

M1V1 = M2V2

(25.0mL) M1 = (0.132 M HCl)( 17.4 mL)

M1 = 0.092 M NaOH

V1 = 0.5 liters

Glucose is an important sugar in many biochemical reactions what is the molarity of a solution that contains 500 grams of glucose (molecular weight= 180.16 g/mol) in 7.02 liters of solutiona. .56M
b. .78 M
c. 3.85 M
b. 4.98 M

Answers

Answer:

The correct answer is c.

Explanation:

First, look for the same problem to verify that the correct volume is 0.702 L.

Now we must calculate the amount of glucose moles (n) in the 500g:

n = (500 g)/(180 (g)/(mol) )

n = 2,7 mol

Molarity is given by moles of compound per liter. In this way, we calculate the molarity (M) as:

M = (2,7 mol)/(0,702 L)

M = 3,85(mol)/(L)

Have a nice day!

Number of moles :

500 / 180.16 => 2.775 moles

Volume = 0.72 L

M = n / V

M = 2.775 / 0.72

M = 3.85 M

hope this helps!