A solution is prepared by adding .8 g of iron sulfate to 450mL of watercalculate the effective molality of the solution'

Answers

Answer 1

Answer: Molar mass FeSO₄ =151.908 g/mol

Volume = 450 mL / 1000 = 0.45 L

1 mol ----------- 151.908 g
n mol ----------- 0.8 g

n = 0.8 * 1 / 151.908

n = 0.00526 moles

M = n / V

M = 0.00526 / 0.45

M = 0.01168 mol/L⁻¹

hope this helps!

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What type of compound is always an electrolyte?a. polar covalent b. nonpolar covalent c. ionic d. network solid

How do physical changes and chemical changes differ and how are they alike please at least 5 provide examples each for a brainliest!

Answers

Answer:

Physical changes only change the appearance of a substance, not its chemical composition. Chemical changes cause a substance to change into an entirely substance with a new chemical formula. Chemical changes are also known as chemical reactions.

How are physical and chemical changes similar and different? (compare and contrast) (Physical and chemical changes are similar because matter experiences a change in state, Physical changes are different because matter remains the same substance, just in a different state, whereas chemical changes change the matter

Examples of chemical changes are burning, cooking, rusting, and rotting. Examples of physical changes are boiling, melting, freezing, and shredding. Often, physical changes can be undone, if energy is input. The only way to reverse a chemical change is via another chemical changes.

Explanation:

From where does the nitrogen in the nitrogen cycle originate?a. root nodules of legumes
b. the atmosphere
c. decomposers
d. nitrifying bacteria

Answers

The correct answer is B. The nitrogen in the nitrogen cycle originate from the atmosphere. It forms approximately 78% of the Earth's atmosphere. However, this form is not usable because it is in its most stable form therefore unreactive. This nitrogen gas needs to be converted into nitrate compound for it to be usable. Then, the nitrogen cycle starts.

Answer:

B) the atmosphere

Explanation:

If 20.0 ml of glacial acetic acid (pure hc2h3o2 is diluted to 1.70 l with water, what is the ph of the resulting solution? the density of glacial acetic acid is 1.05 g/ml.

Answers

The pH of the resulting solution is 2.72

Data;

volume of acid = 20mL
density of acid = 1.05 g/ml
mass = 1.05 * 20 = 21g

pH of a solution

The number of moles of acetic acid is

$n = 21/60 = 0.333 moles$

The concentration of acetic acid in 1.7L is

$c = (0.333)/(1.7) = 0.196M$

The equation for dissociation is

$CH_3COOH + H_2O \to CH_3COO^- +H_3O^+$

The Ka of this reaction is

$K_a = ([CH_3COO^-][H_3O^+)/([CH_3COOH)$

The Ka of acetic acid = 1.8*10^-5

$1.8*10^-^5 = (x*x)/(0.196) \nx = 0.187*10^-^2M\n$

The concentration of hydrogen ion is

$[H^+] = 1.87*10^-^3M$

The pH of this solution is

$pH = -log[H^+]\npH = -log(1.87*10^-^3)\npH = 2.72$

The pH of the resulting solution is 2.72

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Given:
20.0 ml of glacial acetic acid
1.70 L with water
density of the glacial acetic acid is 1.05 g/ml ; Ka = 1.8 x 10⁻⁵

1) find out how many grams of HC2H3O2 is in this glacial matter. It says here it has a density of 1.05g/mL.
So we find the grams from that => 1.05 g/mL * (20.0 mL) = 21 grams of HC2H3O2.
Convert this to moles => 21 grams (1 mol / 60 g) = 0.35 mol HC2H3O2

We then get the Ka formula from that equation so it is
Ka = [H3O+] [C2H3O2] / [HC2H3O2] (Remember H2O has an activity of 1 so we exclude it)

We know the concentration of HC2H3O2 because we have moles of HC2H3O2
Finding concentration of HC2H3O2 => 0.35 mol HC2H3O2/1.70 L = 0.20588 M - initial concentration

1.8 x 10⁻⁵ = (x) (x) / (0.20588 M - x)
1.8 X 10⁻⁵ (0.20588 M) = x²
3.70584⁻ x 10⁻⁶ = x²
x = 1.9251 x 10⁻³

pH = -log (H₃O⁺) = - log (1.9251 x 10⁻³) = -(-2.7156) = 2.7156

pH of the resulting solution is 2.7156

Describe 3 ways that you could change the rate of the reaction based on principles that effect rates of reactions.

Answers

Three ways to change the rate of a reaction are by increasing the concentration of reactants, changing the temperature, and adding a catalyst.

Three ways to change the rate of a reaction:

Increasing the concentration of reactants: This increases the collision frequency between particles, leading to a higher reaction rate. For example, in the reaction between hydrogen and iodine to form hydrogen iodide, increasing the concentration of hydrogen and iodine will speed up the reaction.
Changing the temperature: Higher temperatures increase the kinetic energy of particles, making them move faster and collide more frequently. This results in a faster reaction rate. Using an example, raising the temperature of the reaction between magnesium and hydrochloric acid will speed up the rate of reaction.
Adding a catalyst: Catalysts are substances that speed up reactions by providing an alternative reaction pathway with lower activation energy. For instance, adding an enzyme catalyst like amylase to the reaction between starch and iodine will increase the reaction rate.

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The three main ways to change the rate of reaction based on principles that affect rates of reactions are concentration, temperature, and catalysts .let us describe them one by one further.

Three ways to change the rate of a chemical reaction are:

Concentration Change: Increasing the concentration of reactants usually speeds up the reaction. This is due to more frequent collisions between particles, increasing the likelihood of successful collisions leading to product formation.
Temperature Change: Raising the temperature accelerates reactions by providing more energy to reactant particles, increasing their kinetic energy, and promoting successful collisions.
Catalysts: Adding a catalyst lowers the activation energy required for the reaction, making it easier for reactants to transform into products. Catalysts provide an alternate reaction pathway, allowing reactions to occur at lower energy levels and faster rates.

Answers

I would go with B as more of the reactant is exposed per mol. A catalyst provides and alternate reaction path that reduces the activation energy but not necessarily exposes more of the reactant. Increasing the concentration wont increase the amount of exposed area nor will increasing the tempurature.

Give the formula for the alkane containing 100 hydrogens.

Answers

Answer: The alkane containing 100 hydrogens will be $C_(49)H_(100)$

Explanation:

Saturated hydrocarbons are defined as the hydrocarbons in which a single bond is present between carbon and carbon atoms.These are called as alkanes. The general formula for these hydrocarbons is $C_nH_(2n+2)$

As given number of hydrogen atoms is 100, therefore the value of (2n+2) = 100

2n = 98

n = 49

Thus the formula for the alkane containing 100 hydrogens will be $C_(49)H_(100)$

Final answer:

The alkane containing 100 hydrogens has the formula C49H100.

Explanation:

The formula for the alkane containing 100 hydrogens can be determined using the general formula for alkanes, which is CnH2n+2. To find the value of n, we can set up an equation:

100 = 2n + 2

Simplifying this equation, we get:

n = 49

Therefore, the formula for the alkane containing 100 hydrogens is C49H100.

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