Describe events in the formation of an evaporite?

Answers

Answer 1

Answer: * Alcohol, in function of its defined chemical, evaporates much faster than a water.

* The clothes drying on the Clothesline, the river that evaporates, a puddle of water that dry, etc.

hope this helps!

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one isotope of a metallic element has a mass number of 65 and 35 neutrons in the nucleus. the cation derived the isotope has 28 electrons. write a nuclear symbol for this element
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Why is gold preferred as a superior metal over silver and bronze?

Answers

it is value able because it does not crack while twisting; stretching...
it is important because it is inert to other elements
it is expensive because it is rare.. also mining for gold is very expensive because you have to dig about ten tons of rock or dirt...
also it does not corrode ....

Gold has a better resistance to water than bronze or silver. It doesnt corrode easily.

Compared to pure water, an aqueous solution of calcium chloride has a(1) higher boiling point and higher freezing point
(2) higher boiling point and lower freezing point
(3) lower boiling point and higher freezing point
(4) lower boiling point and lower freezing point

Answers

Answer: option (2) higher boiling point and lower freezing point.

Explanation:

Colligative properties are those properties of solution that depend on the concentraion of the solute.

Increase of boling point and depression of freezing point are two of those colligative properties.

Regarding the boiling point, as some impurities (in this case the solute calcium chloride) are present in the solvent (water) ,at the same temperature, less molecules of water will reach the surface to escape, at a given temperature. Hence, you have to increase the temperature to manage that the number of molecules and their speed increase and so all the molecules can escape fro, the liquid phase to form the gas. So, the boiling point of the water with the salt in it will be higher than the boiling point of pure water.

As for the freezing point, in a solution the particles of solute interfere with the attractive forces between the molecules of water avoiding that the solvent passes to solid state at the normal freezing point. Hence, the temperature to freeze will be lower.

if a sample of magnesium has a mass of 60 g, how many moles of magnesium does the sample contain

Answers

Answer : The moles of magnesium will be, 2.5 moles

Explanation : Given,

Mass of magnesium = 60 g

Molar mass of magnesium = 24 g/mole

Formula used :

$\text{Moles of }Mg=\frac{\text{Mass of }Mg}{\text{Molar mass of }Mg}$

Now put all the given values in this formula, we get the moles of magnesium.

$\text{Moles of }Mg=(60g)/(24g/mole)=2.5mole$

Therefore, the moles of magnesium will be, 2.5 moles

1 mole of Mg ------------ 24,3g
x moles of Mg-------------60g
x = 2,47 moles of Mg

answer: 2,47 moles of magnesium

Samarium-146 has a half-life of 103.5 million years. After 1.035 billion years, how much samarium-146 will remain from a 205-g sample?0.200 g
0.400 g
20.5 g
103 g

Answers

Answer : The correct option is, 0.200 g

Solution :

As we know that the radioactive decays follow first order kinetics.

First we have to calculate the rate constant of a samarium-146.

Formula used :

$t_(1/2)=(0.693)/(k)$

Putting value of $t_(1/2)$ in this formula, we get the rate constant.

$103.5* 10^6=(0.693)/(k)$

$k=6.6* 10^(-9)year^(-1)$

Now we have to calculate the original amount of samarium-146.

The expression for rate law for first order kinetics is given by :

$k=(2.303)/(t)\log(a)/(a-x)$

where,

k = rate constant = $6.6* 10^(-9)year^(-1)$

t = time taken for decay process = $1.035* 10^(9)years$

a = initial amount of the samarium-146 = 205 g

a - x = amount left after decay process = ?

Putting values in above equation, we get the value of initial amount of samarium-146.

$6.6* 10^(-9)=(2.303)/(1.035* 10^(9))\log(205)/(a-x)$

$a-x=0.200g$

Therefore, the amount left of the samarium-146 is, 0.200 g

Ans: 0.200 g

Given:

Half life of Sm-146 = t1/2 = 103.5 million years

Time period, t = 1.035 billion years = 1035 million years

Original mass of sample, [A]₀ = 205 g

To determine:

Amount of sample after t = 1035 million years

Explanation:

The rate of radio active decay is given as:

$A(t) = A(0)e^(-0.693t/t1/2) \n\n= 205 g * e^{(0.693*1035)/(103.5) } \n\n= 0.200 g$

Describe 3 ways abrasion occurs in nature

Answers

There are three ways of abrasion occurs in nature; the wind, waves, and gravity. Abrasion is the mechanical process of wearing away of a rock surface and the movement of the particles while transporting through the wind, waves, and gravity.

Argon-39 has a half-life of 269 years. How long will it take for 52.5 g of a 60.0 g sample to decay to its daughter isotope?

Answers

The years that will take or 52.5 g of a 60.0 g sample to decay to its daughter isotope is 807 years.

What is half-life?

Half-life is the time required to decay or undergo half the process of any element.

Given the sample is 60.0 g in which 52.5 g sample has to be decay

so, 60 - 52.5 = 7.5 g

It can be seen that it goes three half life

60 >30 >15 >7.5

Now, the half life is 269

269 × 3 = 807 years.

Thus, the years taken are 807 years.

Learn more about isotopes

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For 60.0 g sample, if it remains 60-52.5=7.5 g, it will go through 60->30->15->7.5, 3 half-life. So the time being taken is 269*3=807 years.

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