What is static electricty?
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Related Questions
In a generator, mechanical energy is converted into which of the following? A.an electromagnet B.a moving rod C.a magnetic field D.electrical energy
A runner achieves a velocity of 11.1 m/s 9 seconds after he begins. What is his acceleration? What distance did he cover?
A skier reaches the bottom of a slope with a velocity of 12 meters per second north. If the skier comes to a complete stop in 3 seconds, what is the acceleration
Five different forces act on an object. Is it possible for the net force on the object to be zero? Explain
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Answer:
Farsighted and Nearsighted
Explanation:
B. potential energy
C. volume
D. mass
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Thermal energy is heat energy, therefore the hotter a solid is the more thermal energy it has.
C. Volume
When an object gets hotter, it expands. This is becuase the particles vibrate more and so are less compact.
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Accerlation (a) = ?
Initial velocity (V1)= 60 mph = 88 ft/s (because we HAVE to convert mph to ft/s to match time)
Final velocity (V2) = 0 ft/s because the car stops
Time (t) = 4 seconds
a =
a =
a =
a = -22
Therefore, your acceleration is -22 ft/s² !! Hope this helped and was one of the branliest answers :')
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Frequency = rate of sploosh = 2 per second = 2 Hz.
Period = ( 1/frequency ) = 1/2 second
Speed = (wavelength) x (frequency) = (0.15m) x ( 2/sec) = 0.075 m/s .
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I used the Lens Equation:
Where:
obj. is the distance of the object
im. is the distance of the image
f is the focal length
Final answer:
The image formed by the convex lens is real, located 10.91 cm to the right of the lens, and is inverted. The ray diagram would show rays from the object converging at the image point after passing through the lens.
Explanation:
In order to draw a ray diagram and find the location of the image for an object placed 30.0 cm to the left of a convex lens with a focal length of +8.0 cm, we first utilize what is known as the lens formula, which is 1/f = 1/do + 1/di. Here, f is the focal length of the lens, do is the object distance, and di is the image distance.
In the given question, the object distance (do) is -30 cm (the negative sign indicates that the object is on the same side of the lens as the light source), and the focal length (f) is +8 cm. Plugging these values into the lens equation, we find that 1/di = 1/f - 1/do = 1/8 - 1/(-30). Solving this, we get di = 10.91 cm.
This positive value for di means the image is real, meaning it can be projected onto a screen, and appears on the opposite side of the lens from where the object is. The magnitude of the image distance indicates the image is 10.91 cm from the lens.
To determine the orientation of the image, we use the magnification formula, m = -di/do. Substituting the given values into this formula, we get m = -10.91 / -30 = +0.36. Since this value is positive, the image is inverted. The image would appear smaller than the object because the absolute value of the magnification is less than 1.
Learn more about Convex lens image formation here:
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b. nitrogen
c. oxygen
d. halogen
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A is the answer
Hope it helps