Which process causes the temperature to decrease as one goes higher in the mesosphere?a fewer particles to convert the red-green light spectrum into heat
b fewer particles to convert IR light into heat
c fewer particles to convert ozone into heat
d fewer particles to covert UV light into heat

Answers

Answer 1
Answer: The correct answer is letter D. There are fewer particles present in the mesosphere which can convert UV light into heat. This causes the temperature to decrease and the overall atmosphere to decrease with its oxygen content causing a person the inability to breathe at high altitudes.
Answer 2
Answer:

Answer:

D

Explanation:


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What is the main difference between a longitudinal wave and a transverse wave? a longitudinal wave travels faster than a transverse wave. a transverse wave always has a larger amplitude than a longitudinal wave. the motion of the medium is parallel to a longitudinal wave and perpendicular to a transverse wave. the frequency is directly proportional to wavelength in a longitudinal wave but inversely proportional in a transverse wave.?

Answers

When waves propagate in a medium, then the motion of the medium is parallel to a longitudinal wave and perpendicular to a transverse wave.

What are sound waves?

A sound wave is caused by disturbances in the path of propagation of the particles. These disturbances can be caused in the medium like solid, liquid, and air.

There are two main types of waves namely - Transverse waves and longitudinal waves.

Transverse Waves - These waves are the waves where the particles in a medium travel perpendicular to the direction of the wave. These waves do not require a medium to travel and can travel in a vacuum also.

Longitudinal waves - These waves are the waves where the particles of the medium travel parallel to the direction of the wave and these waves require a medium to travel and hence, cannot travel in a vacuum.

Thus, we can conclude that the motion of the medium is parallel to a longitudinal wave and perpendicular to a transverse wave.

Learn more about the sound wave here:

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Answer: The correct answer is the motion of the medium is parallel to a longitudinal wave and perpendicular to a transverse wave.

Explanation:

There are two main types of waves:

1. Transverse Waves: These waves are the waves where the particles in a medium travel perpendicular to the direction of the wave. These waves do not require a medium to travel and can travel in vacuum also. For Example: Light waves.

2. Longitudinal waves: These waves are the waves where the particles of the medium travel parallel to the direction of the wave and these waves require a medium to travel and hence, cannot travel in vacuum. For Example: Sound waves.

From the given options, the correct answer is  the motion of the medium is parallel to a longitudinal wave and perpendicular to a transverse wave.

A snail travels at a rate of 2.37 feet per minute. a. Write a rule to describe the function. b. How far will the snail travel in 6 minutes?

Answers

  a. 
distance = rate*time 
d = 2.37t 

b. 
d = 2.37*6 = 14.22 ft

Answer:

b

Explanation:

How are airplanes artificially pressurized?

Answers

They are built to be airtight so thsy sir can't get in or out, and then, as they climb up to where the air is thin, they use an air pump to pimp air into the inside.

Just like a party balloon.

What is the percent by mass of 5.0 g of iron (II) sulfate dissolved in 75.0 grams of water?

Answers

Considering the definition of percentage by mass, the percent by mass of 5.0 g of iron (II) sulfate dissolved in 75.0 grams of water is 6.25 %.

The percentage by mass expresses the concentration and indicates the amount of mass of solute present in 100 grams of solution.

In other words, the percentage by mass of a component of the solution is defined as the ratio of the mass of the solute to the mass of the solution, expressed as a percentage.

The percentage by mass is calculated as the mass of the solute divided by the mass of the solution, the result of which is multiplied by 100 to give a percentage. This is:

percent by mass= (mass of solute)/(mass of solution)x100

In this case, you know:

  • mass of solute= 5 g
  • mass of water= 75 g
  • mass of solution= mass of solute + mass of water= 5 + 75 g= 80 g

Replacing:

percent by mass= (5 g)/(80 g)x100

Solving:

percent by mass= 6.25 %

Finally, the percent by mass of 5.0 g of iron (II) sulfate dissolved in 75.0 grams of water is 6.25 %.

Learn more:

Hello!

What the percent by mass of 5.0 g of iron (II) sulfate dissolved in 75.0 g of water?

We have the following data:

m1 (solute mass - iron II sulfate) = 5.0 g

m2 (solvent mass - water) = 75.0 g

m (solution mass) = m1 + m2 = 5.0 + 75.0 = 80.0 g

%m/m (percent mass by mass) = ?

We apply the data to the formula

\%\:m/m = (m_1)/(m)*100

\%\:m/m = (5)/(80)*100

\%\:m/m = 0.0625*100

\boxed{\boxed{\%\:m/m = 6.25}}\Longleftarrow(solute\:in\:percent)\:\:\:\:\:\:\bf\blue{\checkmark}

Answer:  

The percent by mass of solute and mass solution of Iron II Sulfate is 6.25%  

_______________________  

\bf\blue{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}\:\:\ddot{\smile}

The conductive tissues of the upper leg can be modeled as a 40- cm-long, 12-cm-diameter cylinder of muscle and fat. The resistivities of muscle and fat are 13 Ω m and 25 Ω m, respectively. One person’s upper leg is 82% muscle, 18% fat. What current is measured if a 1.5 V potential difference is applied between the person’s hip and knee?

Answers

Answer:

current = 0.0027 A

Explanation:

the resistivity of upper leg

\rho = 0.82 (13) + 0.18(25) = 15.16 ohm . m

Resistance of upper leg

R = (\rho L)/(A)

   = (\rho L)/(\pi R^2)

  = (15.16 * 0.40)/(\pi [(0.12)/(2)]^2)

  = 551.27 ohm

currenti = (V)/(R)

current = (1.5)/(551.27)

current = 0.0027 A

Describe all the forces acting on an elevator as it moves from rest upward and stops at its floor.

Answers

The force which acts on the elevator while it starts its motion are described as follows :

1. The elevator when starts from rest, moves in a direction opposite to the gravity, hence there is an upward force which acts on the elevator. It is more than the weight due to gravity of the elevator to cause the motion. This upwards force is the force produced by the strings pulling the elevator upwards.

2. The downwards force is the weight of the elevator which is being imposed due to the gravity of the Earth to pull everything towards it, and the mass of the elevator. This downward force is less than the upward force.

3. When the elevator stops, the upward force and downward force are equal but opposite in magnitude.

Final answer:

An elevator experiences tension in the supporting cable, weight of the elevator, upward force from the floor, and gravitational force as it moves upward from rest. As it accelerates, the tension in the cable is larger than the weight making the elevator and its occupants feel heavier. Conversely, as it decelerates to stop, they feel lighter due to reduced force exerted on the floor and scale.

Explanation:

When an elevator moves upward from rest to it's designated floor, it experiences several forces. The primary forces here include the tension in the supporting cable (T or I), the weight of the elevator (we), the upward force from the floor of the elevator or the normal force (N or Ñ), and the gravitational force which is usually represented by the weight of the person (w) and the weight of the scale (ws).

While the lift is still or moving at a constant speed, the tension in the cable (T or I) and the weight of the elevator are equal but opposite, so they cancel out. But, as the elevator begins to ascend, the tension in the cable must overcome the weight hence it's larger causing the elevator to accelerate upwards. When the elevator approaches the destined floor and begins to decelerate, the tension eases and becomes lesser than the weight.

In relation to the person in the elevator, when the elevator is at rest or moving at consistent speed, the person experiences their normal weight. When the elevator accelerates upwards, the person feels slightly heavier due to the increased force they exert on the floor (Fp or I) and subsequently on the scale (Fs). When the elevator decelerates to stop, the force they exert on floor and scale becomes less and, thus, they feel slightly lighter.

Learn more about Forces acting on an Elevator here:

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