CHEMISTRY HIGH SCHOOL

The temperature of 15 grams of water increases by 3.0 degress. how much heat was absorbed by water?

Answers

Answer 1
Answer:

The amount of heat absorbed by water is 188.28 J.

we know that, specific heat capacity is the amount of heat required to raise the temperature of 1 g of substance by 1 .0C

C = Q /W*ΔT

Q= C*W*ΔT

C= specific heat capacity

Q= amount of heat absorbed

W = weight of substance

ΔT = change in temperature  

Specific heat capacity of water = 4.18 J/g.0C

Given that,

W = 15 g  

ΔT = 3.0C

Q= C*W*ΔT  

Q =4.184J/g. 0C*15g*3.0C

Q= 188.28 J

Thus, we can conclude that, the amount of heat absorbed by water is 188.28 J.

Learn more about heat capacity here:

brainly.com/question/22991121

 
Answer 2
Answer: Heat = Mass of water * specific heat of water * temperature rise= 
15 g * 4.18 J/g K * 3K = 188J

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Answers

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