How much total work is done by the force in lifting the elevator from 0.0 m to 9.0 m?

Answers

Answer 1
Answer: The total work is

         (mass of the elevator, kg) x (9.8 m/s²) x (9.0 m)           Joules .

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A shear force of 400 N is applied to one face of an aluminum cube with sides of 30 cm. What is the resulting relative displacement? (the shear modulus for aluminum is 2.5 X 1010N/m2).a) 4.4 X 10-8 m
b) 8.2 X 10-8 m
c) 1.9 X 10-8 m
d) 5.3 X 10-8 m

Answers

Answer:

\Delta x=5.33* 10^(-8)m

So option (d) will be correct option

Explanation:

We have given shear force F = 400 N

Size of the cube L_0=30cm=0.3m

Shear modulus of aluminium S=2.5* 10^(10)N/m^2

We have to find the resulting relative displacement

Area of the cube A=L_0^2=0.3^2=0.09m^2

We know that shear force is given by

F=S* (\Delta x)/(L_0)* A

So 400=2.5* 10^(10)* (\Delta x)/(0.3)* 0.09

\Delta x=5.33* 10^(-8)m

So option (d) will be correct option

) a 45-mh ideal inductor is connected in series with a 60-ω resistor through an ideal 15-v dc power supply and an open switch. if the switch is closed at time t = 0 s, what is the current 7.0 ms later?a.250 ma

b.850 ma

c.550 ma

d.280 ma

e.650 ma

Answers

the current approximately 7.0 ms after closing the switch is about 250 mA, which is option (a).

To find the current through the circuit 7.0 ms after the switch is closed, we can use the concept of an RL circuit. The current in an RL circuit follows an exponential growth equation, given by:

I(t) = (V/R)(1 - e^(-t/τ))

Where:

I(t) is the current at time t.

V is the voltage from the power supply (15 V in this case).

R is the resistance (60 Ω).

τ (tau) is the time constant of the circuit, given by L/R, where L is the inductance (45 mH = 0.045 H).

First, calculate the time constant τ:

τ = L/R = 0.045 H / 60 Ω = 0.00075 s.

Now, plug in the values into the equation to find I(7.0 ms):

t = 7.0 ms = 0.007 s.

I(0.007 s) = (15 V / 60 Ω) * (1 - e^(-0.007 s / 0.00075 s))

I(0.007 s) = (0.25 A) * (1 - e^(-9.333...))

Now, calculate the current:

I(0.007 s) ≈ (0.25 A) * (1 - e^(-9.333...))

I(0.007 s) ≈ (0.25 A) * (1 - 0.0000962) [Using e^(-9.333...) ≈ 0.0000962]

I(0.007 s) ≈ (0.25 A) * (0.9999038)

I(0.007 s) ≈ 0.24998 A

I(0.007 s) ≈ 250 mA

So, the current approximately 7.0 ms after closing the switch is about 250 mA, which is option (a).

Learn more about RL circuit here:

brainly.com/question/17050299

#SPJ3

Initial current = 0

Final current = (15 V) / (60 ohms) = 0.25 Ampere

Current along the way = 0.25 · (1 - e^- time / time-constant)

"time-constant" = L/R = (0.045 / 60) =  7.5 x 10⁻⁴ second

Current = 0.25 · (1 - e^-10,000t/7.5)

When t = 7 ms,

Current = 0.25 · ( 1 - e^-70/7.5)

Current = 0.25 · (1 - e^-9.33)

Current = 0.25 · (1 - 8.84 x 10⁻⁵)

Current = 0.25 · (0.9999)

Current = so close to 250 mA that you can't tell the difference.

The reason is that 7.0 mS is 9.3 time-constants, and during EVERY time-constant, the current grows by 37% of the distance it still has left to go. So after 9.3 of these, it's practically AT the target.

I have a feeling that the time in the question is SUPPOSED TO BE 7 microseconds.  If that's true, then

Current = 0.25 · (1 - e^-[ 7 x 10⁻⁶ / 7.5 x 10⁻⁴ ]

Current = 0.25 · (1 - e^-0.00933)

Current = 0.25 · (1 - 0.9907)

Current = 0.25 · (0.0093)

Current = 2.32 mA  ?

No, that can't be it either.

Well !  Now, I'm going to determine the true and correct final answer in the only cheap and sleazy way I have left ... by looking at all the choices offered, and eliminating the absurd ones.

The effect of an inductor in the circuit is to resist any change in current.  The final current in this circuit is when it's not trying to change any more.  So the final current is just the battery with a resistor across it ... (12 V) / (60 ohms).  That's 0.25 Ampere, or 250 mA.  The current starts at zero when the switch closes, and it builds up and builds up to 250 mA.  It's never more than 250 mA.  

So look at the choices !  The only one that not more than 250 mA is choice-A .

THAT has to be it.  7.0 mS is a no-brainer.  It's 9.3 time-constants after the switch closes, the current has built up to 99.99% of its final value by then, it's not really trying to change much any more, the inductor is just about finished having any effect on the current, and the current is essentially at its final value of 250 mA.  The action is all over.

Now, I fully realize that Mister "Rishwait" is a bot and all, and nobody really needs the answer to this question.  But every cloud has a silver lining.  It's a numskull question, but it earned me 10 points, and it's been a truly fascinating trip down Memory Lane.

What is the best angle for maximum height and air time? explain why you think this is so.

Answers

Answer: 90 degrees

Explanation:

The projectile will have the greatest air time and height when the launch is the most vertical. At 90 degrees, the launch is all vertical.

What kinds of space and matter can light travel through?

Answers

Answer:

Every material and the void.

Explanation:

Light is a kind of electromagnetic wave and electromagnetic waves do not need a medium to propagate itself. Light can travel through every medium and even in void.

Only Women and children can be victims of domestic violence

Answers

That statement is wrong.

Domestic violence could happen to anyone.

There are a lot of cases in which the domestic violence's victims are men or elderly people.

that is false because even boys who are nerds or poor and even gay are victims of domestic violence.

Which of these components is not necessary for current to flow in a series or parallel circuit?A. wire
B. switch
C. resistor
D. All of these are needed.

Answers

Current requires only an EMF source ... like a battery, or a current already flowing ... and a conducting path ... like wire, ionized air, or something dissolved in water. A switch isn't needed unless you want a quick, easy way to STOP the current. A resistor isn't needed unless you want to be able to dissipate some energy from the current, or limit its magnitude.