what is the force of gravity between a 1000000000 kg asteroid and the earth when the asteroid is 3000000 m away from the earth?

Answers

Answer 1
Answer: Mass of the Earth = 5.972 x 10²⁴ kg
Mass of the asteroid = 1 x 10⁹ kg
Separation distance = 3 x 10⁶ m  (between the Earth's center and the asteroid's center)
                   

Gravitational force between two masses =

        (6.67 x 10⁻¹¹ nt-m²/kg²) · m₁ · m₂ / (distance)²

=  (6.67 x 10⁻¹¹ nt-m²/kg²) · (5.972 x 10²⁴ kg) ·  (1 x 10⁹ kg) / (3 x 10⁶ m)²

=  (6.67 · 5.972 / 9) x 10¹⁰ · (nt · m² · kg · kg / kg² · m²)

             =      13.28 x 10¹⁰     newtons

             =        132.8  Giga-newtons .

    
(about  14,926,763 tons)
         


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The wave function for a traveling wave on a taut string is (in si units) y(x,t) = 0.340 sin 15πt − 4πx + π 4 (a) what are the speed and direction of travel of the wave? g

Answers

Answer:

Explanation:

Given the wave function

y(x,t) = 0.340 sin (15πt − 4πx + π/4)

Generally a wave function is of the form

y(x, t) = A•Sin(wt - kx + θ)

Where

A is amplitude

w is angular frequency

θ is the phase angle

k is the wave number.

Then, comparing this with given wave function

k = 4π, w = 15π and θ = π/4

Speed and direction?

The speed of a wave function can be determined using wave equation

v = fλ

w = 2πf

Then, f = w/2π = 15π/2π = 7.5Hz

Also k = 2π/λ

Then, λ = 2π/k = 2π/4π = 0.5 m

Then,

v = fλ = 7.5 × 0.5

v = 3.75m/s

Direction

Since the time and distance coefficient have opposite sign, for an increasing time interval, the translation will have to increase in the positive direction to nullify the change and maintain the phase. Hence, the wave is traveling in the positive x direction

When driving downhill, your vehicle will accelerate and start moving fast, due to _______________.a. kinetic energy
b. gravity
c. the amount of pressure you put on the accelerator pedal
d. wet pavement

Answers

Correct answer choice is:

B) Gravity


Explanation:


Gravity is a force of attraction that endures within any two bodies, any two groups, any two particles. Gravity is not just the attraction among objects and the Earth. It is because the Earth going around the Sun is in a magnetic stability. The speed of the Earth's action generates a centrifugal force which balances the gravitational force among the Sun and the Earth. Because there is no force to hold it.

B: Gravity.
The force of gravity will pull the car down the hill. The weight/mass of the car also helps this.

The tip of a fan blade is 0.61 m from the center of the fan. The fan turns at a constant speed and completes 2 rotations every 1.0 second. What is the centripetal acceleration of the tip of the fan blade? Option 1: 6.0 m/s² Option 2: 48 m/s² Option 3: 53 m/s² Option 4: 96 m/s²

Answers

Answer: Here's my answer, I made it step-by-step so you can understand it! <3

Explanation:

To find the centripetal acceleration of the tip of the fan blade, we can use the formula for centripetal acceleration:

a = (v^2) / r

where:

a is the centripetal acceleration,

v is the linear velocity, and

r is the radius of the circular path.

Given that the fan completes 2 rotations every 1.0 second, we can find the angular velocity (ω) using the formula:

ω = (2π * n) / t

where:

ω is the angular velocity,

π is a constant (approximately 3.14),

n is the number of rotations (2),

and t is the time taken (1.0 second).

Substituting the values into the formula, we have:

ω = (2π * 2) / 1.0 = 4π rad/s

Next, we can calculate the linear velocity (v) using the formula:

v = r * ω

Substituting the given radius value (0.61 m) and the angular velocity we found earlier, we have:

v = 0.61 * 4π = 2.44π m/s

Finally, we can calculate the centripetal acceleration (a) using the formula:

a = (v^2) / r

Substituting the linear velocity and the radius, we have:

a = (2.44π)^2 / 0.61 = 5.88π^2 / 0.61 ≈ 96 m/s²

Therefore, the centripetal acceleration of the tip of the fan blade is approximately 96 m/s² (Option 4).

A magnetic field is perpendicular to the plane of a single-turn circular coil. The magnitude of the field is changing, so that an emf of 0.43 V and a current of 3.1 A are induced in the coil. The wire is then re-formed into a single-turn square coil, which is used in the same magnetic field (again perpendicular to the plane of the coil and with a magnitude changing at the same rate). What (a) emf and (b) current are induced in the square coil

Answers

Answer:

2.62A

Explanation:

Given

V = 0.43 V

I = 3.1 A

Then, V = IR, R = V/I

R = 0.43/3.1

R = 0.14 Ω

The induced emf = dB/dt * A

So that, dB/dt = emf/A

Since dB/dt is constant then Emf/A(circle) = Emf/A square

So Emf (square)/Emf (circle) = A square / A circle

A circle = πr². The perimeter of the square is 2πr which also is the circumference of the square.

Since the perimeter is 2πr, then each side would be πr/2. Thus, the area of the square would be, (πr/2)² = π²r²/4

So A square/Acircle = (π²r²/4) / πr² = π/4 = 0.79

this means that, emf square = emf circle * 0.79

emf square = 0.43*0.79 = 0.34V

I = V/R

I = 0.34/0.13

I = 2.62A

Which of the following terms describes the motion of particles during the transmission of wave energy?

Answers

The motion of particles during the transmission of wave energy is periodic. A periodic wave is a continuous oscillating motion that connects with simple harmonic motion. It is usual that periodic wave particles also experiences simple harmonic motion. Additionally, the particles on the surface of the water travel in circular motions forming a wave across the surface.

Calculate the displacement for an object traveling at a constant velocity of 32 m/s for 4 s.

Answers

Answer:

128 m

Explanation:

displacement = velocity x time

32 x 4 = 128

Answer:

Displacement= velocity X time

= 32 X 4

=128m/s