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A moon is in orbit around a planet. The​ moon's orbit has a semimajor axis of 4.3 times 10 Superscript 8 Baseline m and has an orbital period of 1.516 days. Use these data to estimate the mass of the planet.

Answers

Answer 1
Answer:

Answer:

The mass of the planet is 2.7*10^(27)\ kg.

Explanation:

Given that,

Semi major axis a= 4.3*10^(8)

Orbital period T=1.516 days

Using Kepler's third law

T^2=(4\pi^2)/(GM)a^3

M=(4\pi^2)/(GT^2)a^3

Where, T = days

G = gravitational constant

a = semi major axis

Put the value into the formula

M=(4*(3.14)^2)/(6.67*10^(-11)(1.516*24*60*60)^2)(4.3*10^(8))^3

M=2.7*10^(27)\ kg

Hence, The mass of the planet is 2.7*10^(27)\ kg.

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A 5-kg moving at 6 m/s collided with a 1-kg ball at rest. The ball bounce off each other and the second ball moves in the same direction as the first ball at 10 m/sec. What is the velocity of the first ball after the collision?

PLEASE HELP IT'S DUE IN LIKE 2 MINUTES

Answers

Answer:

1kg

Explanation:

this box is the smallest and weighs the least. Hope this helps :]

An aluminum rod 17.400 cm long at 20°C is heated to 100°C. What is its new length? Aluminum has a linear expansion coefficient of 25 × 10-6 C-1.

Answers

The new length of aluminum rod is 17.435 cm.

The linear expansion coefficient is given as,

                      \alpha=(L_(1)-L_(0))/(L_(0)(T_(1)-T_(0)))

Given that, An aluminum rod 17.400 cm long at 20°C is heated to 100°C.

and linear expansion coefficient is 25*10^(-6)C^(-1)

Substitute,  L_(0)=17.400cm,T_(1)=100,T_(0)=20,\alpha=25*10^(-6)C^(-1)

                   25*10^(-6)C^(-1) =(L_(1)-17.400)/(17.400(100-20))\n\n25*10^(-6)C^(-1) = (L_(1)-17.400)/(1392) \n\nL_(1)=[25*10^(-6)C^(-1) *1392}]+17.400\n\nL_(1)=17.435cm

Hence, The new length of aluminum rod is 17.435 cm.

Learn more:

brainly.com/question/19495810

Answer:

the new length is 17.435cm

Explanation:

the new length is 17.435cm

pls give brainliest

While standing outdoors one evening, you are exposed to the following four types of electromagnetic radiation: yellow light from a sodium street lamp, radio waves from an AM radio station, radio waves from an FM radio station, and microwaves from an antenna of a communications system. Rank these types of waves in terms of increasing photon energy, lowest first.

Answers

Answer:

Explanation:

1. radio waves from am

2. radio waves from fm

3.yellow light from a sodium street lamp

4. microwaves from an antenna of a communications system.

A Michelson interferometer operating at a 400 nm wavelength has a 3.95-cm-long glass cell in one arm. To begin, the air is pumped out of the cell and mirror M2 is adjusted to produce a bright spot at the center of the interference pattern. Then a valve is opened and air is slowly admitted into the cell. The index of refraction of air at 1.00 atmatm pressure is 1.00028.Required:
How many bright-dark-bright fringe shifts are observed as the cell fills with air?

Answers

Answer:

55.3

Explanation:

The computation of the number of bright-dark-bright fringe shifts observed is shown below:

\triangle m = (2d)/(\lambda) (n - 1)

where

d = 3.95 * 10^(-2)m

\lambda = 400 * 10^(-9)m

n = 1.00028

Now placing these values to the above formula

So, the  number of bright-dark-bright fringe shifts observed is

= (2 *3.95 * 10^(-2)m)/(400 * 10^(-9)m) (1.00028 - 1)

= 55.3

We simply applied the above formula so that the number of bright dark bright fringe shifts could come

During a storm, a tree limb breaks off and comes to rest across a barbed wire fence at a point that is not in the middle between two fence posts. The limb exerts a downward force of 176 N on the wire. The left section of the wire makes an angle of 12.5° relative to the horizontal and sustains a tension of 413 N. Find the (a) magnitude and (b) direction (as an angle relative to horizontal) of the tension that the right section of the wire sustains.

Answers

Answer:

a. 12.12°

b. 412.04 N

Explanation:

Along vertical axis, the equation can be written as

T_1 sin14 + T_2sinA = mg

T_2sinA = mg - T_1sin12.5           ....................... (a)

Along horizontal axis, the equation can be written as

T_2×cosA = T_1×cos12.5    ......................... (b)

(a)/(b) given us

Tan A = (mg - T_1sin12.5) / T_1 cos12.5

 = (176 - 413sin12.5) / 413×cos12.5

A = 12.12 °

(b) T2 cosA = T1 cos12.5

T2 = 413cos12.5/cos12.12

= 412.04 N

Answer:

Magnitude - 11.83 Degree

Direction - 422.42 N

Explanation:

Given data:

Downward force on wire 176 N

Angle made by left section of wire 12.5 degree with horizontal

Tension force = 413 N

From figure

Applying quilibrium principle at point A

The vertical and horizontal force is 0

then we have

Tcos\theta = 413 N   ........1

176 = 413 sin 12.5 + Tsin\theta     .......2

Tsin\theta = 176 - 89.39  = 86.6.......3

divide equation 3 by 1

we get

\theta = tan^(-1) (0.2096)

theta = 11.83^o  ...........4

from equation 3 and 4

T = (86.6)/(sin 11.83)

T = 422.42 N

While a mason was working concrete into formwork, the formwork collapses. Who is BEST suites to rectify this problem? Mason Carpenter Project Manager O Construction Technician A device made in a workplace had defects. To address this issue the workshop manager should communicate directly with the workshop​

Answers

Answer:

1. Carpenter

2. True

Explanation:

While a mason was working concrete into the formwork, the formwork collapses. The best person to rectify this problem is CARPENTER.

This is because it is the job of the Carpenter to design and build formwork, most especially wooden formwork. Formwork is like casing built to receive concrete and reinforcement during construction. Hence, when formwork collapses either due to stress, tension, or improper construction, it is the job of Carpenter to reconstruct the formwork or rectify the problem.

It is TRUE that when a device made in a workplace had defects. To address this issue the workshop manager should communicate directly with the workshop​. However, this communication will be an instruction on what to do next, and it usually directs those responsible to take action where necessary. For example, a workshop manager communicates to a carpenter about the need to rectify a chair or table that has a defect.
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