The threshold of hearing for humans is 30 decibels.
True
False

Answers

Answer 1
Answer: False. Thirty decibels is not the threshold for the human ear. The human ear can hear sounds between 0 to 140 dB. The so-called hearing threshold for humans is 0 dB. It does not mean that at this level there is no sound instead we just can't hear it.

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How does an atom charge if all the electrons are removed
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What effect did the Cold War have on the American space program?A. High levels of military spending deterred scientific research.
B. The need for nuclear weapons led to less sophisticated rocket technology.
C. American and Soviet scientific cooperation lessened political tension.
D. Competition with the Soviet Union spurred American space missions

Answers

The answer is D.Competition with the Soviet Union spurred American space missions.

♡♡Hope I helped!!! :)♡♡

Competition with the Soviet Union spurred American space missions.

The waste products of a nuclear fission powerplant can best be described asa. Small in quantity and not very dangerous.
b. Large in quantity and not very dangerous.
c. Large in quantity and very dangerously radioactive. Eliminate
d. Small in quantity and very dangerously radioactive.

Answers

The answer is D. small in quantity and very dangerously radioactive.

a.
 
-> the products are stable atoms with a much lower atomic number. For example, Uranium 238 commonly breaks down into strontium and xenon, both of which are stable and non-radioactive.

They are also low in quantity because of the precision involved in breaking down a large atom via neutron capture means that few fission reactions take place.

Hope I helped :)

Source: I studied nuclear physics in year 11

When two forces act on an object in the same direction the resultant force is equal to

Answers

When two (or more) forces act on an object, all in the same direction,
the resultant force is equal to the sum of the individual forces.

That's a big part of the reason why, when you're pushing a car, you
ask somebody else to come push it with you, in the same direction.

A positive charge is moving from the floor of a room toward the ceiling. A magnetic field runs from east to west. In what direction is the magnetic force on the moving positive charge?a. toward the north
b. toward the south
c. toward the east
d. toward the west
e. toward the floor

Answers

It will be in the same direction of the charge so it will be toward the north

The force of attraction between things that have mass is called ________________.

Answers

I would assume gravitation.

Calculate how much work is required to launch a spacecraft of mass m from the surface of the earth (mass mE, radius RE) and place it in a circular low earth orbit--that is, an orbit whose altitude above the earth's surface is much less than RE. (As an example, the International Space Station is in low earth orbit at an altitude of about 400 km, much less than RE

Answers

The work done to launch the spacecraft in low earth orbit is  (GM_emh)/(R_e(R_e+h))

Work-energy theorem:

The gravitational force is a conservative force. So, the total energy of the system must be conserved.

According to the work-energy theorem:

work done = - change in potential energy of the system.

W = -ΔPE

Initially, the potential energy of the satellite on the surface is:

PE = -(GM_em)/(R_e)

where m is the mass of the satellite

Let the orbit be at a height of h from the surface, so the potential energy in the orbit is :

PE' = -(GM_em)/(R_e+h)

ΔPE = PE'-PE

ΔPE = -GM_em((1)/(R_e+h)-(1)/(R_e))

\Delta PE=-(GM_emh)/(R_e(R_e+h))

Now work done:

W = - ΔPE

Thus,

W=(GM_emh)/(R_e(R_e+h))

Learn more about work energy theorem:

brainly.com/question/13603991?referrer=searchResults

Answer:

Work done to shift the spacecraft from Earth surface to low Earth radius is given as

W = (GM_e m)/(2R_e)

Explanation:

As we know that spacecraft is at surface of Earth initially

So we will have

U_i = -(GM_e m)/(R_e)

now when it is at low radius Earth Orbit then we have

U_f = -(GM_e m)/(2(R_e + h))

now we know that work done to shift the spacecraft from Earth Surface to Low earth orbit is change in total energy

W = -(GM_e m)/(2(R_e + h)) + (GM_e m)/(R_e)

so we have

W = (GM_e m)/(R_e) (-(1)/(2(1 + h/R_e)) + 1)

W = (GM_e m)/(R_e) (-(1)/(2)(1 - (h)/(R_e)) + 1)

W = (GM_e m)/(2R_e)(1 + (h)/(R_e))

since we know h << Re

so work done is given as

W = (GM_e m)/(2R_e)