PHYSICS MIDDLE SCHOOL

The device which is used to increase or decrease the voltage of electricity is called

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Answer 1

Answer:

Answer:

Transformer

Explanation:

Transformers can increase (step up), or it can decrease (step down) voltage.

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look around you to find an object in motion.Describe the object's motion by discussing its position and direction of motion in relation to a reference point.Then explain how you can determine the object's speed

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the object in motion is a car. the car's motion is fast and bright in color. I can determine the speed of the car by the speed limit at the moment and upping it if the car is moving faster.

Final answer:

The motion of a car in relation to a reference point can be described by its position and direction. Speed can be determined by measuring the distance traveled in a specific time period.

Explanation:

A moving car can be an object in motion. In relation to a reference point, such as a stationary tree, the car's position and direction of motion can be described. For example, the car may be moving to the right of the tree.

To determine the car's speed, you can measure the distance it travels in a certain amount of time. For instance, if the car travels 100 meters in 10 seconds, its speed would be 10 meters per second (m/s).

In summary, by observing the position and direction of motion of an object in relation to a reference point, you can describe its motion. And by measuring the distance it covers in a given time period, you can determine its speed.

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Three resistors (R1 = 120 Ohms, R2 = 330 Ohms, and R3 = 240 Ohms) and an ideal inductor (L = 1.6 mH) are connected to a battery (V = 9 V) through a switch as shown in the figure below.The switch has been open for a long time before it is closed at t = 0. At what time t0, does the current through the inductor (I3) reach a value that is 63% of its maximum value?

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The time at which the current through the inductor reaches 63% of the maximum current is 4.85 $\mu$ s

What is current?

The current is defined as the flow of the charge in the circuit is is the rate of flow of the charge.

At t=0 s there is no current in the circuit because the switch is not closed and the circuit is not complete. The current across the LR circuit increases exponentially, when the switch is closed, and becomes steady after a certain time.

Given that

The value of resistor is .120 ohm

The value of resistor is .330 ohm

The value of resistor is .240ohm

The value of the inductor is .1.6 mh

The voltage applied across the circuit is .9 V

To determine the value of effective resistance of this circuit we need to look at the circuit from inductor’s side i.e., from inductor’s side the resistors is connected in series with the parallel combination of resistors

The effective resistance of the circuit is:

$R_(eff)=R_a+(R_1* R_2)/(R_1+R_2)$ …… (1)

Here, $R{eff$ is the effective resistance of the circuit. Now substituting the values.

$R_(eff)=240+(120* 330)/(120+330)=328\ ohm$

The current through the inductor is:

$i=i_o(1-e^{(tR_(eff))/(L)})$ ...... (2)

Here, is the current across the inductor, io is the maximum current in the circuit and L is the inductance across the inductor.

The current across the inductor is equal to the 63% of the maximum current in the circuit.

The current across the inductor is:

i=0.63io

Substitute 0.63io for 328 ohm , for 1.6 mH and for L in equation (2).

$0.63 i_o=i_o(1-e^(-t(328))/(1.6)})$

Simplify the above expression.

$e^((-2.05*10^6))=0.37$

Taking natural log on both sides and simplify.

$t=4.85* 10^(-6)\ s$

$t=4.85 \mu s$

Thus, the time at which the current through the inductor reaches 63% of the maximum current is $t=4.85 \mu s$

To know more about current follow

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The time at which the current through the inductor reaches 63% of the maximum current is $\fbox{\begin\n4.85 \mu s\end{minispace}}$ or $\fbox{\begin\n4.85 * {10^( - 6)}\,{\text{s}}\end{minispace}}$ .

Further Explanation:

At $t = 0\,{\text{s}}$ there is no current in the circuit because the switch is not closed and the circuit is not complete. The current across the LR circuit increases exponentially, when switch is closed, and becomes steady after certain time.

Given:

The value of resistor is $120\,\Omega$ .

The value of resistor is $330\,\Omega$ .

The value of resistor is $240\,\Omega$ .

The value of the inductor is $1.6\,{\text{mH}}$ .

The voltage applied across the circuit is $9\,{\text{V}}$ .

Concept:

To determine the value of effective resistance of this circuit we need to look at the circuit from inductor’s side i.e., from inductor’s side the resistors ${R_3}$ is connected in series with the parallel combination of resistors ${R_1}$ and ${R_2}$ .

The effective resistance of the circuit is:

$\fbox{\begin\n{R_(eff)} = {R_3} + \frac{{{R_1} * {R_2}}}{{{R_1} + {R_2}}}\end{minispace}}$ …… (1)

Here, ${R_(eff)}$ is the effective resistance of the circuit.

Substitute the $120\,\Omega$ for ${R_1}$ , $330\,\Omega$ for ${R_2}$ and $240\,\Omega$ for ${R_3}$ in equation (1).

$\begin{aligned}{R_(eff)}&=240\,\Omega+\frac{{\left( {120\,\Omega } \right) * 330\,\Omega }}{{120\,\Omega +330\,\Omega }} \n&=328\,\Omega\n \end{aligned}$

The current through the inductor is:

$\fbox{\begin\ni = {i_0}\left( {1 - {e^{ - \frac{{t{R_(eff)}}}{L}}}} \right)\end{minispace}}$ ...... (2)

Here, $i$ is the current across the inductor, ${i_0}$ is the maximum current in the circuit and $L$ is the inductance across the inductor.

The current across the inductor is equal to the 63% or times of the maximum current in the circuit.

The current across the inductor is:

$i = 0.63{i_0}$

Substitute $0.63{i_0}$ for $i$ , $328 \Omega$ for ${R_(eff)}$ and $1.6\,{\text{mH}}$ for $L$ in equation (2).

$0.63{i_0} = {i_0}\left( {1 - {e^{ - \frac{{t\left( {328\Omega } \right)}}{{\left( {1.6\,{\text{mH}}} \right)}}}}} \right)$

Simplify the above expression.

${e^{ - \left( {2.05 * {{10}^6}} \right)t}}= 0.37$

Taking natural log on both sides and simplify.

$\begin{aligned}t&=4.85\, * {10^( - 6\,)}\,{\text{s}} \n&=4.85\mu \text{s}}\n\end{aligned}$

Thus, the time at which the current through the inductor reaches 63% of the maximum current is $\fbox{\begin\n4.85 \mu s\end{minispace}}$ or $\fbox{\begin\n4.85 * {10^( - 6)}\,{\text{s}}\end{minispace}}$ .

Learn more:

1. Conservation of energy brainly.com/question/3943029

2. Average translational energy brainly.com/question/9078768

3. The motion of a body under friction brainly.com/question/4033012

Answer Details:

Grade: Middle School

Subject: Physics

Chapter: Current Electricity

Keywords:

Resistor circuit, LR circuit, current, current across inductor, time constant, 4.85 microsecond, 4.85 microsec, 4.85 micros, 4.85*10-6 s, 4.85*10^6 s, 4.85*10-6 sec, 4.85*10^6 sec.

How mud is made summary

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Mud forms after rain and mud is made from rock

Which is the SI base unit for distance?

A. cm

B. km

C. m

D. mm

I think its C.m

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Yes you're correct. For distance, SI is based on meters.

From this diagram which of the following can you conclude

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Answer: A

Explanation:

I say opposites attract

The answer is A.

Hope this helps :)

What kind of levers are your arms and legs

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Answer:

Legs are the 2nd class lever.

Arms are the 3rd class lever.

Explanation:

A lever is an inflexible body fit for turning on a point on itself. There are three types of lever

1) 1st class lever: (pivot is in the center of load and effort)

In the human body are uncommon. One model is the joint between the head and the principal vertebra

2) 2nd class lever: (load is in the center of pivot and effort)

In the human body, the 2nd class lever is found in the lower leg when somebody remains on tiptoes.

3) 3rd class lever: (The load is far from the pivot than the effort.)

In the human body; one model can be delineated in the elbow joint

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The device which is used to increase or decrease the voltage of electricity is called​

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Final answer:

Explanation:

Learn more about motion here:

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What is current?

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The device which is used to increase or decrease the voltage of electricity is called