A wave has an amplitude of0.0800 m and is moving 7.33 m/s.
One oscillator in the wave takes
0.115 s to go from the lowest point
in its motion to the highest point.
Find the frequency of the wave.
(Unit = Hz)​

Answers

Answer 1
Answer:

Answer:

The frequency of wave is 4.34 Hz.

Explanation:

We know the relation:

                                 λ = (v)/(f) = v × T........................................1

where,

            λ= wavelength

            v= velocity of wave

            T= Period of wave

 

By the definition of period T, you are given that HALF of T is 0.115 s, so

 

T = 2 × (0.115 s)

   = 0.23 s

 

Then,

 

                  λ = v × T

                     = (7.33 m/s) × (0.23 s)

                    ≅ 1.686 m

Now for frequency, return to equation 1,

   f = (v)/( \lambda )

      = (7.33)/(1.686)

      = 4.34

The frequency of the wave is calculated as 4.34 Hz.

Answer 2
Answer:

Answer:

0.230

Explanation:

That's the answer, the one above isn't, I got this answer correct on acellus


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Ah hah !  The two questions on this page are checking to see
if you understand what "net force" means.

Remember that "net force" means the result of adding up the
strength and direction of a group of separate forces.

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