What type of interference results in beats?constructive
destructive
negligible
interference is not involved in the creation of beats

Answers

Answer 1

Answer:

Answer: constructive

Explanation:

Two waves having slightly different frequencies when interfere constructively produce beats. Superposition of these two waves results in addition of amplitudes of the two waves. The amplitude of the resultant wave vibrates or beats.

Beat frequency is given by the absolute difference between the frequencies of the two waves.

b = |f₂ - f₁| = f₂ - f₁ or f₂ + f₁

Answer 2

Answer: The answer is A Constructive.

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An alarm clock draws 0.5 A of current when connected to a 120 volt circuit. Calculate its resistance.

Answers

We need to calculate the resistance of a clock which draws current I=0.5A and is connected to a circuit of V=120V. We can find the resistance of a circuit from Ohm's law: I=U/R where I is the current, U is the voltage and R is the resistance. So lets manipulate Ohm's law to find the resistance: R=U/I. Now we input our numbers: R=120V/0.5A and we get R=240 Ohm. So the resistance is R=240 Ohm.

Given the amount of voltage and the amount of current drawn by the alarm clock, its resistance is 240 ohms.

What is Ohm’s law?

Ohm’s law states that "the potential difference between two points is directly proportional to the current flowing through the resistance.

It is expressed as;

V = I × R

Where V is the voltage or potential difference, potential difference, I is the current and R is the resistance.

Given the data in the question;

Voltage V = 120V

Current I = 0.5A

Resistance R = ?

We substitute our given values into the expression above.

V = I × R

120V = 0.5A × R

R = 120V / 0.5A

R = 240Ω

Therefore, given the amount of voltage and the amount of current drawn by the alarm clock, its resistance is 240 ohms.

Learn more about Ohm's law here: brainly.com/question/2364325

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A 10-meter long ramp has a mechanical advantage of 5. What is the height of the ramp?

Answers

1. If the ramp has a length of 10 and has a mechanical advantage (MA) of 5. Then we need to find the height of the ramp.
Formula:
MA = L / H
Since we already have the mechanical advantage and length, this time we need to find the height .
MA 5 = 10 / h
h = 10 / 5
h = 2 meters

Therefore, the ramp has a length of 10 meters, a height of 2 meters with a mechanical advantage of 5.

Answer:

height=2

Explanation:

MA= input/output

MA= 5

input = 10 (the ramp)

output=x (the height)

5=10/x

x=2

Animals in cold climates often depend on two layers of insulation: a layer of body fat [of thermal conductivity 0.200W/(m⋅K) ] surrounded by a layer of air trapped inside fur or down. We can model a black bear (Ursus americanus) as a sphere 1.60m in diameter having a layer of fat 3.90cm thick. (Actually, the thickness varies with the season, but we are interested in hibernation, when the fat layer is thickest.) In studies of bear hibernation, it was found that the outer surface layer of the fur is at 2.80∘C during hibernation, while the inner surface of the fat layer is at 30.9∘C a) What should the temperature at the fat-inner fur boundary be so that the bear loses heat at a rate of 51.4W ? b) How thick should the air layer (contained within the fur) be so that the bear loses heat at a rate of 51.4W ?

Answers

A) The temperature at the fat-inner fur boundary be so that the bear loses heat at a rate of 51.4W is; T_i = 38.52°C

B) The thickness of the layer contained within the fur so that the bear loses heat at a rate of 51.4 W is; t = 13.41 cm

We are given;

Diameter of sphere; d = 1.6 m

Radius of sphere; r = d/2

r = 1.6/2

r = 0.8 m

Thickness of bear; t = 3.9 cm cm = 0.039 m

Outer surface Temperature of fur; T_h = 2.8 ∘C

Inner surface Temperature of fat;T_f = 30.9 ∘C

Thermal conductivity of fat; K_f = 0.2 W/m⋅k

Thermal conductivity of air; K_a = 0.024 W/m⋅k

A) To find the temperature at the fat-inner fur boundary when heat loss is 51.4 W, we will use the heat current formula;

H = K_f•A(T_f - T_i)/t

Where;

A is area = 4πr²

A = 4π × 0.8²

A = 8.04 m²

T_i is the temperature we are looking for

H is heat loss = 51.4

t is thickness

Making T_i the subject gives;

T_i = (T_f × H × t)/(K_f × A)

T_i = (30.9 × 51.4 × 0.039)/(0.2 × 8.04)

T_i = 38.52°C

B) We want to find the thickness of the layer contained within the fur. Thus, we will use K_a instead of K_f. Let us make t the subject in the heat current formula to get;

t = (K_a•A(T_i - T_h)/H

t = (0.024 × 8.04 × (38.52 - 2.8))/51.4

t = 0.1341 m

t = 13.41 cm

Read more at; brainly.com/question/14548124

Answer:

Explanation:

Using the equation

H = Q/t = k A ( T hot - T cold) / L

where H is the rate of heat loss = 51.4 W, T cold be temperature of the outer surface, A is the surface area of the fat layer which is a model of sphere ( surface area of a sphere ) = 4πr² where diameter = 1.60 m

radius = 1.60 m / 2 = 0.80 m

A = 4 × 3.142 × ( 0.8²) = 8.04352 m²

making T cold subject of the formula

T cold = T hot - $(HL)/(KA)$ = 30.9° C - ( 51.4 W × 3.9 × 10⁻² m) / ( 0.2 W/mK × 8.04352 m² ) = 30.9° C - 1.25 ° C = 29.65° C

b) The thickness of air layer for the bear to lose heat t a rate of 51.4 W

thermal conductivity of air is 0.024 W/mK and rearranging the earlier formula

L = $\frac{kA( T HOT - T COLD )}H}$ = (0.024 W/ m K × 8.04352 m²) ( 29.65° C - 2.8°C) / 51.4 W = 0.101 m = 10.1 m

Use newton's first law of motion to explain why you feel tossed around whenever a roller coaster goes over a hill or through a loop.

Answers

Newton's first law states that an object at rest will stay at rest && an object in motion will remain in motion unless acted on by another force. With that being said you feel tossed around because you are initially at rest but when you ride the roller coaster you take it's course of motion.

Hoped this helped!

Explanation:

A roller coaster is hard to stop because it has a lot of inertia. Inertia can be simplified to, "objects want to keep doing what they are doing." It's when they are forced to do something different that they are doing that is why roller coaster riders experience the float or tossing around of the ride.

The forces acting on a falling leaf are

Answers

Answer:

Gravitational and resistance force.

Explanation:

The push or pull on any object which causes an object to move is called force. The forces can be of many types. The forces acting on the falling leaf are :

Gravitational force : The force that acts in downward direction is called the force of gravity. This force pulls every object towards it.
Resistance force/ normal : The force that act opposite to gravitational force is called the resistance force. It opposes the direction of motion of the leaf.

the forces acting on a leaf are gravity and air resistance.In some cases the only force acting on an object is gravity, if that occurs then its called freefall.

What does a reference point provide