What part of a standing sound wave does a musician seek in playing a musical note of a specific pitch?

Answers

Answer 1

Answer: The correct answer to the question above is that the magician is seeking the wavelength of the standing wave. The part of a standing sound wave, which is its wavelength, the magician is seeking when playing a musical note of a specific pitch.

Answer 2

Answer:

That is false. I just took the test and it is not the wavelength. The correct answer is antinode NOT wavelength.

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A rock hits the ground with a speed of 7 m/s and a kinetic energy of 100 J. What is the rock's mass?

Answers

KE=1/2 times mass times velocity squared. So in this situation your equation would look like this 100J=1/2 times mass times 7 m/s^2. Your answer would be 4.0812 kg

mass = (2*KE) / v²
∴ the answer is 200/49

As a liquid is added to a beaker, the pressure exerted by the liquid on the bottom of the beaker ________.

Answers

Answer:

Explanation:

Hydraulic systems is based on the principle of Pascals principle. Pascal's principle states that " Pressure applied to the to a fluid in a closed container (at rest) is transmitted equally to every point of the fluid and on the walls of the container".

As a liquid is added to a beaker, the pressure exerted by the liquid on the bottom of the beaker increases compared to the liquid near at the tip of the beaker. Pressure increases as depth increases in any form of matter.

How is the horizontal component of velocity for a projectile affected by the vertical component?

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It isn't. The horizontal and vertical velocities are separate. You separate that velocity into the horizontal component which is constant, disregarding air resistance, and vertical velocity which is changed by the acceleration due to gravity. Make calculations separately because they do not influence each other.

An Olympic sprinter can go from a state of rest to 11 meters per second in 10 seconds. What is the average acceleration of the sprinter?

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The sprinter accelerates at 1.1 meter per second.

A girl with a mass of 40 kg is swinging from a rope with a length of 2.5 m. What is the frequency of her swinging?

Answers

For a pendulum with a massless rope 'L' meters long, swinging through
a small arc, the period of the swing is

2 π √(L/g) seconds .

and it doesn't depend on the mass of the thing on the end of the rope ...
that could be a pebble or a bus.

For the girl on the 2.5-m rope,

Period = (2 π) √(2.5 / 9.8) = 3.17 seconds

Frequency = 1 / period = about 0.315 Hz .

If a girl with a mass of 40 kg is swinging from a rope with a length of 2.5 m , then the frequency of her swinging is 0.32 Hz

Further explanation

Simple Harmonic Motion is a motion where the magnitude of acceleration is directly proportional to the magnitude of the displacement but in the opposite direction.

The pulled and then released spring is one of the examples of Simple Harmonic Motion. We can use the following formula to find the period of this spring.

$\large { \boxed {T = 2 \pi\sqrt{(m)/(k)} } }$

T = Periode of Spring ( second )

m = Load Mass ( kg )

k = Spring Constant ( N / m )

The pendulum which moves back and forth is also an example of Simple Harmonic Motion. We can use the following formula to find the period of this pendulum.

$\large { \boxed {T = 2 \pi\sqrt{(L)/(g)} } }$