The amount of heat required to melt 2 lbs of ice is twice the amount of heat required to melt 1 ib of ice. is this observation a macroscopic or microscopic description of chemical behavior? Explain your answer.

Answers

Answer 1
Answer:

The observation in this instance relates to the quantity of heat needed to melt ice, and it is expressed in terms of weights (2 lbs and 1 lb) and a comparison (twice the amount).

Without going into detail into the different molecules or their interactions, it concentrates on the general behaviour and characteristics of the substance (ice) as a whole.

A microscopic description, on the other hand, would describe the behaviour in terms of the molecular or atomic interactions that take place at the particle level. It would go into ideas such as the amount of heat required to dissolve the intermolecular interactions between water molecules.

Therefore, the observation regarding how much heat is needed to melt ice is a macroscopic description since it ignores the underlying molecular interactions in favour of the substance's general behaviour and qualities.        

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Answer 2
Answer:

The observation that melting 2 lbs of ice requires twice the heat of melting 1 lb is a macroscopic description, focusing on observable properties and behavior without exploring microscopic details.

This observation is a macroscopic description of chemical behavior. Macroscopic descriptions involve the properties and behavior of substances on a large scale that can be observed directly, without delving into the molecular or atomic details. In this case, the statement refers to the amount of heat required to melt a certain quantity of ice, and it is expressed in terms of macroscopic, measurable quantities (pounds of ice and the associated heat).

The macroscopic observation does not provide insight into the molecular or atomic interactions within the ice but rather focuses on the overall behavior of the substance. The concept that the amount of heat required to melt 2 lbs of ice is twice that needed for 1 lb of ice is a statement about the material's behavior at a larger scale.

This observation aligns with the macroscopic principles of heat and phase transitions, where the heat required for a phase change is directly proportional to the mass of the substance undergoing the transition. The macroscopic perspective is concerned with observable properties and measurements, making it a practical and accessible way to describe chemical behavior without delving into microscopic details.

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The escape velocity required for gas molecules to overcome the earth’s gravity and go off to outer space is 1.12 x 103m/s at 15oC. Calculate the molar mass of a species with that velocity.

Answers

Here we use the root-mean-square velocity:
V(rms)² = (3RT)/M; where R is the molar gas constant, T is the temperature in Kelvin and M is the molar mass.
(1.12 x 10³)² = (3 x 8.314 x (273 + 15))/M
M = 5.72 x 10⁻³ kg = 5.72 grams

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Answer: Hey Brother by Avicii

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Consider the following chemical equilibrium: C(s) + 2H2 (g) <------> CH4 (g)
Now write an equation below that shows how to calculate Kp from Kc for this reaction at an absolute temperature T. You can assume T is comfortably above room temperature. If you include any common physical constants in your equation be sure you use their standard symbols, found in the ALEKS Calculator.

Answers

Answer:

Kp = [CH₄(g)]/[H₂(g)]²(RT)⁻¹

Explanation:

C(s) + 2H₂(g) => CH₄(g)

Kp = Kc(RT)ⁿ

n= change in molar volumes of gas = 1 - 2 = -1

R = 0.08206 L·Atm/mol·K (gas constant)

T = Kelvin Temperature (arbitrary in problem) K =°C + 273

Kc = [CH₄(g)]/[H₂(g)]²  (measured values need to be in moles/L)

Kp = [CH₄(g)]/[H₂(g)]²(RT)⁻¹

The following reaction was monitored as a function of time: A→B+C A plot of ln[A] versus time yields a straight line with slope −4.3×10−3 /s. If the initial concentration of A is 0.260 M, what is the concentration after 225 s?

Answers

The concentration after 225 s is 0.099 M.

As we know that, the graph of ln [A] versus time yields a straight line with slope 'k'.

So, Slope = k =  4.3*10^(-3)/s

Rate law for first order kinetics:

t=(2.303)/(k) log (a)/(a-x)

where,

k = rate constant  =  4.3*10^(-3)/s

t = time passed by the sample  = 225 s

a = initial amount of the reactant  = 0.260 M

a - x = amount left after decay process = ?

On substituting the values:

t=(2.303)/(k) log (a)/(a-x)\n\nt=(2.303)/(4.3*10^(-3)) log (0.260)/(a-x)\n\na-x=0.099M

Therefore, the concentration after 225 s is 0.099 M.

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Answer : The concentration after 225 s is, 0.099 M

Explanation :

As we know that, the graph of ln [A] versus time yields a straight line with slope 'k'.

So, Slope = k = 4.3* 10^(-3)s^(-1)

Expression for rate law for first order kinetics is given by:

t=(2.303)/(k)\log(a)/(a-x)

where,

k = rate constant  = 4.3* 10^(-3)s^(-1)

t = time passed by the sample  = 225 s

a = initial amount of the reactant  = 0.260 M

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

225=(2.303)/(4.3* 10^(-3))\log(0.260)/(a-x)

a-x=0.099M

Therefore, the concentration after 225 s is, 0.099 M

64.92 grams of Hg(NO3)2 to make 5.00 liters of solution.

Answers

Answer:

          \large\boxed{\large\boxed{0.0400mol/liter}}

Explanation:

Knowing that you have 64.92 grams of Hg(NO₃)₂ to make 5.00 liters of solution, you can calcualte the molarity of the solution.

Molarity is a measure of concentration, defined as the number of moles of solute per liter of soluiton. Mathematically:

      Molarity=\frac{\text{number of moles of solute}}{\text{liters of solution}}

Then, first you must calculate the number of moles of solute. The formula is:

        \text{number of moles}=\frac{\text{mass in grams}}{\text{molar mass}}

You can either calculate the molar mass of the compound using the chemical formula or search it in the internet.

The molar mass of Hg(NO₃)₂  is found to be 324.7 g/mol.

Now you have everything to calculate the molarity of the solution:

  • \text{number of moles}=(64.92g)/(324.7g/mol)=0.199977mol\approx 0.200mol

  • Molarity=(0.19977mol)/(5.00liters)\approx0.0400mol/liter

Use the internet or your textbook as a reference to compare and contrast the Arrhenius Theory of acids and bases vs. the Brønsted-Lowery Theory. Use the internet or your textbook as a reference to name the following and indicate if they are an acid or a base:
a. HCI
b. KOH
c. HNO
d. Mg(OH),

Answers

Answer and Explanation:

1. Arrhenius Theory which describes the concept protonic. The substance that gives H+ ions when diluted in water is called as an acid (e.g. HCl) and the substance that dissociates OH-ions whenever it is diluted in water is called as the base (e.g. NaOH)

on the other hand

Bronsted Lowery Theory describes the concept of a proton donor-acceptor. The proton-donating species is an acid and the proton-accepting species is known as a base.

2. The Chemical name and nature of acid is shown below:-

Nature Chemical Name

a. HCl Acidic Hydrochloric Acid

b. KOH Basic Potassium hydroxide

c. HNO Acidic Nitric Acid

d. Mg(OH)2 Basic Magnesium hydroxide