Which will cause an increase in the reaction rate between molecules? Molecules have strong internal bonding. Molecules collide more frequently. Electrons in the bonds remain in a meta-stable state. Electrons do not have enough energy to leave the bonds.

Answers

Answer 1

Answer:

Molecules Collide more frequently

Explanation:

The factors which effect the rate of reactions are as follow,

Concentration:

Increase in concentration of reactants will increase the number of reactants per unit volume. Therefore, the probability of collisions will increase hence, it will result in the increase in yield.

Temperature:

Increase in temperature increases the kinetic energy of reactants. Therefore, the increase in velocity of reactants results in the collisions with high energy. It makes it feasible for reactants to attain the optimum energy (activation energy) to convert into products with good yield.

Surface Area:

The reactants in grinded / powder form reacts fast as compared to solid form. In fact, grinding results in increase of the surface area of reactants. Greater surface area increases the probability of reactants to colloid. Hence, increases the yield.

Conclusion:

As shown, all the given factors are related to collisions of molecules or atoms hence, the option selected is the correct option.

Answer 2

Answer: Answer: molecules collide more frequently.

Chemical reaction mechanisms are based in the collision of molecules with certaing level of energy. More collisions implies grater probablity of reaction.

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For the principal quantum number, n, its corresponding sets of magnetic quantum, m, values depend on the angular quantum values, l. For n=2, the values of l are from 0 to (n-1), which are 0 and 1. For each value of l, the m value that corresponds to it is given by m = -l, ..., 0, ..., +l. This gives a set of m values equial to m = -1, 0, 1.

Answer:

Explanation:

Thermal expansion or thermal contraction would be most noticeable in which of the following?A. Hot car seat
B. Concrete in a sidewalk
C. Air inside a balloon
D. Liquid in a drink

Answers

The answer is C. Air inside a balloon. This is because gases are much more affected by thermal expansion and contraction compared to liquids and solids. The reason behind this is that gas molecules are very loosely packed, so even the slightest changes in temperature have a big effect on its pressure and volume. If the air inside a balloon has a temperature rise, the tendency is for the balloon to expand and potentially explode.

Liquids are also affected by thermal expansion or contraction, but not as much as gases. Solids tend to maintain their shape under thermal expansion or contraction.

Which structural formula represents 1,1 dibromopropane

Answers

The structural formula of 1, 1 dibromo propane is C₃H₆Br₂.

What is dibromopropane?

It is an organobromine compound. It is a colorless liquid. It is fpmed by the reaction of allyl bromide and hydrogen bromide.

It is used in organic synthesis of compounds.

Thus, the structural formula of 1, 1 dibromo propane is C₃H₆Br₂.

Learn more about dibromopropane

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CHBr2-CH2-CH3 Both bromide groups on the same carbon

A period is a horizontal row on the periodic table.
a. True
b. False

Answers

It is True because in the periodic table of elements, there are seven horizontal rows of elements called periods. The vertical columns of elements are called groups, or families.

44 points! Will medal!3. A calorimeter contains 500 g of water at 25°C. You place a hand warmer containing 200 g of liquid sodium acetate inside the calorimeter. When the sodium acetate finishes crystallizing, the temperature of the water inside the calorimeter is 39.4°C. The specific heat of water is 4.18 J/g-°C. How much energy was needed to heat the water?

Answers

A calorimeter contains 500 g of water at 25°C.....

the temperature of the water inside the calorimeter is 39.4°C.....

The specific heat of water is 4.18 J/g-°C.

energy needed to heat the water = specific heat * mass * temp difference

= 4.18 J/g-°C * 500 g * (39.4°C - 25°C)

= 4.18*500*14.4

= 30096J

or approx. 30kJ

Energy=specific heat of water x mass of water x water's temperatures

=4.18x500x(39.4-25)

=30096J

The standard cell potential for the aqueous reduction of Pb4+ to Pb2 + ions by the corresponding oxidation of Ce3+ to Ce4+ ions, Pb4 •(aq) + 2 Ce' •(aq) --'> Pb'•(aq) + 2 Ce4+(aq) is 0.06 V a

Answers

Answer:the standard reduction potential (E°red) for the reduction half-reaction of Pb^4+(aq) to Pb^2+(aq) is 1.50 V.

Explanation:The given chemical reaction is:

Pb^4+(aq) + 2 Ce^3+(aq) -> Pb^2+(aq) + 2 Ce^4+(aq)

The standard cell potential (E°cell) for this electrochemical reaction is 0.06 V.

The standard cell potential for a galvanic cell can be calculated using the Nernst equation:

E°cell = E°cathode - E°anode

In this reaction, Pb^4+(aq) is being reduced to Pb^2+(aq), so it is the reduction half-reaction, and Ce^3+(aq) is being oxidized to Ce^4+(aq), so it is the oxidation half-reaction.

The standard reduction potentials (E°) for the half-reactions are as follows:

For the reduction half-reaction:

Pb^4+(aq) + 2 e^- -> Pb^2+(aq) E°red = x (we'll solve for x)

For the oxidation half-reaction:

2 Ce^3+(aq) -> 2 Ce^4+(aq) + 2 e^- E°red = 1.44 V (This value is usually given)

Now, plug these values into the Nernst equation:

E°cell = E°cathode - E°anode

0.06 V = x - 1.44 V

Now, solve for x:

x = 0.06 V + 1.44 V

x = 1.50 V

So, the standard reduction potential (E°red) for the reduction half-reaction of Pb^4+(aq) to Pb^2+(aq) is 1.50 V.

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