What component can be used for user input or display of output?JButton
JLabel
JTextField
JFrame

Answer:

C, C, B, C, C, B, B or D, D, A or C, A, D

Explanation:

I am not taking whatever course you are taking, but I would like to know what you're taking. I have only answered the questions to the best of my abilities, so they might be wrong. Next time please award more points for a question so long.

Answer:

Validity

Explanation:

Personnel Selection encompasses all the processes and methods involved in the selection of workers. The purpose of personnel selection is to determine the best candidate for the job and in so doing the recruiting organization must play by the rules laid down by the government for recruitment. Validity refers to the relationship between interviews and excellent performance at the job.

Validity implies that the method of selection must meet up to a standard criterion. This standard criterion is the expected job performance required of the potential employee. Different interview types (such as job-related, situational, and psychological) have different validity levels.  

Answer:

The answer is "O(n2)"

Explanation:

The worst case is the method that requires so many steps if possible with compiled code sized n. It means the case is also the feature, that achieves an average amount of steps in n component entry information.

• In the given code, The total of n integers lists is O(n), which is used in finding complexity.
• Therefore, O(n)+O(n-1)+ .... +O(1)=O(n2) will also be a general complexity throughout the search and deletion of n minimum elements from the list.

Answer:Following is the c++ code for the problem:

#include <iostream>

using namespace std;

int main() {

   int number;

   cout<<"Enter the number"<<endl;

   cin>>number;

   int i=0,c=0,odd[500];

   while(i<=number)//loop for printing the numbers form 0 to number.

   {

       cout<<i<<" ";

       if(i%2!=0)// storing in the odd array if the number is odd.

       {

           odd[c++]=i;//storing odd numbers..

       }

       i++;

   }

   cout<<endl;

   i=0;

   cout<<"The odd numbers are "<<endl;

   while(i<c)//loop to print the odd numbers.

   {

       cout<<odd[i]<<" ";

       i++;

   }

   cout<<endl<<"The prime numbers are "<<endl;

   i=0;

   int sum=0;

   while(i<c)//loop to print the prime numbers..

   {

       int div=2;

       while(div<odd[i])

       {

           if(odd[i]%div==0)

           break;

           div++;

       }

       if(div==odd[i])

      {

           cout<<odd[i]<<" ";

           sum+=odd[i];//updating the sum..

      }

       i++;

   }

   cout<<endl<<"The sum of odd prime numbers is "<<sum<<endl;//printing the sum..

return 0;

}

Output :

Enter the number

49

0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49  

The odd numbers are  

1 3 5 7 9 11 13 15 17 19 21 23 25 27 29 31 33 35 37 39 41 43 45 47 49  

The prime numbers are  

3 5 7 11 13 17 19 23 29 31 37 41 43 47  

The sum of odd prime numbers is 326.

Explanation:

First I have printed the values from 0 to n and i have taken an array to store odd numbers.After that i have printed the odd values.And after that i have printed prime numbers among the odd numbers and their sum.These all operations are done using while loop.

Answer:

Each array position holds the position from which the information is going to be retrieved. After the code is run, each position will have the information retrieved from that position.

Explanation:

The best way to solve this problem is working as if we had a very small array. Then we can generalize for the large array.

For example

int a[3];

a[0] = 1; a[1] = 2; a[2] = 0;

for(i = 0; i < 3; i++)

a[i] = a[a[i]];

When i = 0, we have:

a[i] = a[a[i]] = a[a[0]] = a[1] = 2;

When i = 1, we have

a[i] = a[a[i]] = a[a[1]] = a[2] = 0;

When i = 2, we have

a[i] = a[a[i]] = a[a[2]] = a[0] = 1;

Basically, in our small example, each array position holds the index from which we are going to retrieve the information. The same is going to happen in the array of length 99. After the code is run, each position will have the information retrieved from that position

Contrast is the amount of variation between the lightest highlight and the darkest shadow in a particular image.

What is Contrast?

The visual ratio of various tones in an image is known as contrast in photography. The textures, highlights, shadows, colors, and clarity of a photograph are the result of this difference. The range of brightness, from lightest to darkest, in an image is known as contrast. Very bright highlights and very dark shadows characterize a high-contrastphotograph. High contrast occurs when an image's shadows or highlights are occasionally almost entirely black or almost entirely white. A crucial component for expressing particular moods in your photos is contrast. High contrast images stand out, reveal the subject's textures, and convey a sense of aplomb, vigor, and power. In both street photography and wildlife photography, high contrast is frequently used. Images with low contrast sometimes have a dreamlike quality.

To know more about Contrast visit:

brainly.com/question/1413078

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