What is the mass, in grams, of 1.50 mol of iron (III) sulfate?Express your answer using three significant figures.

Answers

Answer 1
Answer:

Answer : The mass of 1.50 mole of iron(III) sulfate is, 5.99* 10^2g

Explanation : Given,

Moles of iron(III) sulfate = 1.50 mole

Molar mass of iron(III) sulfate = 399.88 g/mole

The formula of iron(III) sulfate is, Fe_2(SO_4)_3

Formula used :

\text{Mass of }Fe_2(SO_4)_3=\text{Moles of }Fe_2(SO_4)_3* \text{Molar mass of }Fe_2(SO_4)_3

Now put all the given values in this formula, we get:

\text{Mass of }Fe_2(SO_4)_3=1.50mole* 399.88g/mole

\text{Mass of }Fe_2(SO_4)_3=599.82g=5.99* 10^2g

Therefore, the mass of 1.50 mole of iron(III) sulfate is, 5.99* 10^2g


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Explain why HCl can be a strong electrolyte, but a dilute HCl solution can be a poor conductor?

Answers

Answer:

Because as the concentration is diminished, the capacity to transfer electricity is diminished as well.

Explanation:

Hello!

In this case, since electrolytes are substances that are able to conduct the electricity in aqueous media (solutions in which water is the the solvent) because they have the capacity to form ions with both positive and negative charges, due to the fact that HCl is a strong acid, we notice it is fully ionized in solution and therefore it is a strong electrolyte. However, when the concentration is diminished, we can notice that strength is diminished as well because less ions will have the capacity to transfer the electricity and therefore it'd become a poor conductor or weak electrolyte.

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50 mL of 0.1 M acetic acid is mixed with 50 mL of 0.1 M sodium acetate (the conjugate base). The Ka of acetic acid is approximately 1. 74 X 10 -5. What is the pH of the resulting solution?

Answers

Answer:

4.76

Explanation:

In this case, we have to start with the buffer system:

CH_3COOH~->~CH_3COO^-~+~H^+

We have an acid (CH_3COOH) and a base (CH_3COO^-). Therefore we can write the henderson-hasselbach reaction:

pH~=~pKa+Log([CH_3COO^-])/([CH_3COOH])

If we want to calculate the pH, we have to calculate the pKa:

pH=-Log~Ka=4.76

According to the problem, we have the same concentration for the acid and the base 0.1M. Therefore:

[CH_3COO^-]=[CH_3COOH]

If we divide:

([CH_3COO^-])/([CH_3COOH])~=~1

If we do the Log of 1:

Log~1=~zero

So:

pH~=~pKa

With this in mind, the pH is 4.76.

I hope it helps!

How does a pharmaceutical percolator work

Answers

Final answer:

A pharmaceutical percolator is a device used to extract active compounds from plants or herbs. It works by passing a solvent through the material to dissolve the desired components. The process involves maceration, percolation, and filtration.


Explanation:

A pharmaceutical percolator is a device used in the pharmaceutical industry to extract active compounds from plants or herbs. It works on the principle of percolation, which involves passing a solvent through a solid material to dissolve the desired components. The percolation process involves three main steps:

  1. Maceration: The plant material is crushed or ground and mixed with a suitable solvent, such as ethanol or water. This mixture is then allowed to stand for a specific period, usually several hours or days, to allow the solvent to dissolve the active compounds.
  2. Percolation: The macerated mixture is then transferred to the percolator, which is a vessel with a perforated plate or bottom. The solvent is poured onto the mixture, and gravity pulls it down through the solid material, dissolving the active compounds along the way.
  3. Filtration: The liquid containing the dissolved active compounds, known as the percolate, is collected at the bottom of the percolator and filtered to remove any solid particles or impurities. The resulting solution can then be further processed or used directly in the production of pharmaceutical products.

Learn more about pharmaceutical percolator here:

brainly.com/question/1183058


How many moles of sulfuric acid are there in 1.50L of a 6.0 M solution

Answers

Answer:

n= 9moles

Explanation:

n=?, C=6M, V= 1.5L

Applying

n= CV

n= 6×1.5= 9moles

A chemical equation is shown:Al + O2 A1203
According to the law of conservation of mass, how many atoms of oxygen exist in the products of this reaction?
6
5
3
2

Answers

Answer:

it's 6

Explanation:

I just took the test and got it right

Answer:

Well the answer of 1 and 3 is WRONG based on the 1 star review and the answer of 3 is wrong too I just took a test with this question.

Explanation:

Sorry...

Nf3 Rotate the molecule until you have a feeling for its three-dimensional shape. How many atoms are bonded to the central atom?

Answers

Answer:

Three atoms are attached to the central atom in NF3.

Explanation:

The central atom is always regarded as the atom having the least electronegativity in a molecule or ion. We can decide on what atom should be the central atom by comparing the relative electro negativities of the atoms in the molecule or ion.

If we consider NF3, we can easily see that nitrogen is less electronegative than fluorine, hence nitrogen is the central atom in the molecule. We can also observe from the molecular model that three atoms of fluorine were attached to the central atom. Hence there are three atoms attached to the central atom in the molecule NF3.