Draw the structure of a compound with the molecular formula CgH1002 that exhibits the following spectral data. (a) IR: 3005 cm-1, 1676 cm-1, 1603 cm-1
(b) H NMR: 2.6 ppm (singlet, I = 3H), 3.9 ppm (singlet, I = 3H), 6.9 ppm (doublet, I = 2H), 7.9 ppm (doublet, I = 2H)
(c) 13C NMR: 26.2, 55.4, 113.7, 130.3, 130.5, 163.5, 196.6 ppm ?

Answer:

The concentration of the HNO3 solution is 0.103 M

Explanation:

Step 1: Data given

Volume of the unknow HNO3 sample = 0.125 L

Volume of 0.200 M Ba(OH)2 = 32.3 mL = 0.0323 L

Step 2: The balanced equation

2HNO3(aq) + Ba(OH)2 ( aq ) ⟶ 2H2O ( l ) + Ba( NO3)2 (aq)

Step 3:

n2*C1*V1 = n1*C2*V2

⇒ n2 = the number of moles of Ba(OH)2 = 1

⇒ C1 = the concentration of HNO3 = TO BE DETERMINED

⇒ V1 = the volume of the HNO3 solution = 0.125 L

⇒ n1 = the number of moles of HNO3 = 2

⇒ C2 = the concentration of Ba(OH)2 = 0.200 M

⇒ V2 = the volume of Ba(OH)2 = 0.0323 L

1*C1 * 0.125 L = 2*0.200M * 0.0323 L

C1 = (2*0.200*0.0323)/0.125

C1 = 0.103 M

The concentration of the HNO3 solution is 0.103 M

Answer:

A. 1 J=1kg•m^2/s^2

Explanation:

Energy refers to the capacity to do work. According to the International System of units (SI units), energy is measured in Joules.

Energy is represented by the force applied over a distance. Force is measured in Newton (N) and distance in metres (m). Hence, energy is Newton × metre (N.m)

Newton is derived from the SI units of mass (Kilograms), and acceleration (metres per seconds^2) i.e Kg.m/s^2, since Force = mass × acceleration.

Since; Energy = Newton × metres

If Newton = Kg.m/s^2 and metres = m

Energy (J) will therefore be; Kg.m/s^2 × m

1J = Kg.m^2/s^2

Answer:

15766

Explanation:

The average molecular weight of the polypropylene = 663419 g/mol.

The mass of the repeating unit , monomer which is propylene = 42.08 g/mol

The degree of polymerization is:

Degree of polymerization = 15766

Answer:

c) 0.080 M Al₂(SO₄)₃

Explanation:

Ion [SO₄²⁻] concentration of each solution is:

a) 0.075 M H₂SO₄: [SO₄²⁻] = 0.075M. Because 1 mole of H₂SO₄ contains 1 mole of SO₄²⁻

b) 0.15 M Na₂SO₄: [SO₄²⁻] = 0.15M. Also, 1 mole of Na₂SO₄ contains 1 mole of SO₄²⁻

c) 0.080 M Al₂(SO₄)₃ [SO₄²⁻] = 0.080Mₓ3 = 0.240M. Because 1 mole of Al₂(SO₄)₃ contains 3 moles of SO₄²⁻.

Thus, the soluion that has the greatest [SO₄²⁻] is 0.080 M Al₂(SO₄)₃

Answer:

We are given the formula of the compound:

C12H24O6

The empirical formula of a molecular formula is the lowest whole number ratio between the number of atoms of each element

The ratio of C to H to O in the given formula is :

12 : 24 : 6

we notice that all 3 of the numbers have 6 in common. Dividing all three of the numbers by 6, we get:

2 : 4 : 1

Hence, the ratio of Carbon to Hydrogen to Oxygen in the empirical formula of the given compound is 2 : 4 : 1 ,

Empirical Formula = C2H4O

Answer:

The empirical formula for C12 H24 O6 is C2 H4 O.

The conclusive test for iron(II) ions is the test by the use of potassium hexacyanoferrate III solution.

In qualitative analysis certain reagents are used to test for the presence of certain cations or anions. Those reagents react in a certain way with those reagents. Usually, a positive test may involve a color change, formation of a precipitate or evolution of a gas.

In the case of iron(II) ions, potassium hexacyanoferrate III solution is used in the conclusive qualitative test for the ion. A positive test involves the appearance of a deep blue precipitate.

Learn more: brainly.com/question/6955504

Answer:

please brainlist answer

Explanation:

The addition of K 3 Fe(CN) 6 to a solution causes the formation of a deep blue precipitate which indicates that iron(II) ions are present.