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A beaker is filled to the 500 mL mark with alcohol. What increase in volume (in mL) does the beaker contain when the temperature changes from 5° C to 30° C? (Neglect the expansion of the beaker, evaporation of alcohol and absorption of water vapor by alcohol.) The volume coefficient of expansion γγ for alcohol = 1.12 x 10-4 K-1

Answers

Answer 1

Answer:

Answer:

"1.4 mL" is the appropriate solution.

Explanation:

According to the question,

$v_0=500$
$\alpha =1.12* 10^(-4)$
$\Delta \epsilon = 25$

Now,

Increase in volume will be:

⇒ $\Delta V = \alpha* v_0* \Delta \epsilon$

By putting the given values, we get

$=1.12* 10^(-4)* 500* 25$

$=1.12* 10^(-4)* 12500$

$=1.4 \ mL$

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What would cause the percent yield of a reaction to be less than 100%?All of the limiting reagent gets used up.The product participates in a side reaction.Pure reactants are used.A balanced chemical equation is used.
Does H form cation, anion both or neither ions?

Briefly explain why sublimation occurs.

Answers

Answer:

Sublimation is basically cause by the heat absorption and this process is an endothermic since it require extra energy.

It basically provide sufficient energy to molecules to control the various type of attractive forces from the neighbors and then convert it into the vapor phase.

Sublimation occur when the particle of gases become cold because some substances has high vapor pressure. Sublimation is the endothermic change and it occur below the triple point in terms of pressure and temperature.

In an attempt to prepare n−propylbenzene, a chemist alkylated benzene with 1−chloropropane and aluminum chloride. However, two isomeric hydrocarbons were obtained in a ratio of 2:1, the desired n−propylbenzene being the minor component. What do you think was the major product? How did it arise?

Answers

Answer:

2-Phenylpropane (Cumene)

Explanation:

Famous Friedel Craft Alkylation.

Aluminum Chloride grasped the 1-chloropropane forming an intermediate product composed of Aluminum tetrachloride and n-propylcation. It is well understood that primary carbocations are unstable and therefore undergo hydrogen shifting to attain stability. n-Propylcarbocation undergone hydrogen shifting, forming isopropylcarbocation which reacted with benzene forming 2-Phenylpropane as the major product and HCl as a byproduct.

AlCl3 + CH3CH2CH2Cl --> AlCl4- + CH3CH2CH2+

CH3CH2CH2+ ---> CH3CH(+)CH3

C6H6 + CH3CH(+)CH3 ---> C6H5CH(CH3)2 + H+

AlCl4- + H+ ---> HCl + AlCl3

Answer:

From the given problem statement,he was attempting to prepare n−propylbenzene by alkylation benzene with 1−chloropropane and aluminum chloride,but 1-propyle benze was a major product in result.

Which term describes this molecular shape?A. Trigonal pyramidal
B. Trigonal planar
C. Tetrahedral
D. Linear

Answers

Answer: Trigonal Pyrimidal

Explanation: Just took test

Which of the following reactions would have the smallest value of K at 298 K? Which of the following reactions would have the smallest value of K at 298 K? A + B → 2 C; E°cell = -0.030 V A + 2 B → C; E°cell = +0.98 V A + B → C; E°cell = +1.22 V A + B → 3 C; E°cell = +0.15 V More information is needed to determine.

Answers

The reactions that would have the smallest value of K is

A + B → 2 C; E°cell = -0.030 V

Option A

Generally the equation for the number of electrons transferred is mathematically given as

$nFE^o_(cell)=RT\ln K$

where

T= Temperature

F=25C(298K)

R = Gas constant

R= 8.314 J/K.mol

F = Faraday's constant

F= 96500 C

We see from the equation that the E-cell is directly proportional to K(equilibrium constant of the reaction)

Hence, The reactions that would have the smallest value of K is

A + B → 2 C; E°cell = -0.030 V

For more information on Reaction

brainly.com/question/11231920

Answer:

The reaction with smallest value of K is :

A + B → 2 C; E°cell = -0.030 V

Explanation:

$nFE^o_(cell)=RT\ln K$

where :

n = number of electrons transferred

F = Faraday's constant = 96500 C

$E^o_(cell)$ = standard electrode potential of the cell

R = Gas constant = 8.314 J/K.mol

T = temperature of the reaction = $25^oC=[273+25]=298K$

$K$ = equilibrium constant of the reaction

As we cans see, that standard electrode potential of the cell is directly linked to the equilibrium constant of the reaction.

Higher $E^o_(cell)$ higher will be the value of K.
Lower $E^o_(cell)$ lower will be the value of K.

So, the reaction with smallest value of electrode potential will have smallest value of equilibrium constant. And that reaction is:

A + B → 2 C; $E^o_(cell) =-0.030 V$

You just measured a metal cylinder and obtained the following information: mass - 3.543 g diameter -0.53 cm height = 4.40 cm. 265 • Determine the volume (V). (V=nrºh, where r = radius, h = height, T - 3.14) V= (3.14 36205² 4.402.17cm? • Determine density of the cylinder D. 3. SMS-365923 197

Answers

The density of the cylinder would be 3.652 gram/ cm³

What is density?

It can be defined as the mass of any object or body per unit volume of the particular object or body. Generally, it is expressed as in gram per cm³ or kilogram per meter³.

As given in the problem, you just measured a metal cylinder and obtained the following information: mass - 3.543 grams, diameter 0.53 cm, height = 4.40 cm , and we have to calculate the density of the cylinder,

mass of the cylinder = 3.543 grams

the volume of the cylinder = πr²h

= 3.14 ×.265²×4.4

=0.97 cm³

By using the above formula for density

ρ = mass of the cylinder/volume of the cylinder

= 3.543 grams/0.97 cm³

=3.652 grams/ cm³

Thus,the density of the cylinder would be 3.652 grams/ cm³.

To learn more about density from here, refer to the link;

brainly.com/question/15164682

#SPJ2

Answer:

V cylinder = $\pi r^2 h = \pi(0.53 cm/2)^24.4cm= 0.97 cm^3$

note that $r=diameter/2$

density = $m/V= 3.543/0.97= 3.65 g/cm^3$

1. What is the angular distance north or south from the earth's equator beginning at0° at the equator and ending at 90° at either pole?
a. Weather
b. Altitude
c. Latitude
d. Climate

Answers

Answer:

c. Latitude

Explanation:

The angular distance north or south from the earth's equator beginning at 0° at the equator and ending at 90° of either pole is the latitude.

The equator is a line of latitude that divided the earth into two hemispheres.

Only the equator is a great circle as a line of latitude. Others are small circles.

Weather is the atmospheric condition of a place over a short period of time
Climate is the average weather condition at a place over a long period of time.
Altitude of a place is its elevation above a reference plane.

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