The vapor pressure of liquid octane, C8H18, is 100 mm Hg at 339 K. A sample of C8H18 is placed in a closed, evacuated 537 mL container at a temperature of 339 K. It is found that all of the C8H18 is in the vapor phase and that the pressure is 68.0 mm Hg. If the volume of the container is reduced to 338 mL at constant temperature, which of the following statements are correct?a. No condensation will occur.
b. Some of the vapor initially present will condense.
c. The pressure in the container will be 100. mm Hg.
d. Only octane vapor will be present.
e. Liquid octane will be present.
Answers
Answer:
the final pressure (108.03 mmHg ) inside the container at 339 K is more than the vapor pressure of liquid octane (100 mmHg) at 339 K.
Hence,
b. Some of the vapor initially present will condense.
e. Liquid octane will be present.
Explanation:
Given that;
The vapor pressure of liquid octane, C8H18, is 100 mm Hg at 339 K
Initial volume of the container, V1 = 537 mL
Initial vapor pressure, P1 = 68.0 mmHg
Final volume of the container, V2 = 338 mL
Let us say that the final vapor pressure = P2
From Boyle's law,
P2V2 = P1V1
P2 * 338 = 68.0 * 537
338P2 = 36516
P2 = 36516 / 338
P2 = 108.03 mmHg
Thus, the final pressure (108.03 mmHg ) inside the container at 339 K is more than the vapor pressure of liquid octane (100 mmHg) at 339 K.
Hence,
b. Some of the vapor initially present will condense.
e. Liquid octane will be present.
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Is scandium a transition metal?
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Answer:
a. volcanic changes create new land
Answers
Answers
Answer:
b) Cu2+
Explanation:
- information sheet for solubility constants:
Ksp PbS = 3.4 E-28
Ksp CuS = 6.0 E-37
- PbS ↔ Pb2+ + S2-
∴ Ksp = 3.4 E-28 = [ Pb2+ ] * [ S2- ]
∴ [ Pb2+ ] = 0.10 M
⇒ [ S2- ] = 3.4 E-28 / 0.10 = 3.4 E-27 M
- CuS ↔ Cu2+ + S2-
∴ Ksp = 6.0 E-37 = [ Cu2+ ] * [ S2- ]
∴ [ Cu2+ ] = 0.10 M
⇒ [ S2- ] = 6.0 E-37 / 0.10 = 6.0 E-36 M
we have:
(1) [ S2- ] PbS >> [ S2- ] CuS
(2) Ksp PbS >> Ksp CuS
from (1) and (2) it can determined, that separation can be carried out and also the cation that precipitates first is the Cu2+
moles?
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765.75
................................
3.5 x 10^3. *
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Answer:
Step-by-step explanation:
- 2.3 × 100 = 230
- 3.5 × 1000 = 3500
- 3500 ÷ 230 =
I hope this helps!
Answers
Answer:
1-pentanol
Explanation:
Hexane is non-polar in nature. This is due to :
The bond in the molecule is C-H, which is non-polar in nature because the carbon and the hydrogen having very similar electronegativity values.
Hexane is also symmetric.
The intermolecular force acting in the molecule of the hexane are induced the dipole-dipole forces or London Dispersion forces / van der Waals forces which is a very weak force.
On the other hand, in the case of 1-pentanol, hydrogen bonding exist which is a strong intermolecular force.
Hence, more amount of thermal energy is required to boil 1-pentanol. hence, it has more boiling point.
Final answer:
The boiling point of 1-Pentanol is higher than hexane because it has stronger intermolecular forces caused by hydrogen bonding. Hexane, on the other hand, has weaker van der Waals forces.
Explanation:
The boiling point of a substance is determined by its intermolecular forces. 1-pentanol has a higher boiling point than hexane because of the presence of hydrogen bonding in 1-pentanol, which is a stronger intermolecular force than the van der Waals forces present in hexane. Hence, more energy is required to break the intermolecular forces in 1-pentanol making its boiling point higher.
Learn more about Boiling Points here:
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